Subscribing to topics in Kafka - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to subscribe the consumer to a topic named 'my_topic'.

Kafka

consumer.subscribe([1])

Drag options to blanks, or click blank then click option'

A['my_topic']

B'my_topic'

Cmy_topic

D{'my_topic'}

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a string instead of a list

Using curly braces which create a set instead of a list

The subscribe method expects a list of topic names. So, ['my_topic'] is correct.

2fill in blank

medium

Complete the code to subscribe the consumer to multiple topics: 'topic1' and 'topic2'.

Kafka

consumer.subscribe([1])

Drag options to blanks, or click blank then click option'

A('topic1', 'topic2')

B['topic1', 'topic2']

C{'topic1', 'topic2'}

D'topic1, topic2'

Attempts:

3 left

💡 Hint

Common Mistakes

Using a tuple instead of a list

Passing a string with comma-separated topics

The subscribe method requires a list of topic names. So, ['topic1', 'topic2'] is correct.

3fill in blank

hard

Fix the error in the code to correctly subscribe the consumer to 'events'.

Kafka

consumer.subscribe([1])

Drag options to blanks, or click blank then click option'

A{'events'}

Bevents

C['events']

D'events'

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a string instead of a list

Using a set instead of a list

The subscribe method expects a list of topics, so ['events'] is correct. Passing a string alone causes an error.

4fill in blank

hard

Fill both blanks to subscribe the consumer to topics starting with 'data_' and print the subscription list.

Kafka

topics = ['data_1', 'data_2', 'logs']
filtered = [topic for topic in topics if topic.[1]('data_')]
consumer.subscribe([2])
print(consumer.subscription())

Drag options to blanks, or click blank then click option'

Astartswith

Bfiltered

Cin

Dtopics

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'in' instead of 'startswith'

Subscribing to the original list instead of filtered

Use startswith to filter topics starting with 'data_'. Then subscribe using the filtered list.

5fill in blank

hard

Fill all three blanks to subscribe the consumer to topics with length greater than 5 and print the subscription.

Kafka

topics = ['alpha', 'beta', 'gamma', 'delta123']
long_topics = [topic for topic in topics if len(topic) [1] 5]
consumer.subscribe([2])
print([3].subscription())

Drag options to blanks, or click blank then click option'

A<

B>

Clong_topics

Dconsumer

Attempts:

3 left

💡 Hint

Common Mistakes

Using less than operator

Printing the list instead of consumer subscription

Use > to filter topics longer than 5 characters, subscribe using long_topics, and print the consumer's subscription.

Practice

1. What is the main purpose of the subscribe() method in Kafka consumers?

easy

A. To close the Kafka consumer connection

B. To send messages to Kafka topics

C. To listen to one or more Kafka topics and receive messages automatically

D. To create new Kafka topics

Solution

1. Step 1: Understand the role of subscribe()

   The subscribe() method is used by Kafka consumers to specify which topics they want to listen to.

2. Step 2: Identify what subscribe() enables

   Once subscribed, the consumer automatically receives messages from those topics when calling poll().

3. Final Answer:

   To listen to one or more Kafka topics and receive messages automatically -> Option C

4. Quick Check:

   subscribe() = listen to topics [OK]

Hint: subscribe() means start listening to topics [OK]

Common Mistakes:

• Confusing subscribe() with sending messages
• Thinking subscribe() creates topics
• Assuming subscribe() closes connections

2. Which of the following is the correct way to subscribe a Kafka consumer to multiple topics named "topicA" and "topicB"?

easy

A. consumer.subscribe(["topicA", "topicB"])

B. consumer.subscribe("topicA", "topicB")

C. consumer.subscribe("topicA" + "," + "topicB")

D. consumer.subscribe({"topicA", "topicB"})

Solution

1. Step 1: Recall the subscribe() method signature

   In Kafka, subscribe() takes a list (or collection) of topic names as an argument.

2. Step 2: Identify correct syntax for multiple topics

   Passing a list like ["topicA", "topicB"] is the correct way to subscribe to multiple topics.

3. Final Answer:

   consumer.subscribe(["topicA", "topicB"]) -> Option A

4. Quick Check:

   subscribe() needs a list for multiple topics [OK]

Hint: Use a list to subscribe to multiple topics [OK]

Common Mistakes:

• Passing multiple string arguments instead of a list
• Concatenating topic names into one string
• Using curly braces instead of square brackets

3. Given the following Kafka consumer code snippet, what will be the output if the consumer is subscribed to topic "news" and there are two messages "Hello" and "World" in the topic?

consumer.subscribe(["news"])
records = consumer.poll(timeout_ms=1000)
for record in records:
    print(record.value)

medium

A. ['Hello', 'World']

B. Hello\nWorld

C. HelloWorld

D. No output because poll() is missing a loop

Solution

1. Step 1: Understand subscribe() and poll() behavior

   The consumer subscribes to "news" and calls poll() once, which fetches available messages.

2. Step 2: Analyze the for loop printing each record

   The loop prints each message value on its own line, so "Hello" and "World" appear separately.

3. Final Answer:

   Hello\nWorld -> Option B

4. Quick Check:

   poll() returns messages, loop prints each [OK]

Hint: poll() returns messages; loop prints each on new line [OK]

Common Mistakes:

• Thinking poll() returns a list printed directly
• Assuming messages print concatenated without newline
• Believing poll() needs a loop to work at all

4. What is wrong with the following Kafka consumer code snippet?

consumer.subscribe("topic1")
while True:
    records = consumer.poll(1000)
    for record in records:
        print(record.value)

medium

A. subscribe() expects a list, not a single string

B. poll() must be called outside the loop

C. print() cannot be used inside the loop

D. The loop should be a for loop, not while

Solution

1. Step 1: Check subscribe() argument type

   The subscribe() method requires a list of topics, even if subscribing to one topic.

2. Step 2: Identify the error in argument

   Passing a single string instead of a list causes a type error or unexpected behavior.

3. Final Answer:

   subscribe() expects a list, not a single string -> Option A

4. Quick Check:

   subscribe() needs list argument [OK]

Hint: Always pass a list to subscribe(), even for one topic [OK]

Common Mistakes:

• Passing a string instead of a list to subscribe()
• Thinking poll() can't be inside a loop
• Misunderstanding loop type requirements

5. You want to subscribe a Kafka consumer to all topics starting with "logs-" dynamically, without listing each topic name. Which approach correctly achieves this?

hard

A. Use consumer.assign() with topic partitions matching "logs-"

B. Manually list all topics starting with "logs-" in a list and pass to subscribe()

C. Call subscribe() multiple times, once per topic starting with "logs-"

D. Use consumer.subscribe(Pattern.compile("logs-.*")) to subscribe by regex pattern

Solution

1. Step 1: Understand dynamic topic subscription

   Kafka consumers can subscribe to topics matching a regex pattern using subscribe(Pattern).

2. Step 2: Identify correct method for pattern subscription

   Using consumer.subscribe(Pattern.compile("logs-.*")) subscribes to all topics starting with "logs-" automatically.

3. Final Answer:

   Use consumer.subscribe(Pattern.compile("logs-.*")) to subscribe by regex pattern -> Option D

4. Quick Check:

   subscribe() supports regex patterns [OK]

Hint: Use regex pattern with subscribe() for dynamic topic matching [OK]

Common Mistakes:

• Listing topics manually instead of using regex
• Calling subscribe() multiple times incorrectly
• Using assign() which requires partitions, not topics