Throwing errors in Javascript - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to throw a new error with the message "Oops!".

Javascript

throw new [1]("Oops!");

Drag options to blanks, or click blank then click option'

AError

BException

CMessage

Dthrow

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'throw' as a type instead of a keyword.

Using 'Exception' which is not a built-in JavaScript error type.

Using 'Message' which is not an error type.

In JavaScript, to throw an error you use the Error constructor with the message inside parentheses.

2fill in blank

medium

Complete the code to throw a TypeError with the message "Invalid type".

Javascript

throw new [1]("Invalid type");

Drag options to blanks, or click blank then click option'

AError

BSyntaxError

CTypeError

DReferenceError

Attempts:

3 left

💡 Hint

Common Mistakes

Using SyntaxError which is for syntax issues.

Using ReferenceError which is for undefined variables.

Using generic Error instead of TypeError.

TypeError is a built-in JavaScript error type used to indicate a type mismatch.

3fill in blank

hard

Fix the error in the code to correctly throw a RangeError with message "Out of range".

Javascript

throw [1]("Out of range");

Drag options to blanks, or click blank then click option'

ARangeError

Bnew RangeError

Cnew Error

DError

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting the 'new' keyword causes a TypeError.

Using just the error type without 'new' is incorrect.

Using generic Error instead of RangeError.

To throw an error object, you must use the 'new' keyword before the error type.

4fill in blank

hard

Fill both blanks to throw a SyntaxError with message "Syntax is wrong".

Javascript

throw [1]([2]);

Drag options to blanks, or click blank then click option'

Anew SyntaxError

B"Syntax is wrong"

CSyntaxError

D'Syntax is wrong'

Attempts:

3 left

💡 Hint

Common Mistakes

Not using 'new' before the error type.

Passing the message without quotes.

Using the error type without 'new'.

You must use 'new' to create the error object and pass the message as a string in quotes.

5fill in blank

hard

Fill both blanks to throw a ReferenceError with message "Variable not found".

Javascript

throw [1]([2]);

Drag options to blanks, or click blank then click option'

AReferenceError

B"Variable not found"

Cnew ReferenceError

D'Variable not found'

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting 'new' keyword.

Passing message without quotes.

Using wrong error type.

You create a new ReferenceError object with 'new', pass the message as a string, and the error type is ReferenceError.