Catching runtime errors in Javascript

Introduction

Sometimes programs make mistakes while running. Catching runtime errors helps stop the program from crashing and lets you handle problems smoothly.

When reading a file that might not exist.

When asking a user for input that might be wrong.

When calling a function that might fail.

When working with data from the internet that might be missing or broken.

Syntax

Javascript

try {
  // code that might cause an error
} catch (error) {
  // code to handle the error
}

The try block contains code that might cause an error.

The catch block runs only if there is an error inside try.

Examples

This example tries to divide by zero. JavaScript does not throw an error here, so catch is not triggered.

Javascript

try {
  let result = 10 / 0;
  console.log(result);
} catch (error) {
  console.log('Error caught:', error.message);
}

This example tries to parse invalid JSON, which causes an error caught by catch.

Javascript

try {
  JSON.parse('invalid json');
} catch (error) {
  console.log('Caught error:', error.message);
}

This example calls a function that does not exist, causing an error caught by catch.

Javascript

try {
  nonExistentFunction();
} catch (error) {
  console.log('Oops! Function not found.');
}

Sample Program

This program tries to read user input as JSON. Because the input is broken, it throws an error. The catch block catches it and prints a friendly message.

Javascript

try {
  let userInput = '{"name": "Alice"'; // missing closing brace
  let user = JSON.parse(userInput);
  console.log('User name:', user.name);
} catch (error) {
  console.log('There was a problem parsing user input:', error.message);
}

Important Notes

Always use try...catch around code that might fail to keep your program running smoothly.

You can access the error message with error.message inside the catch block.

Use finally block if you want to run code no matter what, after try and catch.

Summary

Catching runtime errors helps your program handle problems without crashing.

Use try to run risky code and catch to handle errors.

This makes your program more friendly and reliable.

Practice

1.

What is the main purpose of using try and catch in JavaScript?

easy

A. To create new variables

B. To speed up the program execution

C. To handle errors and prevent the program from crashing

D. To repeat code multiple times

Solution

1. Step 1: Understand the role of try block

   The try block runs code that might cause an error.

2. Step 2: Understand the role of catch block

   The catch block handles any error from the try block to keep the program running smoothly.

3. Final Answer:

   To handle errors and prevent the program from crashing -> Option C

4. Quick Check:

   try-catch = error handling [OK]

Hint: Try-catch blocks catch errors to keep programs running [OK]

Common Mistakes:

• Thinking try-catch speeds up code
• Using try-catch to create variables
• Confusing try-catch with loops

2.

Which of the following is the correct syntax to catch errors in JavaScript?

try {
  // code
} catch (error) {
  // handle error
}

easy

A. try { } catch (error) { }

B. try { } catch error() { }

C. try (error) { } catch { }

D. try { } catch error { }

Solution

1. Step 1: Check the try block syntax

   The try block must be followed by catch with parentheses around the error variable.

2. Step 2: Verify the catch block syntax

   The correct syntax is catch (error) { } with parentheses around the error parameter.

3. Final Answer:

   try { } catch (error) { } -> Option A

4. Quick Check:

   catch needs parentheses [OK]

Hint: Catch block always uses parentheses for error [OK]

Common Mistakes:

• Omitting parentheses in catch
• Using parentheses after try
• Adding parentheses after catch keyword

3.

What will be the output of the following code?

try {
  let result = 10 / 0;
  console.log(result);
} catch (e) {
  console.log('Error caught');
}

medium

A. Infinity

B. Error caught

C. 0

D. undefined

Solution

1. Step 1: Understand division by zero in JavaScript

   Dividing 10 by 0 does not cause an error; it results in Infinity.

2. Step 2: Check if catch block runs

   Since no error occurs, the catch block is skipped and Infinity is logged.

3. Final Answer:

   Infinity -> Option A

4. Quick Check:

   10/0 = Infinity, no error [OK]

Hint: Division by zero returns Infinity, no error thrown [OK]

Common Mistakes:

• Assuming division by zero throws error
• Expecting catch block to run
• Confusing 0 with Infinity

4.

Find the error in this code and choose the correct fix:

try {
  console.log(x);
} catch e {
  console.log('Error:', e.message);
}

medium

A. Declare x before try block

B. Change catch e to catch (e)

C. Add finally block after catch

D. Remove the catch block

Solution

1. Step 1: Identify syntax error in catch block

   The catch block must have parentheses around the error variable, so catch e is invalid syntax.

2. Step 2: Correct the catch syntax

   Changing it to catch (e) fixes the syntax and allows error handling.

3. Final Answer:

   Change catch e to catch (e) -> Option B

4. Quick Check:

   Catch needs parentheses around error [OK]

Hint: Catch error variable must be in parentheses [OK]

Common Mistakes:

• Omitting parentheses in catch
• Adding finally when not needed
• Ignoring undeclared variable error

5.

You want to safely parse JSON data that might be invalid. Which code snippet correctly catches parsing errors?

const jsonString = '{"name": "Alice", age: 25}';
try {
  const data = JSON.parse(jsonString);
  console.log(data.name);
} catch (error) {
  console.log('Invalid JSON:', error.message);
}

hard

A. You must use if-else instead of try-catch for JSON parsing

B. This code will crash because JSON.parse never throws errors

C. The catch block should be after console.log(data.name)

D. This code correctly catches JSON parsing errors and logs a message

Solution

1. Step 1: Understand JSON.parse behavior

   JSON.parse throws an error if the JSON string is invalid, like missing quotes around keys.

2. Step 2: Check try-catch usage

   The try block runs JSON.parse, and the catch block handles any parsing error to avoid crashing.

3. Final Answer:

   This code correctly catches JSON parsing errors and logs a message -> Option D

4. Quick Check:

   try-catch handles JSON.parse errors [OK]

Hint: Use try-catch to handle JSON.parse errors safely [OK]

Common Mistakes:

• Assuming JSON.parse never throws errors
• Placing catch block incorrectly
• Using if-else instead of try-catch for errors