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Javascriptprogramming~5 mins

Map method in Javascript - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the map() method do in JavaScript?
The map() method creates a new array by applying a function to each element of the original array.
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beginner
How does map() differ from forEach()?
map() returns a new array with transformed elements, while forEach() just runs a function on each element without returning anything.
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intermediate
What arguments does the callback function inside map() receive?
The callback receives three arguments: the current element, the index of the element, and the original array.
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intermediate
Can map() change the size of the array it returns?
No, map() always returns a new array of the same length as the original array.
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beginner
Give an example of using map() to double numbers in an array.
Example: <br><code>const numbers = [1, 2, 3];<br>const doubled = numbers.map(n => n * 2);<br>console.log(doubled); // [2, 4, 6]</code>
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What does the map() method return?
AA single value
BUndefined
CThe original array
DA new array with transformed elements
Which of these is a valid use of map()?
ATo filter out elements from an array
BTo create a new array by modifying each element
CTo sort an array
DTo remove duplicates
What arguments does the callback function in map() receive?
AElement, index, array
BElement only
CIndex only
DArray only
If you want to change the size of an array, is map() the right method?
ANo, it keeps the same length
BYes, but only to add elements
CYes, it can add or remove elements
DNo, it deletes elements only
What will this code output?
[1, 2, 3].map(x => x + 1)
A[1, 3, 5]
B[1, 2, 3]
C[2, 3, 4]
D[0, 1, 2]
Explain how the map() method works and when you would use it.
Think about turning a list of raw items into a list of changed items.
You got /4 concepts.
    Describe the difference between map() and forEach() in JavaScript.
    One returns a new list, the other just runs code on each item.
    You got /4 concepts.

      Practice

      (1/5)
      1.

      What does the map method do in JavaScript?

      easy
      A. Sorts the elements of the array in place.
      B. Changes the original array by removing elements.
      C. Creates a new array by applying a function to each element of the original array.
      D. Filters elements from the array based on a condition.

      Solution

      1. Step 1: Understand the purpose of map

        The map method applies a function to each element and creates a new array with the results.
      2. Step 2: Compare with other array methods

        Unlike filter or sort, map does not remove or reorder elements but transforms them.
      3. Final Answer:

        Creates a new array by applying a function to each element of the original array. -> Option C
      4. Quick Check:

        map creates new transformed array = A [OK]
      Hint: Map always returns a new array with transformed items [OK]
      Common Mistakes:
      • Thinking map changes the original array
      • Confusing map with filter or sort
      • Believing map removes elements
      2.

      Which of the following is the correct syntax to double each number in the array nums using map?

      const nums = [1, 2, 3];
      easy
      A. const doubled = nums.map(x => x * 2);
      B. const doubled = nums.map(x * 2);
      C. const doubled = nums.map(x => { x * 2 });
      D. const doubled = nums.map(x => return x * 2);

      Solution

      1. Step 1: Check arrow function syntax inside map

        The function must be x => x * 2 to return the doubled value directly.
      2. Step 2: Identify syntax errors in other options

        const doubled = nums.map(x * 2); misses the arrow function syntax. const doubled = nums.map(x => { x * 2 }); uses braces but no return statement, so returns undefined. const doubled = nums.map(x => return x * 2); incorrectly uses return without braces.
      3. Final Answer:

        const doubled = nums.map(x => x * 2); -> Option A
      4. Quick Check:

        Correct arrow function syntax = B [OK]
      Hint: Use arrow function with implicit return inside map [OK]
      Common Mistakes:
      • Missing arrow (=>) in the function
      • Using braces without return statement
      • Incorrect return syntax inside arrow function
      3.

      What is the output of the following code?

      const arr = [1, 2, 3];
      const result = arr.map(x => x + 1);
      console.log(result);
      medium
      A. [1, 2, 3]
      B. [2, 3, 4]
      C. [1, 3, 5]
      D. Error

      Solution

      1. Step 1: Understand the map function applied

        Each element x in arr is increased by 1, so 1 becomes 2, 2 becomes 3, and 3 becomes 4.
      2. Step 2: Check the output array

        The new array is [2, 3, 4], which is logged to the console.
      3. Final Answer:

        [2, 3, 4] -> Option B
      4. Quick Check:

        Each element +1 = [2, 3, 4] [OK]
      Hint: Add 1 to each element inside map to get output [OK]
      Common Mistakes:
      • Thinking original array changes
      • Confusing output with original array
      • Expecting error due to syntax
      4.

      Find the error in this code snippet:

      const numbers = [1, 2, 3];
      const newNumbers = numbers.map(num => { num * 3 });
      console.log(newNumbers);
      medium
      A. The arrow function syntax is incorrect.
      B. The array numbers is not defined.
      C. map method cannot be used on arrays.
      D. Missing return statement inside the arrow function block.

      Solution

      1. Step 1: Analyze arrow function with braces

        When using braces in arrow functions, an explicit return is needed to return a value.
      2. Step 2: Identify missing return

        The function body { num * 3 } does not return anything, so newNumbers will be an array of undefined.
      3. Final Answer:

        Missing return statement inside the arrow function block. -> Option D
      4. Quick Check:

        Arrow function with braces needs return [OK]
      Hint: Add return inside braces or remove braces for implicit return [OK]
      Common Mistakes:
      • Forgetting return inside arrow function with braces
      • Thinking map changes original array
      • Assuming map works only with simple functions
      5.

      You have an array of objects representing people:

      const people = [
        { name: 'Alice', age: 25 },
        { name: 'Bob', age: 30 },
        { name: 'Carol', age: 35 }
      ];
      
      // Use map to create an array of greetings like "Hello, Alice!"

      Which code correctly creates this greetings array?

      hard
      A. const greetings = people.map(person => `Hello, ${person.name}!`);
      B. const greetings = people.map(person => { `Hello, ${person.name}!` });
      C. const greetings = people.map(person => { return `Hello, ${person.age}!` });
      D. const greetings = people.map(person => person.name + 'Hello!');

      Solution

      1. Step 1: Use map to transform each object to a greeting string

        The function should return a string like "Hello, Alice!" using template literals.
      2. Step 2: Check arrow function syntax for returning string

        const greetings = people.map(person => `Hello, ${person.name}!`); uses implicit return with template literal correctly. const greetings = people.map(person => { `Hello, ${person.name}!` }); misses return inside braces. const greetings = people.map(person => { return `Hello, ${person.age}!` }); incorrectly uses age instead of name. const greetings = people.map(person => person.name + 'Hello!'); concatenates incorrectly.
      3. Final Answer:

        const greetings = people.map(person => `Hello, ${person.name}!`); -> Option A
      4. Quick Check:

        Implicit return with template literal = C [OK]
      Hint: Use template literals with implicit return in map [OK]
      Common Mistakes:
      • Missing return inside braces
      • Incorrect string concatenation
      • Confusing implicit and explicit return
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