Function hoisting behavior in Javascript - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to call the function before its declaration.

Javascript

console.log([1]());
function greet() { return 'Hello!'; }

Drag options to blanks, or click blank then click option'

Agreet

BsayHello

Chello

Dgreeting

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name that is not declared as a function.

Trying to call a function expression before its assignment.

The function greet is hoisted, so you can call it before its declaration.

2fill in blank

medium

Complete the code to assign a function expression and call it.

Javascript

const sayHi = [1]() { return 'Hi!'; };
console.log(sayHi());

Drag options to blanks, or click blank then click option'

Afun

Bfunc

Cfunction

Ddef

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect keywords like 'func' or 'def' which are not valid in JavaScript.

Omitting the function keyword entirely.

Function expressions use the keyword function to assign a function to a variable.

3fill in blank

hard

Complete the code to call the function expression correctly.

Javascript

const greet = function() { return 'Hello!'; };
console.log([1]());

Drag options to blanks, or click blank then click option'

AsayHello

Bgreeting

Chello

Dgreet

Attempts:

3 left

💡 Hint

Common Mistakes

Calling the function expression before it is assigned.

Using a different variable name than the one assigned.

Function expressions are not hoisted, so call them after assignment. The variable name is greet.

4fill in blank

hard

Fill both blanks to create a function expression and call it.

Javascript

const add = [1](a, b) [2] a + b;
console.log(add(2, 3));

Drag options to blanks, or click blank then click option'

A() =>

B=>

C{ return

Dfunction

Attempts:

3 left

💡 Hint

Common Mistakes

Using arrow function syntax incorrectly.

Omitting the return statement inside braces.

Use function to define the function expression and { return for the body with explicit return.

5fill in blank

hard

Fill all three blanks to create a function expression and call it.

Javascript

const multiply = [1](x, y) [2] x * y;
console.log([3](4, 5));

Drag options to blanks, or click blank then click option'

Afunction

B{ return

Cmultiply

D() =>

Attempts:

3 left

💡 Hint

Common Mistakes

Using arrow function syntax incorrectly.

Calling the function with a wrong name.

This code defines a function expression named multiply and calls it correctly.

Practice

1. Which statement best describes function hoisting in JavaScript?

easy

A. Function declarations are hoisted and can be called before they are defined.

B. Function expressions are hoisted and can be called before assignment.

C. Variables declared with let are hoisted like functions.

D. Arrow functions are hoisted like function declarations.

Solution

1. Step 1: Understand hoisting for function declarations

   Function declarations are moved to the top of their scope, so they can be called before their definition in code.

2. Step 2: Compare with function expressions and other types

   Function expressions and arrow functions are not hoisted in the same way; they cannot be called before assignment.

3. Final Answer:

   Function declarations are hoisted and can be called before they are defined. -> Option A

4. Quick Check:

   Function declarations hoisted = C [OK]

Hint: Only function declarations are hoisted fully [OK]

Common Mistakes:

• Thinking function expressions are hoisted like declarations
• Confusing variable hoisting with function hoisting
• Assuming arrow functions are hoisted

2. Which of the following is the correct syntax to declare a function that will be hoisted?

easy

A. function myFunc() { return 1; }

B. var myFunc = () => 1;

C. let myFunc = () => 1;

D. const myFunc = function() { return 1; };

Solution

1. Step 1: Identify function declaration syntax

   Function declarations use the function keyword followed by the function name and body.

2. Step 2: Check other options for hoisting behavior

   Options A, B, and C are function expressions or arrow functions assigned to variables, which are not hoisted as functions.

3. Final Answer:

   function myFunc() { return 1; } -> Option A

4. Quick Check:

   Function declaration syntax = D [OK]

Hint: Only function declarations use 'function name()' syntax [OK]

Common Mistakes:

• Confusing function expressions with declarations
• Assuming arrow functions are hoisted
• Using variable assignment syntax for hoisted functions

3. What will be the output of the following code?

console.log(foo());

function foo() {
  return 'Hello';
}

console.log(bar());

var bar = function() {
  return 'World';
};

medium

A. SyntaxError

B. ReferenceError for bar

C. 'Hello' followed by 'World'

D. 'Hello' followed by TypeError

Solution

1. Step 1: Analyze the call to foo()

   The function foo is a declaration and hoisted, so foo() returns 'Hello'.

2. Step 2: Analyze the call to bar()

   bar is a variable assigned a function expression. The variable is hoisted but initialized as undefined at the time of the call, so calling bar() causes a TypeError.

3. Final Answer:

   'Hello' followed by TypeError -> Option D

4. Quick Check:

   Function declaration hoisted, function expression not initialized = A [OK]

Hint: Function declarations hoisted, expressions not initialized [OK]

Common Mistakes:

• Expecting both functions to run without error
• Confusing ReferenceError with TypeError
• Assuming variable functions are hoisted fully

4. Consider the code below. It throws an error. What is the fix?

console.log(add(2, 3));

const add = function(a, b) {
  return a + b;
};

medium

A. Move the console.log after the function expression.

B. Use var add instead of const add.

C. Change const add to function add declaration.

D. Wrap the function expression in parentheses.

Solution

1. Step 1: Identify why error occurs

   The variable add is declared with const and assigned a function expression. It is not hoisted as a function, so calling it before assignment causes a ReferenceError.

2. Step 2: Fix by using function declaration

   Changing to a function declaration function add(a, b) hoists the function, allowing calls before its definition.

3. Final Answer:

   Change const add to function add declaration. -> Option C

4. Quick Check:

   Function declarations hoisted, expressions not [OK]

Hint: Use function declarations to call before definition [OK]

Common Mistakes:

• Assuming var fixes hoisting for function expressions
• Thinking moving console.log is the only fix
• Trying to wrap function expression in parentheses

5. You want to organize your code so that helper functions can be called anywhere in the file without errors. Which approach best uses function hoisting to achieve this?

hard

A. Assign all helper functions to const variables at the top of the file.

B. Use function declarations anywhere; they are hoisted to the top automatically.

C. Declare all helper functions using function declarations at the bottom of the file.

D. Wrap helper functions in arrow functions assigned to let variables.

Solution

1. Step 1: Understand hoisting behavior for function declarations

   Function declarations are hoisted to the top of their scope, so they can be called anywhere in the file regardless of their position.

2. Step 2: Compare with other approaches

   Assigning functions to variables (const or let) does not hoist the function body, so calls before assignment cause errors.

3. Final Answer:

   Use function declarations anywhere; they are hoisted to the top automatically. -> Option B

4. Quick Check:

   Function declarations hoisted anywhere = A [OK]

Hint: Function declarations can be called anywhere due to hoisting [OK]

Common Mistakes:

• Thinking function expressions are hoisted
• Placing function declarations only at bottom
• Using arrow functions expecting hoisting