Nested conditional statements in Javascript - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

Javascript

if (num [1] 0) {
  console.log('Positive number');
}

Drag options to blanks, or click blank then click option'

A<

B>

C===

D!==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check for negative numbers.

Using '===' checks for equality, not greater than.

The condition num > 0 checks if the number is positive.

2fill in blank

medium

Complete the code to check if a number is positive and even.

Javascript

if (num > 0) {
  if (num [1] 2 === 0) {
    console.log('Positive even number');
  }
}

Drag options to blanks, or click blank then click option'

A%

B/

C*

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using division / instead of modulus %.

Using multiplication or subtraction operators incorrectly.

The modulus operator % checks the remainder. If num % 2 === 0, the number is even.

3fill in blank

hard

Fix the error in the nested condition to check if a number is negative and odd.

Javascript

if (num [1] 0) {
  if (num % 2 !== 0) {
    console.log('Negative odd number');
  }
}

Drag options to blanks, or click blank then click option'

A<

B!==

C>

D===

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<' to check for negative numbers.

Using equality operators instead of comparison.

The condition num < 0 checks if the number is negative.

4fill in blank

hard

Fill both blanks to check if a number is zero or positive and even.

Javascript

if (num [1] 0) {
  if (num [2] 2 === 0) {
    console.log('Zero or positive even number');
  }
}

Drag options to blanks, or click blank then click option'

A>=

B<

C%

D===

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>=' for the first condition.

Using division instead of modulus for even check.

The first condition num >= 0 checks for zero or positive numbers. The second condition uses % to check if the number is even.

5fill in blank

hard

Fill all three blanks to check if a number is positive, even, and less than 100.

Javascript

if (num [1] 0) {
  if (num [2] 2 === 0 && num [3] 100) {
    console.log('Positive even number less than 100');
  }
}

Drag options to blanks, or click blank then click option'

A>

B%

C<

D===

Attempts:

3 left

💡 Hint

Common Mistakes

Using division instead of modulus for even check.

Using '>=' instead of '>' for positivity.

Using '>' instead of '<' for less than 100.

The first condition checks if num > 0 (positive). The second uses % to check evenness. The third checks if num < 100.