If–else statement in Javascript - Time & Space Complexity

Time Complexity: If-else statement

O(1)

Understanding Time Complexity

Let's see how the time it takes to run an if-else statement changes as the input changes.

We want to know how many steps the program takes when it checks conditions.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

function checkNumber(num) {
  if (num > 0) {
    return 'Positive';
  } else {
    return 'Non-positive';
  }
}
    

This code checks if a number is positive or not and returns a message.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: A single if-else condition check.
• How many times: Exactly once per function call.

How Execution Grows With Input

Checking one condition takes the same amount of time no matter what the input number is.

Input Size (n)	Approx. Operations
10	1 check
100	1 check
1000	1 check

Pattern observation: The time stays the same even if the input number changes.

Final Time Complexity

Time Complexity: O(1)

This means the program takes the same short time no matter what number you give it.

Common Mistake

[X] Wrong: "If-else takes longer when the number is bigger because it has to check more things."

[OK] Correct: The if-else only checks one condition once, so the size or value of the number does not change how long it takes.

Interview Connect

Understanding that simple condition checks run quickly helps you explain how your code handles decisions efficiently.

Self-Check

"What if we added a loop that runs the if-else check multiple times? How would the time complexity change?"

Practice

1. What does an if-else statement do in JavaScript?

easy

A. It repeats a block of code multiple times.

B. It creates a new variable.

C. It defines a function to be used later.

D. It chooses between two actions based on a condition.

Solution

1. Step 1: Understand the purpose of if-else

   An if-else statement lets the program decide between two paths depending on a condition.

2. Step 2: Match the description to the options

   Only It chooses between two actions based on a condition. describes choosing between two actions based on a condition.

3. Final Answer:

   It chooses between two actions based on a condition. -> Option D

4. Quick Check:

   If-else = choose between two actions [OK]

Hint: If-else picks one of two paths based on true or false [OK]

Common Mistakes:

• Confusing if-else with loops
• Thinking if-else defines functions
• Believing if-else creates variables

2. Which of the following is the correct syntax for an if-else statement in JavaScript?

easy

A. if (condition) { } else { }

B. if condition { } else { }

C. if (condition) then { } else { }

D. if condition then { } else { }

Solution

1. Step 1: Recall JavaScript if-else syntax

   JavaScript requires parentheses around the condition and braces for blocks: if (condition) { } else { }

2. Step 2: Compare options to correct syntax

   Only if (condition) { } else { } uses parentheses and braces correctly without extra keywords.

3. Final Answer:

   if (condition) { } else { } -> Option A

4. Quick Check:

   Correct syntax uses parentheses and braces [OK]

Hint: Remember: condition in ( ), blocks in { } [OK]

Common Mistakes:

• Omitting parentheses around condition
• Adding 'then' keyword (not in JS)
• Missing braces for code blocks

3. What will be the output of this code?

let age = 18;
if (age >= 18) {
  console.log('Adult');
} else {
  console.log('Minor');
}

medium

A. Adult

B. Minor

C. undefined

D. Error

Solution

1. Step 1: Evaluate the condition age >= 18

   Since age is 18, the condition age >= 18 is true.

2. Step 2: Determine which block runs

   The if block runs and prints 'Adult'. The else block is skipped.

3. Final Answer:

   Adult -> Option A

4. Quick Check:

   Condition true -> if block runs -> 'Adult' [OK]

Hint: Check if condition is true or false to pick output [OK]

Common Mistakes:

• Thinking 18 is less than 18
• Confusing else block runs when condition is true
• Expecting syntax error

4. Find the error in this code:

let score = 75;
if score >= 60 {
  console.log('Pass');
} else {
  console.log('Fail');
}

medium

A. Using else without if

B. Missing semicolon after console.log

C. Missing parentheses around the condition

D. Variable score is not declared

Solution

1. Step 1: Check if-else syntax

   JavaScript requires parentheses around the condition in if statements.

2. Step 2: Identify the missing parentheses

   The code has if score >= 60 { ... } but it should be if (score >= 60) { ... }

3. Final Answer:

   Missing parentheses around the condition -> Option C

4. Quick Check:

   if condition must be in ( ) [OK]

Hint: Always put condition inside ( ) after if [OK]

Common Mistakes:

• Forgetting parentheses around condition
• Thinking semicolon is required after console.log block
• Confusing else usage

5. You want to print 'Even' if a number is even, and 'Odd' if it is odd. Which code correctly uses if-else to do this?

let num = 7;
// Choose the correct code snippet

hard

A. if (num % 2 != 0) {
console.log('Even');
} else {
console.log('Odd');
}

B. if (num % 2 === 0) {
console.log('Even');
} else {
console.log('Odd');
}

C. if (num % 2) {
console.log('Even');
} else {
console.log('Odd');
}

D. if (num / 2 === 0) {
console.log('Even');
} else {
console.log('Odd');
}

Solution

1. Step 1: Understand how to check even numbers

   A number is even if remainder when divided by 2 is zero: num % 2 === 0.

2. Step 2: Check each option's condition

   if (num % 2 === 0) { console.log('Even'); } else { console.log('Odd'); } correctly checks num % 2 === 0. Others either use wrong operator or logic.

3. Final Answer:

   if (num % 2 === 0) { console.log('Even'); } else { console.log('Odd'); } -> Option B

4. Quick Check:

   Even check uses num % 2 === 0 [OK]

Hint: Use modulo (%) to test evenness: zero remainder means even [OK]

Common Mistakes:

• Using division (/) instead of modulo (%)
• Checking if remainder is truthy instead of zero
• Reversing even and odd conditions