If statement in Javascript - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the number is positive.

Javascript

if (number [1] 0) {
  console.log('Positive number');
}

Drag options to blanks, or click blank then click option'

A>

B<

C===

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will check for negative numbers instead.

Using '===' checks for equality, not greater than.

The '>' operator checks if the number is greater than zero, meaning it is positive.

2fill in blank

medium

Complete the code to print 'Even' if the number is divisible by 2.

Javascript

if (number [1] 2 === 0) {
  console.log('Even');
}

Drag options to blanks, or click blank then click option'

A%

B+

C-

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' or '-' will not check divisibility.

Using '*' multiplies numbers, not checks remainder.

The '%' operator gives the remainder. If remainder is 0 when divided by 2, number is even.

3fill in blank

hard

Fix the error in the if statement to check if age is at least 18.

Javascript

if (age [1] 18) {
  console.log('Adult');
}

Drag options to blanks, or click blank then click option'

A<

B<=

C>=

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' or '<=' checks for younger than 18.

Using '==' checks only exactly 18, not older.

The '>=' operator checks if age is greater than or equal to 18, meaning adult or older.

4fill in blank

hard

Fill both blanks to print 'Teenager' if age is between 13 and 19 inclusive.

Javascript

if (age [1] 13 && age [2] 19) {
  console.log('Teenager');
}

Drag options to blanks, or click blank then click option'

A>=

B<

C<=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' for the first blank would exclude 13.

Using '>' for the second blank would exclude 19.

Use '>=' to check age is at least 13 and '<=' to check age is at most 19.

5fill in blank

hard

Fill the blanks to print 'Grade A' if score is above 90, 'Grade B' if score is above 80, else 'Grade C'.

Javascript

if (score [1] 90) {
  console.log('Grade A');
} else if (score [2] 80) {
  console.log('Grade B');
} else {
  console.log('Grade C');
}

Drag options to blanks, or click blank then click option'

A>

B>=

C<=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>=' would include boundary scores incorrectly.

Using '<=' in the blanks would cause wrong grade assignments.

Use '>' to check if score is strictly greater than 90 for A and greater than 80 for B.