Break statement in Javascript - Mini Project: Build & Apply

Using the Break Statement in JavaScript Loops

📖 Scenario: You are helping a store manager find the first product that is out of stock from a list of products.

🎯 Goal: Build a program that searches through a list of product stock counts and stops searching as soon as it finds a product with zero stock using the break statement.

📋 What You'll Learn

Create an array called stockCounts with the exact values: [5, 3, 0, 7, 2].

Create a variable called index and set it to 0.

Use a for loop with variable i to go through stockCounts.

Inside the loop, use an if statement to check if stockCounts[i] is 0.

If zero is found, set index to i and use break to stop the loop.

Print the message: "First out of stock product is at index: " followed by the value of index.

💡 Why This Matters

🌍 Real World

Store managers often need to quickly find products that are out of stock to reorder them.

💼 Career

Knowing how to stop loops early with break improves efficiency in many programming tasks like searching and filtering.

1

Create the stock counts array

Create an array called stockCounts with these exact values: [5, 3, 0, 7, 2].

Javascript

# Create the array stockCounts with values [5, 3, 0, 7, 2]
// Your code here

Need a hint?

Use const to create the array named stockCounts.

2

Create the index variable

Create a variable called index and set it to 0.

Javascript

const stockCounts = [5, 3, 0, 7, 2];
// Create a variable index and set it to 0
// Your code here

Need a hint?

Use let to create a variable named index and assign it 0.

3

Use a for loop with break to find zero stock

Use a for loop with variable i to go through stockCounts. Inside the loop, use an if statement to check if stockCounts[i] is 0. If zero is found, set index to i and use break to stop the loop.

Javascript

const stockCounts = [5, 3, 0, 7, 2];
let index = 0;
// Use a for loop with i to check each stock count
// Use if to check if stockCounts[i] is 0
// If yes, set index to i and break
// Your code here

Need a hint?

Use a for loop with i from 0 to stockCounts.length. Inside, check if stockCounts[i] equals 0. If yes, assign i to index and use break.

4

Print the result

Write a console.log statement to print the message: "First out of stock product is at index: " followed by the value of index.

Javascript

const stockCounts = [5, 3, 0, 7, 2];
let index = 0;
for (let i = 0; i < stockCounts.length; i++) {
    if (stockCounts[i] === 0) {
        index = i;
        break;
    }
}
// Print the message with index
// Your code here

Need a hint?

Use console.log to print the message and the index variable.