Method overriding in Java - Mini Project: Build & Apply

Method overriding

📖 Scenario: Imagine you are creating a simple program to show different types of vehicles and how they make sounds. Each vehicle has a basic sound, but some vehicles make special sounds. We will use method overriding to show this difference.

🎯 Goal: You will build a Java program with a base class Vehicle that has a method makeSound(). Then you will create a subclass Car that overrides the makeSound() method to show a different sound. Finally, you will print the sounds from both classes.

📋 What You'll Learn

Create a class called Vehicle with a method makeSound() that prints "Vehicle sound".

Create a subclass called Car that extends Vehicle.

Override the makeSound() method in Car to print "Car sound".

Create objects of both Vehicle and Car and call their makeSound() methods.

Print the output of both method calls.

💡 Why This Matters

🌍 Real World

Method overriding is used when different types of objects share the same method name but need to behave differently, like different vehicles making different sounds.

💼 Career

Understanding method overriding is essential for object-oriented programming, which is widely used in software development jobs to create flexible and reusable code.

1

Create the base class Vehicle

Create a class called Vehicle with a method makeSound() that prints exactly "Vehicle sound".

Java

// Your code here

Hint

Define a class named Vehicle. Inside it, write a method makeSound() that prints "Vehicle sound" using System.out.println.

2

Create the subclass Car

Create a class called Car that extends Vehicle. Do not add any methods yet.

Java

class Vehicle {
    void makeSound() {
        System.out.println("Vehicle sound");
    }
}

// Your code here

Hint

Write a new class named Car that uses extends Vehicle to inherit from the Vehicle class.

3

Override the makeSound() method in Car

Inside the Car class, override the makeSound() method to print exactly "Car sound".

Java

class Vehicle {
    void makeSound() {
        System.out.println("Vehicle sound");
    }
}

class Car extends Vehicle {
    // Your code here
}

Hint

Inside the Car class, write a method makeSound() with the @Override annotation that prints "Car sound".

4

Create objects and print sounds

Create an object called vehicle of class Vehicle and an object called car of class Car. Call makeSound() on both objects and print their outputs.

Java

class Vehicle {
    void makeSound() {
        System.out.println("Vehicle sound");
    }
}

class Car extends Vehicle {
    @Override
    void makeSound() {
        System.out.println("Car sound");
    }
}

// Your code here

Hint

Create objects using new keyword and call makeSound() on each. The output should show "Vehicle sound" first, then "Car sound".

Practice

1.

What is method overriding in Java?

easy

A. When a child class provides a new version of a method from its parent class

B. When a method calls itself repeatedly

C. When two methods have the same name but different parameters

D. When a method is hidden from other classes

Solution

1. Step 1: Understand method overriding concept

   Method overriding means a child class changes the behavior of a method inherited from its parent class.

2. Step 2: Compare options with definition

   When a child class provides a new version of a method from its parent class correctly describes this. When a method calls itself repeatedly is recursion, C is method overloading, D is incorrect.

3. Final Answer:

   When a child class provides a new version of a method from its parent class -> Option A

4. Quick Check:

   Method overriding = child changes parent method [OK]

Hint: Overriding means child changes parent's method behavior [OK]

Common Mistakes:

• Confusing overriding with overloading
• Thinking overriding changes method signature
• Mixing overriding with recursion

2.

Which of the following is the correct syntax to override a method in Java?

class Parent {
    void show() { System.out.println("Parent"); }
}
class Child extends Parent {
    ?
}

easy

A. private void show() { System.out.println("Child"); }

B. @Override void show() { System.out.println("Child"); }

C. void Show() { System.out.println("Child"); }

D. void show(int x) { System.out.println("Child"); }

Solution

1. Step 1: Check method signature and annotation

   To override, method name and parameters must match exactly. Using @Override annotation helps catch mistakes.

2. Step 2: Analyze options

   private void show() { System.out.println("Child"); } uses private access modifier, narrowing from package-private (not allowed for overriding; causes hiding). void show(int x) { System.out.println("Child"); } changes parameters (overloading). void Show() { System.out.println("Child"); } has method name mismatch ('Show' vs 'show' due to case sensitivity). @Override void show() { System.out.println("Child"); } matches method signature exactly and uses @Override correctly.

3. Final Answer:

   @Override void show() { System.out.println("Child"); } -> Option B

4. Quick Check:

   @Override + same signature = correct override [OK]

Hint: Use @Override and same method signature to override [OK]

Common Mistakes:

• Narrowing access modifier (e.g., to private)
• Changing method parameters (overloading instead)
• Method name case mismatch

3.

What will be the output of the following code?

class Parent {
    void greet() { System.out.println("Hello from Parent"); }
}
class Child extends Parent {
    @Override
    void greet() { System.out.println("Hello from Child"); }
}
public class Test {
    public static void main(String[] args) {
        Parent obj = new Child();
        obj.greet();
    }
}

medium

A. Hello from Parent

B. Compilation error

C. Runtime error

D. Hello from Child

Solution

1. Step 1: Understand dynamic method dispatch

   When a parent reference points to a child object, overridden methods in child are called at runtime.

2. Step 2: Trace the method call

   obj is Parent type but refers to Child instance. Calling greet() runs Child's version.

3. Final Answer:

   Hello from Child -> Option D

4. Quick Check:

   Parent ref + Child object calls Child method [OK]

Hint: Parent reference calls child's overridden method at runtime [OK]

Common Mistakes:

• Expecting parent method output
• Confusing compile-time and runtime method binding
• Thinking method overloading applies here

4.

Identify the error in the following code snippet:

class Parent {
    void display() { System.out.println("Parent"); }
}
class Child extends Parent {
    @Override
    void Display() { System.out.println("Child"); }
}

medium

A. Method name case mismatch causes no overriding

B. Missing return type in Child class method

C. Cannot override a method without parameters

D. No error, code is correct

Solution

1. Step 1: Check method names carefully

   Parent method is 'display' (lowercase d), Child method is 'Display' (uppercase D). Java is case-sensitive, so these are different methods.

2. Step 2: Understand @Override annotation effect

   @Override expects exact match. Here, it causes a compile-time error because method names differ in case.

3. Final Answer:

   Method name case mismatch causes no overriding -> Option A

4. Quick Check:

   Method names must match exactly, including case [OK]

Hint: Method names must match case exactly to override [OK]

Common Mistakes:

• Ignoring case sensitivity in method names
• Assuming @Override is optional and ignoring errors
• Confusing overriding with overloading

5.

Consider the following classes:

class Animal {
    String sound() { return "Some sound"; }
}
class Dog extends Animal {
    @Override
    String sound() { return "Bark"; }
}
class Cat extends Animal {
    @Override
    String sound() { return "Meow"; }
}
public class Test {
    public static void main(String[] args) {
        Animal[] animals = {new Dog(), new Cat(), new Animal()};
        for (Animal a : animals) {
            System.out.println(a.sound());
        }
    }
}

What is the output of this program?

hard

A. Bark
Some sound
Meow

B. Some sound
Some sound
Some sound

C. Bark
Meow
Some sound

D. Compilation error due to array of different types

Solution

1. Step 1: Understand polymorphism with overridden methods

   Each object calls its own overridden sound() method at runtime, even if referenced as Animal.

2. Step 2: Trace the loop output

   Dog's sound() returns "Bark", Cat's returns "Meow", Animal's returns "Some sound".

3. Final Answer:

   Bark Meow Some sound -> Option C

4. Quick Check:

   Array of Animals calls each overridden sound() correctly [OK]

Hint: Array of parent type calls each child's overridden method [OK]

Common Mistakes:

• Expecting all calls to use parent method
• Thinking array cannot hold different subclass objects
• Confusing overriding with overloading