Method overriding in Java - Time & Space Complexity
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Let's see how the time it takes to run a program changes when we use method overriding in Java.
We want to know if calling an overridden method takes more time as the program grows.
Analyze the time complexity of the following code snippet.
class Animal {
void sound() {
System.out.println("Animal sound");
}
}
class Dog extends Animal {
@Override
void sound() {
System.out.println("Bark");
}
}
public class Main {
public static void main(String[] args) {
Animal a = new Dog();
a.sound();
}
}
This code shows a class Animal with a method sound, and a Dog class that changes (overrides) this method. We call the sound method on a Dog object through an Animal reference.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Calling the overridden method sound()
- How many times: Called once in this example, but could be called many times in a larger program
Calling an overridden method takes about the same time no matter how many classes or objects you have.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 10 method calls, each takes similar time |
| 100 | 100 method calls, each takes similar time |
| 1000 | 1000 method calls, each takes similar time |
Pattern observation: Each method call takes a fixed amount of time, so total time grows linearly with the number of calls.
Time Complexity: O(n)
This means if you call the overridden method n times, the total time grows in a straight line with n.
[X] Wrong: "Overriding a method makes the program slower because it adds extra steps."
[OK] Correct: The program uses a simple way to find the right method to run, so each call still takes about the same time as a normal method call.
Understanding how method overriding affects time helps you explain how programs stay efficient even when using flexible designs.
"What if we called the overridden method inside a loop that runs n times? How would the time complexity change?"
Practice
What is method overriding in Java?
Solution
Step 1: Understand method overriding concept
Method overriding means a child class changes the behavior of a method inherited from its parent class.Step 2: Compare options with definition
When a child class provides a new version of a method from its parent class correctly describes this. When a method calls itself repeatedly is recursion, C is method overloading, D is incorrect.Final Answer:
When a child class provides a new version of a method from its parent class -> Option AQuick Check:
Method overriding = child changes parent method [OK]
- Confusing overriding with overloading
- Thinking overriding changes method signature
- Mixing overriding with recursion
Which of the following is the correct syntax to override a method in Java?
class Parent {
void show() { System.out.println("Parent"); }
}
class Child extends Parent {
?
}Solution
Step 1: Check method signature and annotation
To override, method name and parameters must match exactly. Using @Override annotation helps catch mistakes.Step 2: Analyze options
private void show() { System.out.println("Child"); } uses private access modifier, narrowing from package-private (not allowed for overriding; causes hiding). void show(int x) { System.out.println("Child"); } changes parameters (overloading). void Show() { System.out.println("Child"); } has method name mismatch ('Show' vs 'show' due to case sensitivity). @Override void show() { System.out.println("Child"); } matches method signature exactly and uses @Override correctly.Final Answer:
@Override void show() { System.out.println("Child"); } -> Option BQuick Check:
@Override + same signature = correct override [OK]
- Narrowing access modifier (e.g., to private)
- Changing method parameters (overloading instead)
- Method name case mismatch
What will be the output of the following code?
class Parent {
void greet() { System.out.println("Hello from Parent"); }
}
class Child extends Parent {
@Override
void greet() { System.out.println("Hello from Child"); }
}
public class Test {
public static void main(String[] args) {
Parent obj = new Child();
obj.greet();
}
}Solution
Step 1: Understand dynamic method dispatch
When a parent reference points to a child object, overridden methods in child are called at runtime.Step 2: Trace the method call
obj is Parent type but refers to Child instance. Calling greet() runs Child's version.Final Answer:
Hello from Child -> Option DQuick Check:
Parent ref + Child object calls Child method [OK]
- Expecting parent method output
- Confusing compile-time and runtime method binding
- Thinking method overloading applies here
Identify the error in the following code snippet:
class Parent {
void display() { System.out.println("Parent"); }
}
class Child extends Parent {
@Override
void Display() { System.out.println("Child"); }
}Solution
Step 1: Check method names carefully
Parent method is 'display' (lowercase d), Child method is 'Display' (uppercase D). Java is case-sensitive, so these are different methods.Step 2: Understand @Override annotation effect
@Override expects exact match. Here, it causes a compile-time error because method names differ in case.Final Answer:
Method name case mismatch causes no overriding -> Option AQuick Check:
Method names must match exactly, including case [OK]
- Ignoring case sensitivity in method names
- Assuming @Override is optional and ignoring errors
- Confusing overriding with overloading
Consider the following classes:
class Animal {
String sound() { return "Some sound"; }
}
class Dog extends Animal {
@Override
String sound() { return "Bark"; }
}
class Cat extends Animal {
@Override
String sound() { return "Meow"; }
}
public class Test {
public static void main(String[] args) {
Animal[] animals = {new Dog(), new Cat(), new Animal()};
for (Animal a : animals) {
System.out.println(a.sound());
}
}
}What is the output of this program?
Solution
Step 1: Understand polymorphism with overridden methods
Each object calls its own overridden sound() method at runtime, even if referenced as Animal.Step 2: Trace the loop output
Dog's sound() returns "Bark", Cat's returns "Meow", Animal's returns "Some sound".Final Answer:
Bark Meow Some sound -> Option CQuick Check:
Array of Animals calls each overridden sound() correctly [OK]
- Expecting all calls to use parent method
- Thinking array cannot hold different subclass objects
- Confusing overriding with overloading
