[Solved] Find the problem in this code:String s1 = null;String s2 = "hello";if (s1.equals(s2)) { System.out.println("Match");} else { System.out.println("No Match");} | Java

Java - Strings and String Handling

Find the problem in this code:

String s1 = null;
String s2 = "hello";
if (s1.equals(s2)) {
    System.out.println("Match");
} else {
    System.out.println("No Match");
}

ANo problem, prints No Match

BCompilation error due to null string

CThrows NullPointerException

DAlways prints Match

Step-by-Step Solution

Solution:

Step 1: Check method call on null reference
Calling equals() on s1 which is null causes NullPointerException at runtime.
Step 2: Understand program behavior
Program crashes before printing anything due to exception.
Final Answer:
Throws NullPointerException -> Option C
Quick Check:
Calling method on null reference causes NullPointerException [OK]

Quick Trick: Never call methods on null strings to avoid exceptions [OK]

Common Mistakes:

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