[Solved] Identify the error in this code snippet: StringBuilder sb = new StringBuilder(); sb.append("Java"); sb.deleteCharAt(4); System.out.println(sb); | Java

Java - Strings and String Handling

Identify the error in this code snippet:

StringBuilder sb = new StringBuilder();
sb.append("Java");
sb.deleteCharAt(4);
System.out.println(sb);

AdeleteCharAt index is out of bounds

Bappend method is incorrect

CStringBuilder cannot be empty

DSystem.out.println cannot print StringBuilder

Step-by-Step Solution

Solution:

Step 1: Check string length after append
After append, sb = "Java" which has length 4 (indices 0-3).
Step 2: deleteCharAt(4) is invalid
Index 4 is out of bounds, causing StringIndexOutOfBoundsException.
Final Answer:
deleteCharAt index is out of bounds -> Option A
Quick Check:
Index bounds error = deleteCharAt index is out of bounds [OK]

Quick Trick: Indexes start at 0; max index = length-1 [OK]

Common Mistakes:

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