Solution:Step 1: Analyze the if-else conditionsIf n > 0 returns "Positive", if n Step 2: Check the else case for n = 0Since 0 is neither greater nor less than 0, else returns "Zero".Final Answer:"Zero" -> Option AQuick Check:0 triggers else return "Zero" [OK]

[Solved] Given this method:public static String checkNumber(int n) { if (n > 0) return "Positive"; else if (n What will checkNumber(0) return? | Java

Java - Methods and Code Reusability

Given this method:

public static String checkNumber(int n) {
  if (n > 0) return "Positive";
  else if (n < 0) return "Negative";
  else return "Zero";
}

What will checkNumber(0) return?

A"Zero"

B"Negative"

C"Positive"

Dnull

Step-by-Step Solution

Solution:

Step 1: Analyze the if-else conditions
If n > 0 returns "Positive", if n < 0 returns "Negative".
Step 2: Check the else case for n = 0
Since 0 is neither greater nor less than 0, else returns "Zero".
Final Answer:
"Zero" -> Option A
Quick Check:
0 triggers else return "Zero" [OK]

Quick Trick: Check all conditions including else for exact return [OK]

Common Mistakes:

Assuming 0 is positive or negative
Missing else return case
Expecting null when no return

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More Java Quizzes

Given this method:

Step 1: Analyze the if-else conditions

Step 2: Check the else case for n = 0

Final Answer:

Quick Check:

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