[Solved] Identify the error in the following code snippet:String s = "456"; int n = Integer.valueOf(s); System.out.println(n); | Java

Java - Wrapper Classes

Identify the error in the following code snippet:

String s = "456";
int n = Integer.valueOf(s);
System.out.println(n);

AMissing semicolon after Integer.valueOf(s)

BString s cannot be converted to Integer

CCannot assign Integer object to int directly

DNo error, code runs fine

Step-by-Step Solution

Solution:

Step 1: Check return type of Integer.valueOf
valueOf returns an Integer object.
Step 2: Auto-unboxing allows assignment
Java (5+) automatically unboxes Integer to int, so the code compiles and runs, printing 456.
Final Answer:
No error, code runs fine -> Option D
Quick Check:
valueOf(String) auto-unboxes to int [OK]

Quick Trick: valueOf(String) auto-unboxes to int [OK]

Common Mistakes:

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