Array length property in Java - Interactive Code Practice

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Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the length of the array.

Java

int[] numbers = {1, 2, 3, 4, 5};
System.out.println(numbers[1]);

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A.length()

B.count

C.size

D.length

Attempts:

3 left

2fill in blank

medium

Complete the code to loop through the array using its length property.

Java

int[] values = {10, 20, 30};
for (int i = 0; i < values[1]; i++) {
    System.out.println(values[i]);
}

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A.count

B.size()

C.length

D.length()

Attempts:

3 left

3fill in blank

hard

Fix the error in accessing the array length property.

Java

String[] names = {"Anna", "Bob", "Cara"};
int size = names[1];
System.out.println(size);

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A.length()

B.length

C.size

D.count

Attempts:

3 left

4fill in blank

hard

Fill both blanks to create a map of array elements to their lengths.

Java

Map<String, Integer> map = new HashMap<>();
String[] words = {"cat", "dog", "bird"};
for (String word : words) {
    map.put(word, word[1]);
}
System.out.println(map.size() == words[2]);

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A.length()

B.length

C.size()

D.count

Attempts:

3 left

5fill in blank

hard

Fill all three blanks to create a dictionary of word lengths for words longer than 3 characters.

Java

Map<String, Integer> wordLengths = new HashMap<>();
String[] words = {"apple", "bat", "carrot", "dog"};
for (String [1] : words) {
    if ([1].[2]() > 3) {
        wordLengths.put([3], [3].length());
    }
}
System.out.println(wordLengths);

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Aword

Blength

Clength()

Dwords

Attempts:

3 left