Code generation from schema in GraphQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a GraphQL type for a User with an ID field.

GraphQL

type User { id: [1] }

Drag options to blanks, or click blank then click option'

AInt

BString

CID!

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using String instead of ID for unique identifiers.

Forgetting the exclamation mark to make the field required.

The ID! type is used for unique identifiers and the exclamation mark means it is required.

2fill in blank

medium

Complete the code to add a name field of type String to the User type.

GraphQL

type User { id: ID! name: [1] }

Drag options to blanks, or click blank then click option'

AString!

BInt

CBoolean

DFloat

Attempts:

3 left

💡 Hint

Common Mistakes

Using Int or Boolean instead of String for text.

Omitting the exclamation mark if the field is required.

The String! type means the name is a required string field.

3fill in blank

hard

Fix the error in the schema by completing the field type for posts as a list of Post types.

GraphQL

type User { posts: [[1]!]! }

Drag options to blanks, or click blank then click option'

ABoolean

BString

CID

DPost

Attempts:

3 left

💡 Hint

Common Mistakes

Using scalar types like String or ID instead of the Post type.

Forgetting to add exclamation marks for non-nullability.

The posts field is a non-nullable list of non-nullable Post objects.

4fill in blank

hard

Fill both blanks to define a Query type with a user field that takes an ID argument and returns a User.

GraphQL

type Query { user(id: [1]!): [2] }

Drag options to blanks, or click blank then click option'

AID

BString

CUser

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using String instead of ID for the argument.

Returning a scalar type instead of the User type.

The user query takes a non-nullable ID argument and returns a User type.

5fill in blank

hard

Fill all three blanks to define a Mutation type with a createUser field that takes a name argument and returns a User.

GraphQL

type Mutation { createUser(name: [1]!): [2] } input CreateUserInput { name: [3]! }

Drag options to blanks, or click blank then click option'

AString

BUser

DID

Attempts:

3 left

💡 Hint

Common Mistakes

Using ID instead of String for the name argument.

Returning a scalar type instead of User.

Mismatching input field types.

The createUser mutation takes a non-nullable String name argument and returns a User. The input type CreateUserInput also defines a required String name field.