Schema-first development in GraphQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a GraphQL type for a User with an ID field.

GraphQL

type User { id: [1] }

Drag options to blanks, or click blank then click option'

AID!

BString

CInt

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using String instead of ID for unique identifiers.

Forgetting the exclamation mark to mark the field as required.

The ID! type is used for unique identifiers and the exclamation mark means it is required.

2fill in blank

medium

Complete the code to add a required name field of type String to the User type.

GraphQL

type User { name: [1] }

Drag options to blanks, or click blank then click option'

AInt

BString!

CBoolean

DID

Attempts:

3 left

💡 Hint

Common Mistakes

Using ID instead of String for name.

Omitting the exclamation mark, making the field optional.

The String! type means the name field is a required string.

3fill in blank

hard

Fix the error in the schema by completing the field type for posts as a list of Post types.

GraphQL

type User { posts: [[1]] }

Drag options to blanks, or click blank then click option'

AInt

BString

CPost

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using scalar types like String instead of the Post type.

Forgetting to use square brackets for lists.

The posts field should be a list of Post objects, so the type is [Post].

4fill in blank

hard

Fill both blanks to define a Query type with a user field that takes an ID argument and returns a User.

GraphQL

type Query { user(id: [1]): [2] }

Drag options to blanks, or click blank then click option'

AID!

BUser

CString

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using String instead of ID for the argument type.

Returning a scalar type instead of the User object.

The user field takes a required ID argument (ID!) and returns a User type.

5fill in blank

hard

Fill both blanks to define a Mutation type with a createUser field that takes a name argument and returns a User.

GraphQL

type Mutation { createUser(name: [1]): [2] }

Drag options to blanks, or click blank then click option'

AString!

BUser

CID!

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using optional argument types without exclamation marks.

Returning scalar types instead of the User object.

The createUser mutation takes a required name argument (String!) and returns a User. The ID! option is a distractor here and not used in the blanks.