Defer execution order in Go - Mini Project: Build & Apply

Defer Execution Order in Go

📖 Scenario: Imagine you are writing a Go program that needs to clean up resources in a specific order after some operations. You want to learn how defer statements work and how their execution order is managed.

🎯 Goal: Build a Go program that uses multiple defer statements and prints messages to show the order in which deferred functions execute.

📋 What You'll Learn

Create a main function

Use multiple defer statements with print messages

Understand and demonstrate the LIFO (last-in, first-out) order of defer execution

Print the messages to show the order clearly

💡 Why This Matters

🌍 Real World

In real programs, defer is used to ensure resources like files or network connections are properly closed even if errors occur.

💼 Career

Understanding defer is important for writing clean, safe Go code especially in backend development, system programming, and cloud services.

1

Create the main function and initial print

Write a main function in Go that prints "Start of main".

Go

package main

func main() {
    // Your code here
}

Hint

Use func main() to define the main function and println to print the message.

2

Add two defer statements with print messages

Inside the main function, add two defer statements that print "First defer" and "Second defer" respectively.

Go

package main

func main() {
    println("Start of main")
    // Your code here
}

Hint

Use defer println("message") to add deferred print statements.

3

Add a final print statement after defer statements

After the two defer statements, add a print statement that prints "End of main" inside the main function.

Go

package main

func main() {
    println("Start of main")
    defer println("First defer")
    defer println("Second defer")
    // Your code here
}

Hint

Just add println("End of main") after the defer statements.

4

Run the program and observe the output

Run the program and print the output to see the order of execution of the print statements and deferred functions.

Go

package main

func main() {
    println("Start of main")
    defer println("First defer")
    defer println("Second defer")
    println("End of main")
}

// Run the program to see the output

Hint

Run the program using go run and observe that deferred functions run in reverse order.

Practice

1. What happens when multiple defer statements are used in a Go function?

easy

A. Deferred calls execute in last-in, first-out order when the function returns.

B. Deferred calls execute immediately when encountered.

C. Deferred calls execute in the order they appear in the code.

D. Deferred calls never execute automatically.

Solution

1. Step 1: Understand defer behavior

   In Go, deferred functions are postponed until the surrounding function returns.

2. Step 2: Execution order of deferred calls

   Deferred calls run in reverse order of their appearance, like a stack (last-in, first-out).

3. Final Answer:

   Deferred calls execute in last-in, first-out order when the function returns. -> Option A

4. Quick Check:

   Defer order = last-in, first-out [OK]

Hint: Remember: defer calls run backwards at function end [OK]

Common Mistakes:

• Thinking defer calls run immediately
• Assuming defer calls run in code order
• Believing defer calls never run

2. Which of the following is the correct syntax to defer a function call in Go?

easy

A. defer() fmt.Println("Hello")

B. defer := fmt.Println("Hello")

C. defer fmt.Println("Hello")

D. defer call fmt.Println("Hello")

Solution

1. Step 1: Recall defer syntax

   The keyword defer is followed directly by the function call without assignment or parentheses around defer.

2. Step 2: Identify correct syntax

   defer fmt.Println("Hello") correctly uses defer fmt.Println("Hello"). Other options misuse defer syntax.

3. Final Answer:

   defer fmt.Println("Hello") -> Option C

4. Quick Check:

   defer + function call = correct syntax [OK]

Hint: Use 'defer' directly before function call without extra symbols [OK]

Common Mistakes:

• Adding := after defer
• Using parentheses after defer keyword
• Writing extra words like 'call' after defer

3. What is the output of this Go program?

package main
import "fmt"
func main() {
    defer fmt.Println("First")
    defer fmt.Println("Second")
    fmt.Println("Third")
}

medium

A. Third
First
Second

B. Third
Second
First

C. First
Second
Third

D. Second
First
Third

Solution

1. Step 1: Identify immediate and deferred prints

   "Third" is printed immediately. The two deferred prints run after main ends.

2. Step 2: Determine deferred call order

   Deferred calls run last-in, first-out, so "Second" prints before "First".

3. Final Answer:

   Third Second First -> Option B

4. Quick Check:

   Immediate then deferred reverse order = Third, Second, First [OK]

Hint: Immediate prints first; deferred prints run backward after [OK]

Common Mistakes:

• Assuming deferred prints run in code order
• Thinking deferred prints run before immediate prints
• Confusing the order of deferred calls

4. Consider this Go code snippet:

func example() {
    defer fmt.Println("A")
    defer fmt.Println("B")
    defer fmt.Println("C")
    fmt.Println("D")
}

If the output is not as expected, what is the likely mistake?

medium

A. The function does not call fmt.Println("D") before defers.

B. The deferred calls are not in reverse order.

C. The deferred calls are missing parentheses.

D. The deferred calls execute immediately, not at function end.

Solution

1. Step 1: Understand expected output order

   "D" should print first immediately, then deferred calls print "C", "B", "A" in reverse order.

2. Step 2: Identify cause of unexpected output

   If "D" is missing or not printed before defers, output order changes unexpectedly.

3. Final Answer:

   The function does not call fmt.Println("D") before defers. -> Option A

4. Quick Check:

   Immediate prints must run before deferred calls [OK]

Hint: Ensure immediate prints run before deferred calls [OK]

Common Mistakes:

• Expecting deferred calls to run in code order
• Forgetting to call immediate print before defers
• Misunderstanding when deferred calls execute

5. You want to open three files in a Go function and ensure all are closed properly using defer. Which code snippet correctly closes the files in the right order?

hard

A. file1.Close()
file2.Close()
file3.Close()

B. defer file3.Close()
defer file2.Close()
defer file1.Close()

C. defer Close(file1)
defer Close(file2)
defer Close(file3)

D. defer file1.Close()
defer file2.Close()
defer file3.Close()

Solution

1. Step 1: Understand defer closing order

   Deferred calls run last-in, first-out, so the last deferred closes first.

2. Step 2: Apply to file closing

   Deferring file1.Close() first, then file2.Close(), then file3.Close() means file3 closes first, then file2, then file1, matching open order reversed.

3. Final Answer:

   defer file1.Close() defer file2.Close() defer file3.Close() -> Option D

4. Quick Check:

   Defer in open order closes files in reverse [OK]

Hint: Defer closes in reverse order of defer statements [OK]

Common Mistakes:

• Deferring closes in reverse order of opening
• Calling Close() immediately without defer
• Using incorrect function calls for closing