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Goprogramming~5 mins

Channel closing behavior in Go - Time & Space Complexity

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Time Complexity: Channel closing behavior
O(n)
Understanding Time Complexity

When working with channels in Go, it's important to understand how closing a channel affects the program's speed.

We want to see how the time to close and read from a channel changes as the number of messages grows.

Scenario Under Consideration

Analyze the time complexity of the following code snippet.


ch := make(chan int, n)
for i := 0; i < n; i++ {
    ch <- i
}
close(ch)
for v := range ch {
    _ = v
}
    

This code fills a channel with n integers, closes it, then reads all values until the channel is empty.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Sending and receiving values in a loop over n items.
  • How many times: Each loop runs n times, once for each item.
How Execution Grows With Input

As the number of items n increases, the total operations increase proportionally.

Input Size (n)Approx. Operations
10About 20 (10 sends + 10 receives)
100About 200 (100 sends + 100 receives)
1000About 2000 (1000 sends + 1000 receives)

Pattern observation: The work grows linearly with the number of items sent and received.

Final Time Complexity

Time Complexity: O(n)

This means the time to send, close, and receive all items grows directly with the number of items.

Common Mistake

[X] Wrong: "Closing a channel instantly empties it, so reading after close is free."

[OK] Correct: Even after closing, you must receive each item one by one, so reading still takes time proportional to the number of items.

Interview Connect

Understanding how channel operations scale helps you write efficient concurrent programs and explain your reasoning clearly in interviews.

Self-Check

"What if we replaced the buffered channel with an unbuffered channel? How would the time complexity change?"

Practice

(1/5)
1. What happens when you close a channel in Go?
easy
A. The channel is deleted from memory immediately
B. Senders can still send values without error
C. Receivers know no more values will be sent
D. The channel blocks all operations permanently

Solution

  1. Step 1: Understand channel closing purpose

    Closing a channel signals receivers that no more values will be sent.
  2. Step 2: Effects on senders and receivers

    Senders cannot send after closing; receivers get zero value and ok=false.
  3. Final Answer:

    Receivers know no more values will be sent -> Option C
  4. Quick Check:

    close(channel) signals receivers [OK]
Hint: Closing signals receivers no more data comes [OK]
Common Mistakes:
  • Thinking senders can send after close
  • Believing channel is deleted immediately
  • Assuming channel blocks forever after close
2. Which of the following is the correct way to close a channel named ch in Go?
easy
A. ch.Close()
B. ch.close()
C. close channel ch
D. close(ch)

Solution

  1. Step 1: Recall Go syntax for closing channels

    The built-in function close() is used with the channel as argument.
  2. Step 2: Identify correct syntax

    Only close(ch) is valid; methods like ch.close() or ch.Close() do not exist.
  3. Final Answer:

    close(ch) -> Option D
  4. Quick Check:

    Use close(channel) syntax [OK]
Hint: Use built-in close(channel) function [OK]
Common Mistakes:
  • Trying to call close as a method
  • Using incorrect keywords like 'close channel'
  • Capitalizing close as Close
3. What is the output of this Go program?
package main
import "fmt"
func main() {
  ch := make(chan int, 2)
  ch <- 10
  ch <- 20
  close(ch)
  for v := range ch {
    fmt.Print(v, " ")
  }
}
medium
A. 10 20
B. 10 20 0
C. Runtime panic: send on closed channel
D. No output

Solution

  1. Step 1: Understand channel buffering and closing

    Channel has buffer size 2, two values sent, then channel closed.
  2. Step 2: Loop over channel with range

    Range reads all values until channel is closed and drained, printing 10 and 20.
  3. Final Answer:

    10 20 -> Option A
  4. Quick Check:

    Range over closed channel prints buffered values [OK]
Hint: Range prints all buffered values before stopping [OK]
Common Mistakes:
  • Expecting panic on reading closed channel
  • Thinking zero value prints after buffered values
  • Assuming no output because channel is closed
4. Identify the error in this Go code snippet:
ch := make(chan int)
go func() {
  for i := 0; i < 3; i++ {
    ch <- i
  }
  close(ch)
}()
for {
  v, ok := <-ch
  if !ok {
    break
  }
  fmt.Println(v)
}
medium
A. Channel is unbuffered but sender is in goroutine, no deadlock
B. No error, code runs and prints 0 1 2
C. Closing channel inside goroutine causes panic
D. Receiver loop never ends, causing infinite loop

Solution

  1. Step 1: Analyze channel usage and goroutine

    Unbuffered channel with sender in goroutine sends 3 values then closes channel.
  2. Step 2: Check receiver loop behavior

    Receiver reads values until channel closes, then breaks loop correctly.
  3. Final Answer:

    No error, code runs and prints 0 1 2 -> Option B
  4. Quick Check:

    Proper close and ok check ends loop [OK]
Hint: Use ok to detect closed channel and break loop [OK]
Common Mistakes:
  • Thinking closing in goroutine causes panic
  • Assuming infinite loop without break
  • Ignoring need to check ok when receiving
5. Consider this Go program:
package main
import "fmt"
func main() {
  ch := make(chan int)
  go func() {
    for i := 1; i <= 3; i++ {
      ch <- i
    }
    close(ch)
  }()
  for {
    v, ok := <-ch
    if !ok {
      break
    }
    if v%2 == 0 {
      fmt.Println(v)
    }
  }
}
What is the output and why?
hard
A. 2 Only even numbers printed before channel closes
B. 1 2 3 All numbers printed despite channel closing
C. No output because channel is closed before reading
D. Runtime panic due to sending on closed channel

Solution

  1. Step 1: Understand sending and closing in goroutine

    Values 1, 2, 3 sent then channel closed properly.
  2. Step 2: Receiver loop filters even numbers

    Loop reads until closed; prints only values where v%2 == 0, which is 2.
  3. Final Answer:

    2 Only even numbers printed before channel closes -> Option A
  4. Quick Check:

    Filter with condition inside loop after close [OK]
Hint: Filter values after reading until channel closes [OK]
Common Mistakes:
  • Expecting all values printed
  • Thinking channel closes before sending
  • Assuming panic on close with goroutine sender
Recommended

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