Parent-child document retrieval in Prompt Engineering / GenAI - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to retrieve child documents linked to a parent document.

Prompt Engineering / GenAI

child_docs = client.search(index='children', query={'parent_id': [1])

Drag options to blanks, or click blank then click option'

A'12345'

B'parent_id'

C'children'

D'parent_doc'

Attempts:

3 left

💡 Hint

Common Mistakes

Using the field name 'parent_id' instead of the actual ID value.

Using the index name instead of the ID.

The parent document ID '12345' is needed to find its child documents.

2fill in blank

medium

Complete the code to filter parent documents that have children with a specific attribute.

Prompt Engineering / GenAI

parents = client.search(index='parents', query={'has_child': {'type': 'child', 'query': {'term': {'[1]': 'active'}}}})

Drag options to blanks, or click blank then click option'

Astatus

Bparent_id

Cchild_id

Dtype

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'parent_id' which is not a child attribute.

Using 'type' which is a fixed value.

We filter children by their 'status' field to find parents with active children.

3fill in blank

hard

Fix the error in the code to correctly retrieve parents with children matching a condition.

Prompt Engineering / GenAI

results = client.search(index='parents', query={'has_child': {'type': 'child', 'query': {'match': {'[1]': 'urgent'}}}})

Drag options to blanks, or click blank then click option'

Achild_id

Bpriority

Cparent_id

Dstatus

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'parent_id' which is not a child field.

Using 'status' which may not indicate urgency.

The 'priority' field in children is matched to find urgent child documents.

4fill in blank

hard

Fill both blanks to build a dictionary comprehension that maps parent IDs to counts of their children with score above 80.

Prompt Engineering / GenAI

parent_child_counts = {parent['id']: sum(1 for child in parent['children'] if child['score'][1] 80) for parent in parents if 'children' [2] parent}

Drag options to blanks, or click blank then click option'

A>

Bin

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' for score comparison.

Using '==' instead of 'in' to check key existence.

We count children with score > 80 and check if 'children' key exists in parent.

5fill in blank

hard

Fill all three blanks to create a filtered list of child documents with type 'comment' and length of text over 50.

Prompt Engineering / GenAI

filtered_children = [child for child in children if child['type'] == '[1]' and len(child['[2]']) [3] 50]

Drag options to blanks, or click blank then click option'

Acomment

Btext

C>

Dcontent

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'content' instead of 'text' for the field name.

Using '<' instead of '>' for length comparison.

We filter children of type 'comment' whose 'text' length is greater than 50 characters.