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Vector database operations (CRUD) in Prompt Engineering / GenAI - Cheat Sheet & Quick Revision

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beginner
What does CRUD stand for in vector database operations?
CRUD stands for Create, Read, Update, and Delete. These are the four basic operations to manage data in a vector database.
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beginner
How is the 'Create' operation performed in a vector database?
Create means adding new vectors (data points) into the database. Each vector represents information like text or images in numeric form.
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beginner
What is the purpose of the 'Read' operation in vector databases?
Read means searching or retrieving vectors from the database. This often involves finding vectors similar to a query vector using similarity search.
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intermediate
Why is the 'Update' operation important in vector databases?
Update changes existing vectors to keep data accurate or add new information. For example, updating a vector after improving its representation.
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beginner
What happens during the 'Delete' operation in a vector database?
Delete removes vectors from the database when they are no longer needed, helping keep the database clean and efficient.
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Which operation adds new vectors to a vector database?
ARead
BDelete
CUpdate
DCreate
What does the 'Read' operation usually involve in vector databases?
AFinding similar vectors
BRemoving vectors
CChanging vector values
DAdding new vectors
Why might you perform an 'Update' on a vector in the database?
ATo delete old data
BTo add new vectors
CTo improve or correct the vector data
DTo search for vectors
Which CRUD operation helps keep the vector database clean by removing unwanted data?
ACreate
BDelete
CRead
DUpdate
In vector databases, what form do data points take?
AVectors of numbers
BImages only
CText strings
DAudio files
Explain the four CRUD operations in vector databases with simple examples.
Think about adding, finding, changing, and removing data.
You got /4 concepts.
    Describe why similarity search is important in the 'Read' operation of vector databases.
    Imagine finding friends who are most like you.
    You got /3 concepts.

      Practice

      (1/5)
      1. What does the CRUD acronym stand for in vector database operations?
      easy
      A. Connect, Run, Undo, Deploy
      B. Compute, Retrieve, Upload, Download
      C. Create, Read, Update, Delete
      D. Cache, Refresh, Use, Drop

      Solution

      1. Step 1: Understand CRUD basics

        CRUD is a common term in databases meaning the four basic operations you can do with data.
      2. Step 2: Match each letter to its meaning

        C stands for Create (add new data), R for Read (get data), U for Update (change data), and D for Delete (remove data).
      3. Final Answer:

        Create, Read, Update, Delete -> Option C
      4. Quick Check:

        CRUD = Create, Read, Update, Delete [OK]
      Hint: Remember CRUD as basic data actions: add, get, change, remove [OK]
      Common Mistakes:
      • Confusing CRUD with unrelated terms
      • Mixing up the order of operations
      • Thinking CRUD only applies to files, not vectors
      2. Which of the following is the correct syntax to add a vector with ID 'vec1' and values [0.1, 0.2, 0.3] to a vector database named db?
      easy
      A. db.push_vector(['vec1', 0.1, 0.2, 0.3])
      B. db.insert('vec1', [0.1, 0.2, 0.3])
      C. db.create_vector('vec1', 0.1, 0.2, 0.3)
      D. db.add_vector('vec1', [0.1, 0.2, 0.3])

      Solution

      1. Step 1: Identify the common method for adding vectors

        Most vector databases use a method like add_vector with an ID and a list of numbers.
      2. Step 2: Check method parameters

        The method should take the vector ID as a string and the vector values as a list or array.
      3. Final Answer:

        db.add_vector('vec1', [0.1, 0.2, 0.3]) -> Option D
      4. Quick Check:

        Add vector syntax = db.add_vector(id, vector) [OK]
      Hint: Add vectors with add_vector(id, vector_list) method [OK]
      Common Mistakes:
      • Using wrong method names like insert or push_vector
      • Passing vector values as separate arguments instead of a list
      • Mixing ID and vector in one list
      3. Given the following code snippet, what will be the output?
      db = VectorDB()
      db.add_vector('v1', [1, 0, 0])
      db.add_vector('v2', [0, 1, 0])
      results = db.search([0.9, 0.1, 0], top_k=1)
      print(results)
      medium
      A. [('v1', 0.9)]
      B. [('v2', 0.9)]
      C. [('v1', 0.1)]
      D. [('v2', 0.1)]

      Solution

      1. Step 1: Understand the vectors and query

        Vectors 'v1' = [1,0,0], 'v2' = [0,1,0], query = [0.9,0.1,0].
      2. Step 2: Calculate similarity or distance

        Assuming cosine similarity, 'v1' is closer to query (dot product ~0.9), 'v2' is less similar (~0.1).
      3. Final Answer:

        [('v1', 0.9)] -> Option A
      4. Quick Check:

        Closest vector = v1 with similarity 0.9 [OK]
      Hint: Closest vector has highest dot product with query [OK]
      Common Mistakes:
      • Confusing similarity with distance
      • Mixing up vector IDs in output
      • Assuming lower score means closer
      4. The following code tries to update a vector but throws an error. What is the likely cause?
      db = VectorDB()
      db.add_vector('v1', [0.5, 0.5, 0.5])
      db.update_vector('v2', [0.1, 0.1, 0.1])
      medium
      A. Vector 'v2' does not exist, so update fails
      B. The update_vector method requires 4 arguments
      C. Vector values must be integers, not floats
      D. The add_vector method was not called before update_vector

      Solution

      1. Step 1: Check vector existence before update

        Updating a vector requires it to exist in the database first.
      2. Step 2: Identify the error cause

        Since 'v2' was never added, trying to update it causes an error.
      3. Final Answer:

        Vector 'v2' does not exist, so update fails -> Option A
      4. Quick Check:

        Update needs existing vector [OK]
      Hint: Update only existing vectors, else error occurs [OK]
      Common Mistakes:
      • Assuming update creates new vectors
      • Thinking data type mismatch causes error
      • Ignoring vector existence check
      5. You want to delete vectors with similarity less than 0.5 to a query vector [0, 1, 0] from your vector database. Which sequence of operations correctly achieves this?
      hard
      A. Delete all vectors, then add only those with similarity >= 0.5
      B. Search vectors with similarity < 0.5, then delete each by ID
      C. Update vectors with similarity < 0.5 to zero vectors
      D. Add new vectors with similarity >= 0.5, ignoring deletion

      Solution

      1. Step 1: Find vectors below similarity threshold

        Use a search or filter operation to get IDs of vectors with similarity less than 0.5.
      2. Step 2: Delete vectors by their IDs

        Use the delete operation on each vector ID found to remove them from the database.
      3. Final Answer:

        Search vectors with similarity < 0.5, then delete each by ID -> Option B
      4. Quick Check:

        Filter then delete unwanted vectors [OK]
      Hint: Filter vectors first, then delete by ID [OK]
      Common Mistakes:
      • Deleting all vectors instead of selective ones
      • Trying to update instead of delete
      • Ignoring the similarity filter step