What if you could find any word instantly without flipping through pages?
Why Trie Search Operation in DSA Typescript?
Imagine you have a huge phone book with thousands of names. You want to find if a name exists, but you have to flip through every page one by one.
Searching manually is slow and tiring. You might miss names or take too long to find what you want. It's easy to get lost or confused flipping pages.
A Trie organizes words like a tree, where each letter leads you closer to the full word. This way, you quickly jump to the right place without checking every name.
function searchWord(words: string[], target: string): boolean {
for (let word of words) {
if (word === target) return true;
}
return false;
}class TrieNode { children: Map<string, TrieNode> = new Map(); isEndOfWord: boolean = false; } class Trie { root = new TrieNode(); search(word: string): boolean { let current = this.root; for (let char of word) { if (!current.children.has(char)) return false; current = current.children.get(char)!; } return current.isEndOfWord; } }
It lets you find words instantly, even in huge lists, by following letter paths instead of checking every word.
When you type in a search box, the system suggests words quickly because it uses a Trie to find matches as you type.
Manual search checks every word, which is slow.
Trie search follows letters step-by-step, making it fast.
Tries help autocomplete and spell-check features work smoothly.
Practice
search operation in a Trie data structure do?Solution
Step 1: Understand the purpose of search in Trie
The search operation is designed to check if a specific word is present in the Trie data structure.Step 2: Differentiate from other operations
Insertion adds words, deletion removes words, and counting totals words, but search only checks existence.Final Answer:
Checks if a given word exists in the Trie -> Option AQuick Check:
Search = Check existence [OK]
- Confusing search with insert operation
- Thinking search deletes words
- Assuming search counts words
Solution
Step 1: Identify input and output types for search
The search method takes a word as a string and returns true or false, so input is string and output is boolean.Step 2: Match method signature with correct types
Onlysearch(word: string): booleanmatches the expected input and output types.Final Answer:
search(word: string): boolean -> Option DQuick Check:
Input string, output boolean [OK]
- Using wrong input type like number or boolean
- Returning void instead of boolean
- Confusing return type with string
const trie = new Trie();
trie.insert('cat');
trie.insert('car');
trie.insert('dog');
console.log(trie.search('car'));
console.log(trie.search('cap'));Solution
Step 1: Check inserted words in Trie
The words 'cat', 'car', and 'dog' are inserted into the Trie.Step 2: Search for 'car' and 'cap'
'car' exists in the Trie, so search returns true. 'cap' was not inserted, so search returns false.Final Answer:
true\nfalse -> Option BQuick Check:
Inserted words found, missing words not found [OK]
- Assuming 'cap' is found because it starts like 'car'
- Mixing true/false order in output
- Forgetting to insert words before search
search(word: string): boolean {
let node = this.root;
for (let i = 0; i <= word.length; i++) {
const char = word[i];
if (!node.children.has(char)) return false;
node = node.children.get(char)!;
}
return node.isEndOfWord;
}Solution
Step 1: Analyze loop boundary in search method
The loop runs from i = 0 to i <= word.length, which means it accesses word[word.length], an undefined index.Step 2: Correct loop condition to avoid out-of-bounds
The loop should run while i < word.length to access valid characters only.Final Answer:
Loop condition should bei < word.length, not <= -> Option AQuick Check:
Loop boundary off by one [OK]
- Using <= causes undefined access
- Ignoring empty string edge case
- Misusing non-null assertion without checks
Solution
Step 1: Understand prefix search goal
Prefix search should confirm if any word starts with the given prefix, not necessarily a complete word.Step 2: Adjust search logic for prefix
Return true once all prefix characters are found in sequence, without requiring isEndOfWord to be true.Final Answer:
Return true as soon as all prefix characters are found, without checking isEndOfWord -> Option CQuick Check:
Prefix found means true, no full word check needed [OK]
- Checking isEndOfWord for prefix search
- Rejecting short prefixes arbitrarily
- Requiring prefix to match exactly one word
Ready to prove it?
Pass the test and this pattern moves unknown
