Trie Search Operation in DSA Typescript - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the current character exists in the children of the node.

DSA Typescript

if (!node.children.has([1])) {
    return false;
}

Drag options to blanks, or click blank then click option'

Aindex

Bchar

Cword

Dnode

Attempts:

3 left

💡 Hint

Common Mistakes

Using the whole word instead of a single character.

Using the node variable instead of the character.

We check if the current character 'char' exists in the children map of the node.

2fill in blank

medium

Complete the code to move to the next node in the trie for the current character.

DSA Typescript

node = node.children.get([1])!;

Drag options to blanks, or click blank then click option'

Achar

Bindex

Cword

Dnode

Attempts:

3 left

💡 Hint

Common Mistakes

Using the whole word or index instead of the character.

Trying to get children with the node variable.

We get the child node corresponding to the current character 'char' to continue traversal.

3fill in blank

hard

Fix the error in the return statement to check if the node marks the end of a word.

DSA Typescript

return node.[1];

Drag options to blanks, or click blank then click option'

AisWord

Bend

CisEndOfWord

DwordEnd

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect property names like 'isWord' or 'end'.

Returning the node itself instead of a boolean.

The property 'isEndOfWord' indicates if the node marks the end of a valid word in the trie.

4fill in blank

hard

Fill both blanks to iterate over each character in the word and check the trie.

DSA Typescript

for (let [1] = 0; [2] < word.length; [2]++) {
    const char = word[[1]];
    // rest of the code
}

Drag options to blanks, or click blank then click option'

Ai

Bj

Cindex

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names in initialization and condition.

Using variables not declared in the loop.

The loop variable 'i' is used consistently to index characters in the word.

5fill in blank

hard

Fill all three blanks to complete the search function that returns true if the word exists in the trie.

DSA Typescript

function search(word: string): boolean {
    let node = this.root;
    for (let i = 0; i < word.length; i++) {
        const char = word[[1]];
        if (!node.children.has([2])) {
            return false;
        }
        node = node.children.get([3])!;
    }
    return node.isEndOfWord;
}

Drag options to blanks, or click blank then click option'

Ai

Bchar

Cword

Dnode

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'word' instead of 'char' to check children.

Using 'i' instead of 'char' to get children.

We use 'i' to get the character from 'word', then check and get the child node using 'char'.

Practice

1. What does the search operation in a Trie data structure do?

easy

A. Checks if a given word exists in the Trie

B. Deletes a word from the Trie

C. Inserts a new word into the Trie

D. Counts the total words stored in the Trie

Solution

1. Step 1: Understand the purpose of search in Trie

   The search operation is designed to check if a specific word is present in the Trie data structure.

2. Step 2: Differentiate from other operations

   Insertion adds words, deletion removes words, and counting totals words, but search only checks existence.

3. Final Answer:

   Checks if a given word exists in the Trie -> Option A

4. Quick Check:

   Search = Check existence [OK]

Hint: Search checks presence of word, not insertion or deletion [OK]

Common Mistakes:

• Confusing search with insert operation
• Thinking search deletes words
• Assuming search counts words

2. Which of the following is the correct TypeScript method signature for a Trie search function that returns a boolean?

easy

A. search(word: boolean): boolean

B. search(word: number): string

C. search(word: string): void

D. search(word: string): boolean

Solution

1. Step 1: Identify input and output types for search

   The search method takes a word as a string and returns true or false, so input is string and output is boolean.

2. Step 2: Match method signature with correct types

   Only search(word: string): boolean matches the expected input and output types.

3. Final Answer:

   search(word: string): boolean -> Option D

4. Quick Check:

   Input string, output boolean [OK]

Hint: Search takes string, returns true/false [OK]

Common Mistakes:

• Using wrong input type like number or boolean
• Returning void instead of boolean
• Confusing return type with string

3. Given the following TypeScript Trie search code, what will be the output?

const trie = new Trie();
trie.insert('cat');
trie.insert('car');
trie.insert('dog');
console.log(trie.search('car'));
console.log(trie.search('cap'));

medium

A. true\ntrue

B. true\nfalse

C. false\ntrue

D. false\nfalse

Solution

1. Step 1: Check inserted words in Trie

   The words 'cat', 'car', and 'dog' are inserted into the Trie.

2. Step 2: Search for 'car' and 'cap'

   'car' exists in the Trie, so search returns true. 'cap' was not inserted, so search returns false.

3. Final Answer:

   true\nfalse -> Option B

4. Quick Check:

   Inserted words found, missing words not found [OK]

Hint: Inserted words return true, others false [OK]

Common Mistakes:

• Assuming 'cap' is found because it starts like 'car'
• Mixing true/false order in output
• Forgetting to insert words before search

4. Identify the bug in this TypeScript Trie search method:

search(word: string): boolean {
  let node = this.root;
  for (let i = 0; i <= word.length; i++) {
    const char = word[i];
    if (!node.children.has(char)) return false;
    node = node.children.get(char)!;
  }
  return node.isEndOfWord;
}

medium

A. Loop condition should be i < word.length, not <=

B. Missing check for empty string input

C. Should return true before loop ends

D. Incorrect use of non-null assertion operator (!)

Solution

1. Step 1: Analyze loop boundary in search method

   The loop runs from i = 0 to i <= word.length, which means it accesses word[word.length], an undefined index.

2. Step 2: Correct loop condition to avoid out-of-bounds

   The loop should run while i < word.length to access valid characters only.

3. Final Answer:

   Loop condition should be i < word.length, not <= -> Option A

4. Quick Check:

   Loop boundary off by one [OK]

Hint: Loop over characters with i < length, not <= length [OK]

Common Mistakes:

• Using <= causes undefined access
• Ignoring empty string edge case
• Misusing non-null assertion without checks

5. You want to modify a Trie search method to support prefix search (check if any word starts with given prefix). Which change is correct?

hard

A. Return true only if prefix is a complete word (isEndOfWord true)

B. Return false if prefix length is less than 3 characters

C. Return true as soon as all prefix characters are found, without checking isEndOfWord

D. Return true only if prefix matches exactly one word

Solution

1. Step 1: Understand prefix search goal

   Prefix search should confirm if any word starts with the given prefix, not necessarily a complete word.

2. Step 2: Adjust search logic for prefix

   Return true once all prefix characters are found in sequence, without requiring isEndOfWord to be true.

3. Final Answer:

   Return true as soon as all prefix characters are found, without checking isEndOfWord -> Option C

4. Quick Check:

   Prefix found means true, no full word check needed [OK]

Hint: Prefix search stops after matching prefix, ignores full word flag [OK]

Common Mistakes:

• Checking isEndOfWord for prefix search
• Rejecting short prefixes arbitrarily
• Requiring prefix to match exactly one word