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DSA Typescriptprogramming~20 mins

Why Stack Exists and What Problems It Solves in DSA Typescript - Challenge Your Understanding

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Challenge - 5 Problems
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🧠 Conceptual
intermediate
2:00remaining
Why do we use a stack data structure?
Which of the following best explains why a stack is useful in programming?
AIt organizes data randomly to speed up searching.
BIt stores data in a first-in, first-out order, like a queue at a ticket counter.
CIt helps manage data in a last-in, first-out order, useful for undo features and function calls.
DIt stores data permanently on disk for long-term storage.
Attempts:
2 left
💡 Hint
Think about how undo buttons or browser back buttons work.
❓ Predict Output
intermediate
2:00remaining
Stack Operations Output
What is the printed output after running this TypeScript stack code?
DSA Typescript
class Stack {
  private items: number[] = [];
  push(item: number) { this.items.push(item); }
  pop(): number | undefined { return this.items.pop(); }
  print() { console.log(this.items.join(' -> ') + ' -> null'); }
}

const stack = new Stack();
stack.push(10);
stack.push(20);
stack.pop();
stack.push(30);
stack.print();
A10 -> 20 -> 30 -> null
B20 -> 30 -> null
C30 -> null
D10 -> 30 -> null
Attempts:
2 left
💡 Hint
Remember pop removes the last pushed item.
🔧 Debug
advanced
2:00remaining
Identify the error in stack implementation
What error will this TypeScript stack code cause when running?
DSA Typescript
class Stack {
  private items: number[] = [];
  push(item: number) { this.items.push(item); }
  pop(): number { return this.items.pop()!; }
}

const stack = new Stack();
stack.pop();
ANo error, returns undefined safely
BTypeError because pop returns undefined but method expects number
CSyntaxError due to missing return type
DRuntime error because push is not defined
Attempts:
2 left
💡 Hint
Check the pop method return type and what happens when popping empty stack.
🚀 Application
advanced
2:00remaining
Using stack to check balanced parentheses
What will be the output of this function when called with input '(())()'?
DSA Typescript
function isBalanced(s: string): boolean {
  const stack: string[] = [];
  for (const char of s) {
    if (char === '(') stack.push(char);
    else if (char === ')') {
      if (stack.length === 0) return false;
      stack.pop();
    }
  }
  return stack.length === 0;
}

console.log(isBalanced('(())()'));
Atrue
Bfalse
CSyntaxError
Dundefined
Attempts:
2 left
💡 Hint
Think about matching opening and closing parentheses using a stack.
🧠 Conceptual
expert
2:00remaining
Why is stack preferred for function call management?
Why do programming languages use a stack to manage function calls?
ABecause functions are called and return in a last-in, first-out order, matching stack behavior.
BBecause stacks allow random access to any function call in memory.
CBecause stacks automatically parallelize function calls for speed.
DBecause stacks store function calls permanently for debugging.
Attempts:
2 left
💡 Hint
Think about how functions call other functions and then return back.

Practice

(1/5)
1. Why do we use a stack data structure in programming?
easy
A. To sort numbers in ascending order automatically
B. To store data in random order for quick access
C. To keep track of function calls and return in the correct order
D. To store large amounts of data permanently

Solution

  1. Step 1: Understand the purpose of a stack

    A stack stores items in Last In First Out (LIFO) order, which is perfect for tracking function calls.
  2. Step 2: Relate stack to function calls

    When a function calls another, the current function is paused and saved on the stack. When the called function finishes, the program returns to the last saved function.
  3. Final Answer:

    To keep track of function calls and return in the correct order -> Option C
  4. Quick Check:

    Stack = function call tracking [OK]
Hint: Stack follows LIFO, perfect for tracking nested calls [OK]
Common Mistakes:
  • Thinking stack stores data randomly
  • Confusing stack with queue
  • Assuming stack sorts data automatically
2. Which of the following is the correct way to push an element '5' onto a stack named myStack in TypeScript?
easy
A. myStack.push(5);
B. myStack.add(5);
C. myStack.insert(5);
D. myStack.enqueue(5);

Solution

  1. Step 1: Recall stack method names in TypeScript

    Stacks use push() to add elements on top.
  2. Step 2: Identify correct method for adding element

    push() is the standard method; others like add(), insert(), or enqueue() are not used for stacks.
  3. Final Answer:

    myStack.push(5); -> Option A
  4. Quick Check:

    Push adds element on top [OK]
Hint: Use push() to add on stack top [OK]
Common Mistakes:
  • Using enqueue which is for queues
  • Using add or insert which are not stack methods
  • Confusing push with pop
3. What will be the output of the following TypeScript code?
const stack: number[] = [];
stack.push(10);
stack.push(20);
const popped = stack.pop();
stack.push(30);
console.log(stack);
medium
A. [30]
B. [10, 20, 30]
C. [20, 30]
D. [10, 30]

Solution

  1. Step 1: Trace stack operations step-by-step

    Initially stack is empty []. Push 10 -> [10]. Push 20 -> [10, 20]. Pop removes 20 -> [10]. Push 30 -> [10, 30].
  2. Step 2: Determine final stack content

    After all operations, stack contains [10, 30].
  3. Final Answer:

    [10, 30] -> Option D
  4. Quick Check:

    Push/pop changes stack top [OK]
Hint: Pop removes last pushed element [OK]
Common Mistakes:
  • Forgetting pop removes top element
  • Assuming pop returns stack without removing
  • Mixing order of push and pop
4. Find the error in this TypeScript stack usage code:
const stack: number[] = [];
stack.push(1);
stack.push(2);
const top = stack.peek();
console.log(top);
medium
A. Stack does not have a peek() method by default
B. push() method is used incorrectly
C. stack should be declared as Stack<number> not number[]
D. console.log cannot print stack elements

Solution

  1. Step 1: Check methods available on array used as stack

    TypeScript arrays have push() and pop(), but no peek() method by default.
  2. Step 2: Identify cause of error

    Calling stack.peek() will cause a runtime error because peek() is not defined.
  3. Final Answer:

    Stack does not have a peek() method by default -> Option A
  4. Quick Check:

    peek() missing in array stack [OK]
Hint: Array stack has pop(), no peek() [OK]
Common Mistakes:
  • Assuming peek() exists on arrays
  • Thinking push() is wrong
  • Confusing type declaration with method error
5. You want to reverse a string using a stack in TypeScript. Which approach correctly uses a stack to reverse the string "hello"?
hard
A. Push characters and pop in same order to keep string unchanged
B. Push each character onto stack, then pop all to build reversed string
C. Use stack to sort characters alphabetically
D. Push entire string onto stack, then pop once to get reversed string

Solution

  1. Step 1: Understand stack reversal logic

    Pushing characters one by one stores them in order. Popping them reverses the order because stack is LIFO.
  2. Step 2: Apply to string reversal

    Push 'h', 'e', 'l', 'l', 'o' then pop all to get 'o', 'l', 'l', 'e', 'h' which is reversed string.
  3. Final Answer:

    Push each character onto stack, then pop all to build reversed string -> Option B
  4. Quick Check:

    Stack LIFO reverses order [OK]
Hint: Push chars, pop all to reverse string [OK]
Common Mistakes:
  • Pushing entire string at once
  • Popping in same order as push
  • Using stack for sorting instead of reversing
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