Bird
Raised Fist0
DSA Typescriptprogramming~10 mins

Why Queue Exists and What Problems It Solves in DSA Typescript - Test Your Knowledge

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add an element to the end of the queue.

DSA Typescript
queue.[1](5);
Drag options to blanks, or click blank then click option'
Aenqueue
Bpush
Cpop
Ddequeue
Attempts:
3 left
💡 Hint
Common Mistakes
Using pop or dequeue to add elements
Using push which is for stacks, not queues
2fill in blank
medium

Complete the code to remove the first element from the queue.

DSA Typescript
const first = queue.[1]();
Drag options to blanks, or click blank then click option'
Apush
Bpeek
Cdequeue
Denqueue
Attempts:
3 left
💡 Hint
Common Mistakes
Using enqueue or push to remove elements
Using peek which only views the first element
3fill in blank
hard

Fix the error in the code to check if the queue is empty.

DSA Typescript
if (queue.[1] === 0) { console.log('Empty'); }
Drag options to blanks, or click blank then click option'
Asize
Blength
Ccount
Dempty
Attempts:
3 left
💡 Hint
Common Mistakes
Using size or count which are not valid properties
Using empty which is a method, not a property
4fill in blank
hard

Fill both blanks to create a queue and add an element to it.

DSA Typescript
const queue = new Array[1]();
queue.[2](10);
Drag options to blanks, or click blank then click option'
A<number>
Benqueue
Cpush
D<string>
Attempts:
3 left
💡 Hint
Common Mistakes
Using when numbers are added
Using enqueue which is not an array method
5fill in blank
hard

Fill all three blanks to create a queue, add two elements, and remove one.

DSA Typescript
const queue = new Array[1]();
queue.[2](1);
queue.[3](2);
const first = queue.shift();
Drag options to blanks, or click blank then click option'
A<number>
Bpush
D<string>
Attempts:
3 left
💡 Hint
Common Mistakes
Using instead of
Using enqueue which is not an array method

Practice

(1/5)
1. Why do we use a Queue data structure instead of just using an array for all cases?
easy
A. Because queues use less memory than arrays.
B. Because arrays cannot store multiple values.
C. Because a queue follows a specific order (FIFO) which is useful for tasks like scheduling.
D. Because arrays do not allow adding elements.

Solution

  1. Step 1: Understand the order of elements in a queue

    A queue follows First-In-First-Out (FIFO) order, meaning the first element added is the first to be removed.
  2. Step 2: Compare with arrays and their use cases

    Arrays can store multiple values but do not enforce FIFO order automatically. Queues are designed for tasks like scheduling where order matters.
  3. Final Answer:

    Because a queue follows a specific order (FIFO) which is useful for tasks like scheduling. -> Option C
  4. Quick Check:

    Queue = FIFO order [OK]
Hint: Queues keep order FIFO, arrays don't enforce order [OK]
Common Mistakes:
  • Thinking arrays can't store multiple values
  • Confusing memory usage between queues and arrays
  • Believing arrays don't allow adding elements
2. Which of the following is the correct way to add an element to the end of a queue in TypeScript?
easy
A. queue.push(element);
B. queue.pop(element);
C. queue.shift(element);
D. queue.unshift(element);

Solution

  1. Step 1: Identify the method to add elements at the end of an array

    In TypeScript, push() adds an element to the end of an array, which simulates enqueue in a queue.
  2. Step 2: Understand other methods

    pop() removes from the end, shift() removes from the start, and unshift() adds to the start, so they don't add to the end.
  3. Final Answer:

    queue.push(element); -> Option A
  4. Quick Check:

    push() adds to end [OK]
Hint: Use push() to add at queue's end [OK]
Common Mistakes:
  • Using pop() which removes instead of adds
  • Using shift() or unshift() incorrectly
  • Confusing push() with unshift()
3. What will be the output of the following TypeScript code simulating a queue?
const queue: number[] = [];
queue.push(10);
queue.push(20);
const first = queue.shift();
queue.push(30);
console.log(queue);
medium
A. [20, 30]
B. [10, 20, 30]
C. [30, 20]
D. [10, 30]

Solution

  1. Step 1: Trace the queue operations step-by-step

    Initially empty queue: [] - push(10) -> [10] - push(20) -> [10, 20] - shift() removes first element 10 -> queue becomes [20] - push(30) -> [20, 30]
  2. Step 2: Check the final console.log output

    The queue now contains [20, 30], so console.log prints this array.
  3. Final Answer:

    [20, 30] -> Option A
  4. Quick Check:

    After shift(), queue = [20], then push(30) = [20, 30] [OK]
Hint: Remember shift() removes front, push() adds end [OK]
Common Mistakes:
  • Thinking shift() removes from end
  • Confusing push() and unshift() effects
  • Expecting original array unchanged after shift()
4. The following TypeScript code is intended to simulate a queue but has a bug. What is the bug?
const queue: number[] = [];
queue.push(1);
queue.push(2);
const removed = queue.pop();
console.log(queue);
medium
A. console.log cannot print arrays.
B. push() cannot add elements to an array.
C. queue is not initialized correctly.
D. Using pop() removes from the end, not the front of the queue.

Solution

  1. Step 1: Understand queue removal operation

    In a queue, elements are removed from the front (FIFO). Using pop() removes from the end (LIFO), which is incorrect for a queue.
  2. Step 2: Identify the correct method to remove from front

    The correct method to remove from the front is shift(), not pop().
  3. Final Answer:

    Using pop() removes from the end, not the front of the queue. -> Option D
  4. Quick Check:

    pop() removes end, queue needs front removal [OK]
Hint: Use shift() to remove front, not pop() [OK]
Common Mistakes:
  • Thinking pop() removes from front
  • Believing push() can't add elements
  • Assuming console.log can't print arrays
5. You want to process tasks in the order they arrive and also be able to add urgent tasks that should run before others. Which data structure best solves this problem and why?
hard
A. Queue, because it processes tasks in arrival order only.
B. Priority Queue, because it processes tasks based on priority and arrival order.
C. Array, because it allows random access to tasks.
D. Stack, because it processes the most recent task first.

Solution

  1. Step 1: Understand the problem requirements

    Tasks must be processed in arrival order, but urgent tasks should run before others, meaning priority matters.
  2. Step 2: Match data structure to requirements

    A normal queue processes strictly FIFO, ignoring priority. A stack processes last-in-first-out, which is not suitable. A priority queue processes tasks based on priority and can maintain arrival order among same priority tasks.
  3. Final Answer:

    Priority Queue, because it processes tasks based on priority and arrival order. -> Option B
  4. Quick Check:

    Priority Queue = priority + order [OK]
Hint: Use priority queue for priority + order tasks [OK]
Common Mistakes:
  • Choosing queue ignoring priority needs
  • Confusing stack order with queue order
  • Thinking array handles priority automatically
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard