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DSA Typescriptprogramming~10 mins

Why Doubly Linked List Over Singly Linked List in DSA Typescript - Test Your Knowledge

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a node with a pointer to the next node only.

DSA Typescript
class Node {
  value: number;
  next: Node | null;
  constructor(value: number) {
    this.value = value;
    this.next = [1];
  }
}
Drag options to blanks, or click blank then click option'
Anull
Bundefined
C0
Dthis
Attempts:
3 left
💡 Hint
Common Mistakes
Setting next to undefined or 0 instead of null.
Assigning next to this, which causes a circular reference.
2fill in blank
medium

Complete the code to add a previous pointer in a doubly linked list node.

DSA Typescript
class DoublyNode {
  value: number;
  next: DoublyNode | null;
  prev: DoublyNode | null;
  constructor(value: number) {
    this.value = value;
    this.next = null;
    this.prev = [1];
  }
}
Drag options to blanks, or click blank then click option'
A0
Bundefined
Cthis
Dnull
Attempts:
3 left
💡 Hint
Common Mistakes
Setting prev to undefined or 0 instead of null.
Assigning prev to this, causing self-reference.
3fill in blank
hard

Fix the error in the method that moves backward in a doubly linked list.

DSA Typescript
moveBackward(node: DoublyNode | null): number[] {
  const values: number[] = [];
  while (node !== null) {
    values.push(node.value);
    node = node.[1];
  }
  return values;
}
Drag options to blanks, or click blank then click option'
Anext
Bprevious
Cprev
Dback
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'next' instead of 'prev' to move backward.
Using incorrect property names like 'previous' or 'back'.
4fill in blank
hard

Fill both blanks to insert a new node after a given node in a doubly linked list.

DSA Typescript
insertAfter(node: DoublyNode, newNode: DoublyNode): void {
  newNode.prev = node;
  newNode.next = node.[1];
  if (node.[2] !== null) {
    node.[2].prev = newNode;
  }
  node.next = newNode;
}
Drag options to blanks, or click blank then click option'
Anext
Bprev
Cprevious
Dback
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'prev' instead of 'next' for the newNode's next pointer.
Not updating the next node's prev pointer.
5fill in blank
hard

Fill all three blanks to remove a node from a doubly linked list.

DSA Typescript
remove(node: DoublyNode): void {
  if (node.[1] !== null) {
    node.[1].prev = node.[2];
  }
  if (node.[3] !== null) {
    node.[3].next = node.[2];
  }
}
Drag options to blanks, or click blank then click option'
Anext
Bprev
Cprevious
Dback
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up next and prev pointers.
Not checking for null before updating pointers.

Practice

(1/5)
1. Why might you choose a doubly linked list over a singly linked list in a program?
easy
A. Because it uses less memory per node
B. Because it allows traversal in both directions easily
C. Because it is simpler to implement
D. Because it only stores one pointer per node

Solution

  1. Step 1: Understand traversal capabilities

    A singly linked list allows moving forward only, while a doubly linked list allows moving forward and backward.
  2. Step 2: Compare memory and complexity

    Doubly linked lists use more memory and are more complex but provide two-way traversal.
  3. Final Answer:

    Because it allows traversal in both directions easily -> Option B
  4. Quick Check:

    Two-way traversal = A [OK]
Hint: Doubly means two directions, singly means one [OK]
Common Mistakes:
  • Thinking doubly linked lists use less memory
  • Confusing simplicity with singly linked lists
  • Assuming singly linked lists allow backward traversal
2. Which of the following is the correct way to declare a node in a doubly linked list in TypeScript?
easy
A. class Node { value: number; next: Node; }
B. class Node { value: number; prev: Node; }
C. class Node { value: number; next: Node | null; prev: Node | null; }
D. class Node { value: number; next: Node | null; }

Solution

  1. Step 1: Identify required pointers for doubly linked list node

    A doubly linked list node must have both next and prev pointers, which can be null if no neighbor exists.
  2. Step 2: Check TypeScript syntax for nullable pointers

    Using Node | null correctly allows for the end nodes to have null pointers.
  3. Final Answer:

    class Node { value: number; next: Node | null; prev: Node | null; } -> Option C
  4. Quick Check:

    Doubly linked node needs next and prev with nulls [OK]
Hint: Doubly linked nodes have next and prev pointers [OK]
Common Mistakes:
  • Omitting the prev pointer
  • Not allowing null for next or prev
  • Using only one pointer like singly linked list
3. Consider this TypeScript code snippet for a doubly linked list node insertion at the front:
class Node {
  value: number;
  next: Node | null = null;
  prev: Node | null = null;
  constructor(value: number) { this.value = value; }
}

class DoublyLinkedList {
  head: Node | null = null;
  insertFront(value: number) {
    const newNode = new Node(value);
    if (this.head) {
      newNode.next = this.head;
      this.head.prev = newNode;
    }
    this.head = newNode;
  }
}

const list = new DoublyLinkedList();
list.insertFront(10);
list.insertFront(20);
list.insertFront(30);

let current = list.head;
const result = [];
while (current) {
  result.push(current.value);
  current = current.next;
}
console.log(result);
What will be printed?
medium
A. [10, 30, 20]
B. [10, 20, 30]
C. [20, 30, 10]
D. [30, 20, 10]

Solution

  1. Step 1: Trace insertFront calls

    First insert 10: list is 10. Then insert 20 at front: list is 20 -> 10. Then insert 30 at front: list is 30 -> 20 -> 10.
  2. Step 2: Traverse from head to next

    Starting at head (30), next is 20, then 10, then null. So collected values are [30, 20, 10].
  3. Final Answer:

    [30, 20, 10] -> Option D
  4. Quick Check:

    Insert front reverses order = [30, 20, 10] [OK]
Hint: Insert front adds new node before head [OK]
Common Mistakes:
  • Assuming insertion appends at end
  • Mixing order of traversal
  • Ignoring prev pointer effects
4. This TypeScript code tries to delete the last node from a doubly linked list but has a bug:
deleteLast() {
  if (!this.head) return;
  let current = this.head;
  while (current.next) {
    current = current.next;
  }
  current.prev.next = null;
}
What is the bug here?
medium
A. It does not handle the case when list has only one node
B. It incorrectly sets current.next to null instead of current.prev.next
C. It causes infinite loop in the while
D. It deletes the head node instead of the last node

Solution

  1. Step 1: Analyze deletion logic

    The code moves to the last node by following next pointers. Then it sets current.prev.next = null to remove last node.
  2. Step 2: Check edge case for single node list

    If list has only one node, current.prev is null, so current.prev.next causes error.
  3. Final Answer:

    It does not handle the case when list has only one node -> Option A
  4. Quick Check:

    Single node list needs special case [OK]
Hint: Check for single node before accessing prev [OK]
Common Mistakes:
  • Ignoring single node edge case
  • Assuming prev is always non-null
  • Confusing next and prev pointers
5. You want to implement a feature that requires frequent backward traversal from any node in a list. Which data structure is best and why? Options: A) Singly linked list because it uses less memory B) Circular singly linked list because it loops infinitely C) Array because it supports random access D) Doubly linked list because it allows backward traversal efficiently
hard
A. Doubly linked list because it allows backward traversal efficiently
B. Circular singly linked list because it loops infinitely
C. Array because it supports random access
D. Singly linked list because it uses less memory

Solution

  1. Step 1: Understand backward traversal need

    Backward traversal means moving from a node to its previous nodes efficiently.
  2. Step 2: Compare data structures for backward traversal

    Singly linked lists do not have backward pointers. Arrays allow random access but not linked traversal. Circular singly linked lists loop but do not support backward traversal. Doubly linked lists have prev pointers for efficient backward moves.
  3. Final Answer:

    Doubly linked list because it allows backward traversal efficiently -> Option A
  4. Quick Check:

    Backward traversal needs prev pointers [OK]
Hint: Backward moves need prev pointers, only doubly linked lists have them [OK]
Common Mistakes:
  • Choosing singly linked list for backward traversal
  • Confusing arrays with linked lists
  • Thinking circular singly linked lists support backward moves
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10 questions~5 mineasy hard