Why Substring Search Patterns in DSA Typescript?

The Big Idea

Discover how computers find your words instantly in huge texts without reading every letter!

The Scenario

Imagine you have a huge book and you want to find every place where a certain word appears. You try to read every page carefully and check each word one by one.

The Problem

This manual way is very slow and tiring. You might miss some places or take a long time to find all matches, especially if the book is very big or the word appears many times.

The Solution

Substring search patterns help computers quickly find where a smaller text appears inside a bigger text. They use smart tricks to skip unnecessary checks and find matches fast and correctly.

Before vs After

✗ Before

function findWord(text: string, word: string): number[] {
  const positions: number[] = [];
  for (let i = 0; i <= text.length - word.length; i++) {
    if (text.substring(i, i + word.length) === word) {
      positions.push(i);
    }
  }
  return positions;
}

✓ After

function kmpSearch(text: string, pattern: string): number[] {
  // KMP algorithm implementation
  // Preprocess pattern to create lps array
  // Use lps to skip characters while matching
  return [];
}

What It Enables

It enables fast and reliable searching of patterns inside large texts, making tasks like searching documents, DNA sequences, or logs efficient.

Real Life Example

When you use the search box in a text editor or browser, substring search patterns help find your word instantly, even in very long documents.

Key Takeaways

Manual search is slow and error-prone for large texts.

Substring search patterns use clever methods to speed up finding matches.

This makes searching in big data fast and reliable.

Practice

1. What is the main goal of substring search algorithms in strings?

easy

A. To sort all characters in a string alphabetically

B. To find if a smaller string exists inside a larger string

C. To reverse the entire string

D. To count the total number of vowels in a string

Solution

1. Step 1: Understand substring search purpose

   Substring search algorithms check if a smaller string (pattern) appears inside a bigger string (text).

2. Step 2: Compare options with substring search definition

   Only To find if a smaller string exists inside a larger string matches this goal. Sorting, reversing, or counting vowels are different tasks.

3. Final Answer:

   To find if a smaller string exists inside a larger string -> Option B

4. Quick Check:

   Substring search = find smaller string inside larger [OK]

Hint: Substring search means finding a smaller string inside a bigger one [OK]

Common Mistakes:

• Confusing substring search with sorting or reversing strings
• Thinking substring search counts characters
• Mixing substring search with string length calculation

2. Which of the following is the correct TypeScript syntax to check if string text contains substring pattern?

easy

A. text.includes(pattern)

B. text.contains(pattern)

C. text.has(pattern)

D. text.find(pattern)

Solution

1. Step 1: Recall TypeScript string methods

   TypeScript strings have a method called includes to check substring presence.

2. Step 2: Verify method names

   Only includes is valid. contains, has, and find are not string methods in TypeScript.

3. Final Answer:

   text.includes(pattern) -> Option A

4. Quick Check:

   Use includes() to check substring presence [OK]

Hint: Use includes() method to check substring in TypeScript [OK]

Common Mistakes:

• Using non-existent methods like contains() or has()
• Confusing includes() with find() which is for arrays
• Forgetting parentheses after method name

3. What will be the output of the following TypeScript code?

const text = "hello world";
const pattern = "wor";
console.log(text.indexOf(pattern));

medium

A. 6

B. -1

C. 3

D. 0

Solution

1. Step 1: Understand indexOf method

   indexOf returns the starting index of the substring if found, else -1.

2. Step 2: Find substring position in text

   In "hello world", substring "wor" starts at index 6 (0-based counting: h=0, e=1, l=2, l=3, o=4, space=5, w=6).

3. Final Answer:

   6 -> Option A

4. Quick Check:

   indexOf("wor") = 6 [OK]

Hint: indexOf returns start index or -1 if not found [OK]

Common Mistakes:

• Counting index starting from 1 instead of 0
• Confusing indexOf with includes (which returns boolean)
• Assuming indexOf returns substring length

4. Identify the error in the following TypeScript code snippet for substring search:

const text = "typescript";
const pattern = "script";
if (text.find(pattern)) {
  console.log("Found");
} else {
  console.log("Not Found");
}

medium

A. Using if statement without parentheses

B. Missing semicolon after console.log statements

C. Pattern variable is not declared

D. Using find() method on string which does not exist

Solution

1. Step 1: Check string methods in TypeScript

   Strings do not have a find() method. The correct method to check substring is includes() or indexOf().

2. Step 2: Verify other code parts

   Semicolons are optional in TypeScript, pattern is declared, and if statement syntax is correct.

3. Final Answer:

   Using find() method on string which does not exist -> Option D

4. Quick Check:

   Strings have includes(), not find() [OK]

Hint: Use includes() or indexOf(), not find() on strings [OK]

Common Mistakes:

• Assuming find() works on strings like arrays
• Thinking semicolons are mandatory causing errors
• Misreading if statement syntax

5. You want to find all starting indices of substring pattern in string text. Which approach correctly finds multiple occurrences in TypeScript?

hard

A. Use text.indexOf(pattern) once and return that single index

B. Use text.includes(pattern) repeatedly without changing index

C. Use a loop with indexOf(pattern, startIndex) updating startIndex after each find

D. Use text.findAll(pattern) method to get all indices

Solution

1. Step 1: Understand multiple substring search

   To find all occurrences, you must repeatedly search starting after the last found index.

2. Step 2: Analyze each option

   Use a loop with indexOf(pattern, startIndex) updating startIndex after each find uses a loop with indexOf and updates start index, which is correct. Use text.includes(pattern) repeatedly without changing index does not update index, so it loops infinitely or finds only once. Use text.indexOf(pattern) once and return that single index finds only one occurrence. Use text.findAll(pattern) method to get all indices uses a non-existent method.

3. Final Answer:

   Use a loop with indexOf(pattern, startIndex) updating startIndex after each find -> Option C

4. Quick Check:

   Loop with indexOf and updated start index finds all [OK]

Hint: Loop with indexOf and update start index to find all [OK]

Common Mistakes:

• Not updating start index causing infinite loops
• Using includes() which returns boolean, not index
• Expecting findAll() method which does not exist