A stack is a collection where elements are added and removed from the top only. It follows Last In, First Out (LIFO) order, like a stack of plates where you add or remove the top plate first.
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beginner
What is a linked list in simple terms?
A linked list is a chain of nodes where each node holds data and a link (pointer) to the next node. Itβs like a treasure hunt where each clue leads to the next one.
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intermediate
Why use a linked list to implement a stack?
Using a linked list for a stack allows dynamic size changes without fixed limits. It easily adds or removes elements at the top without shifting others, unlike arrays.
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beginner
What does the push operation do in a stack implemented with a linked list?
Push adds a new node at the start (top) of the linked list. The new node points to the old top, and then it becomes the new top.
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beginner
What happens during the pop operation in a stack implemented with a linked list?
Pop removes the top node from the linked list. The top pointer moves to the next node, effectively removing the first node from the stack.
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What order does a stack follow?
ARandom order
BFirst In, First Out (FIFO)
CSorted order
DLast In, First Out (LIFO)
β Incorrect
A stack follows Last In, First Out (LIFO) order, meaning the last element added is the first to be removed.
In a linked list, what does each node contain?
AData and a pointer to the next node
BOnly data
COnly a pointer to the previous node
DData and a pointer to the previous node
β Incorrect
Each node in a linked list contains data and a pointer to the next node.
What does the push operation do in a stack using a linked list?
ARemoves the top node
BAdds a new node at the bottom
CAdds a new node at the top
DRemoves the bottom node
β Incorrect
Push adds a new node at the top of the stack (start of the linked list).
What happens when you pop from an empty stack?
AReturn null or error
BAdd a new node
CReturn the bottom node
DNothing happens
β Incorrect
Popping from an empty stack returns null or an error because there is no element to remove.
Why is a linked list preferred over an array for stack implementation?
AEasier to sort
BDynamic size and no shifting needed
CUses less memory always
DFaster access to middle elements
β Incorrect
Linked lists allow dynamic size changes and easy addition/removal at the top without shifting elements.
Explain how push and pop operations work in a stack implemented using a linked list.
Think about how nodes connect and disconnect at the start of the list.
You got /5 concepts.
Describe the advantages of using a linked list to implement a stack compared to using an array.
Consider how arrays have fixed size and shifting costs.
You got /4 concepts.
Practice
(1/5)
1. What is the main advantage of implementing a stack using a linked list instead of an array?
easy
A. It allows random access to elements
B. It uses less memory than an array
C. The stack can grow dynamically without a fixed size limit
D. It is faster to access elements by index
Solution
Step 1: Understand stack size limitation in arrays
Arrays have a fixed size, so stacks implemented with arrays have a maximum capacity.
Step 2: Linked list dynamic size
Linked lists can grow or shrink dynamically by adding or removing nodes, so stack size is not fixed.
Final Answer:
The stack can grow dynamically without a fixed size limit -> Option C
Quick Check:
Linked list stacks grow dynamically = A [OK]
Hint: Linked list stacks grow dynamically, arrays do not [OK]
Common Mistakes:
Thinking linked lists use less memory always
Confusing stack with queue behavior
Assuming random access is possible in linked lists
2. Which of the following is the correct TypeScript syntax to define a node class for a linked list stack?
easy
A. class Node { value: number; next: Node; constructor(value: number) { this.value = value; this.next = null; } }
3. Given the following TypeScript code for a stack push operation, what will be the top node's value after pushing 10, then 20?
medium
A. undefined
B. 10
C. null
D. 20
Solution
Step 1: Understand push operation
Push adds a new node at the top, so the last pushed value becomes the top.
Step 2: Trace pushing 10 then 20
First push 10: top.value = 10; then push 20: top.value = 20 (new node).
Final Answer:
20 -> Option D
Quick Check:
Last pushed value is top = 20 [OK]
Hint: Top always holds last pushed value [OK]
Common Mistakes:
Assuming bottom value is top
Confusing push with pop
Not updating top pointer
4. Identify the error in this pop method of a linked list stack implementation:
pop(): number | null {
if (!this.top) return null;
const value = this.top.value;
this.top = this.top.next;
return this.top.value;
}
medium
A. Returns the new top value instead of popped value
B. Does not check if stack is empty
C. Does not update top pointer
D. Throws error when stack is empty
Solution
Step 1: Analyze return value
The method returns this.top.value after updating top, which is the new top, not the popped value.
Step 2: Correct return value
It should return the saved value before updating top to return the popped element.
Final Answer:
Returns the new top value instead of popped value -> Option A
Quick Check:
Pop must return popped value, not new top [OK]
Hint: Return saved value before updating top [OK]
Common Mistakes:
Returning top after update instead of popped value
Not handling empty stack
Forgetting to update top pointer
5. You want to implement a method peek() in your linked list stack that returns the top value without removing it. Which is the correct implementation?
hard
A. peek(): number | null { return this.top ? this.top.value : null; }
B. peek(): number | null { const val = this.top.value; this.top = this.top.next; return val; }
C. peek(): number | null { if (!this.top) return null; this.top = this.top.next; return this.top.value; }
D. peek(): number | null { return this.top.next ? this.top.next.value : null; }
Solution
Step 1: Understand peek operation
Peek returns the top value without changing the stack.
Step 2: Check each option
peek(): number | null { return this.top ? this.top.value : null; } returns top value if exists, else null, without modifying stack. Others modify top or return wrong node.
Final Answer:
peek(): number | null { return this.top ? this.top.value : null; } -> Option A
Quick Check:
Peek returns top value without removal = C [OK]
Hint: Peek returns top value without changing stack [OK]
Common Mistakes:
Modifying top pointer in peek
Returning next node's value
Not handling empty stack
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