Why Roman to Integer Conversion in DSA Typescript?

The Big Idea

What if you could turn ancient Roman numbers into modern digits with just a few lines of code?

The Scenario

Imagine you have a list of Roman numerals written on old scrolls, and you need to add them up or compare their values. Doing this by hand means remembering all the Roman numeral rules and converting each symbol carefully every time.

The Problem

Manually converting Roman numerals is slow and easy to mess up. You might forget when to subtract instead of add, or confuse symbols. This leads to mistakes and wastes time, especially with long or many numerals.

The Solution

Roman to Integer Conversion automates this process. It uses a simple set of rules in code to quickly and correctly turn any Roman numeral into its number form. This saves time and avoids errors.

Before vs After

✗ Before

function manualRomanToInt(roman: string): number {
  // Manually check each symbol and add or subtract
  let total = 0;
  for (let i = 0; i < roman.length; i++) {
    // Complex if-else for each case
  }
  return total;
}

✓ After

function romanToInt(roman: string): number {
  const values: {[key: string]: number} = {I:1, V:5, X:10, L:50, C:100, D:500, M:1000};
  let total = 0;
  for (let i = 0; i < roman.length; i++) {
    if (values[roman[i]] < values[roman[i+1]] || roman[i+1] === undefined) {
      total -= values[roman[i]];
    } else {
      total += values[roman[i]];
    }
  }
  return total;
}

What It Enables

This lets you instantly understand and work with Roman numerals in your programs, unlocking easy math and comparisons with ancient numbering.

Real Life Example

Suppose you are building a history app that shows dates in Roman numerals. This conversion lets you sort events by date or calculate durations without manual errors.

Key Takeaways

Manual conversion is slow and error-prone.

Code uses simple rules to convert quickly and correctly.

Enables easy math and comparisons with Roman numerals.

Practice

1. What is the main rule to convert Roman numerals to integers?

easy

A. Add values of symbols, subtract if a smaller symbol is before a larger one

B. Multiply all symbol values together

C. Add values only if symbols are the same

D. Subtract all symbol values from 1000

Solution

1. Step 1: Understand Roman numeral rules

   Roman numerals are converted by adding values of symbols, but if a smaller value comes before a larger one, it is subtracted.

2. Step 2: Apply the rule to conversion

   For example, IV is 5 - 1 = 4, not 1 + 5 = 6.

3. Final Answer:

   Add values of symbols, subtract if a smaller symbol is before a larger one -> Option A

4. Quick Check:

   Roman to integer = add/subtract values [OK]

Hint: Subtract when smaller symbol precedes larger one [OK]

Common Mistakes:

• Always adding values without subtraction
• Multiplying symbol values
• Ignoring order of symbols

2. Which TypeScript syntax correctly defines a function to convert Roman numerals to integers?

easy

A. def romanToInt(s): return 0

B. function romanToInt(s: string): number { return 0; }

C. func romanToInt(s string) int { return 0 }

D. romanToInt = (s) => { return '0'; }

Solution

1. Step 1: Identify TypeScript function syntax

   TypeScript functions use the syntax: function name(params): returnType { body }

2. Step 2: Match correct syntax

   function romanToInt(s: string): number { return 0; } matches TypeScript syntax with parameter type and return type specified.

3. Final Answer:

   function romanToInt(s: string): number { return 0; } -> Option B

4. Quick Check:

   TypeScript function syntax = function romanToInt(s: string): number { return 0; } [OK]

Hint: Use 'function name(params: type): returnType' in TypeScript [OK]

Common Mistakes:

• Using Python or Go syntax in TypeScript
• Returning string instead of number
• Missing type annotations

3. What is the output of this TypeScript code?

function romanToInt(s: string): number {
  const map: {[key: string]: number} = {I:1, V:5, X:10, L:50, C:100, D:500, M:1000};
  let total = 0;
  for(let i = 0; i < s.length; i++) {
    const current = map[s[i]];
    const next = map[s[i+1]] || 0;
    if(current < next) total -= current;
    else total += current;
  }
  return total;
}
console.log(romanToInt('IX'));

medium

A. 11

B. 4

C. 9

D. Error

Solution

1. Step 1: Trace the loop for 'IX'

   For 'I' (1) and next 'X' (10), since 1 < 10, subtract 1. For 'X' (10), no next, add 10.

2. Step 2: Calculate total

   Total = -1 + 10 = 9.

3. Final Answer:

   9 -> Option C

4. Quick Check:

   'IX' = 9 [OK]

Hint: Subtract if current < next, else add [OK]

Common Mistakes:

• Adding all values without subtraction
• Off-by-one error in loop
• Not handling last character correctly

4. Find the bug in this TypeScript code for Roman to Integer conversion:

function romanToInt(s: string): number {
  const map = {I:1, V:5, X:10, L:50, C:100, D:500, M:1000};
  let total = 0;
  for(let i = 0; i <= s.length; i++) {
    const current = map[s[i]];
    const next = map[s[i+1]] || 0;
    if(current < next) total -= current;
    else total += current;
  }
  return total;
}

medium

A. Return type should be string, not number

B. map object keys should be lowercase

C. Use 'var' instead of 'let' for i

D. Loop condition should be i < s.length, not i <= s.length

Solution

1. Step 1: Check loop boundary

   The loop runs from i = 0 to i <= s.length, which causes s[i] to be undefined at last iteration.

2. Step 2: Correct loop condition

   Change to i < s.length to avoid accessing undefined index.

3. Final Answer:

   Loop condition should be i < s.length, not i <= s.length -> Option D

4. Quick Check:

   Loop boundary off-by-one error fixed [OK]

Hint: Use i < length to avoid out-of-bounds access [OK]

Common Mistakes:

• Using <= instead of < in loops
• Wrong case for map keys
• Incorrect return type

5. Given the Roman numeral string 'MCMXCIV', what integer does the following TypeScript function return?

function romanToInt(s: string): number {
  const map: {[key: string]: number} = {I:1, V:5, X:10, L:50, C:100, D:500, M:1000};
  let total = 0;
  for(let i = 0; i < s.length; i++) {
    const current = map[s[i]];
    const next = map[s[i+1]] || 0;
    if(current < next) total -= current;
    else total += current;
  }
  return total;
}
console.log(romanToInt('MCMXCIV'));

hard

A. 1994

B. 1904

C. 2004

D. 1494

Solution

1. Step 1: Break down 'MCMXCIV'

   M=1000, C=100, M=1000, X=10, C=100, I=1, V=5. Apply subtraction where smaller precedes larger.

2. Step 2: Calculate total step-by-step

   1000 (M) + (100 < 1000, subtract 100) + 1000 + (10 < 100, subtract 10) + 100 + (1 < 5, subtract 1) + 5 = 1000 - 100 + 1000 - 10 + 100 - 1 + 5 = 1994.

3. Final Answer:

   1994 -> Option A

4. Quick Check:

   'MCMXCIV' = 1994 [OK]

Hint: Subtract smaller before larger, else add [OK]

Common Mistakes:

• Adding all values without subtraction
• Misreading symbol order
• Skipping last character