Reverse Bits of a Number in DSA Typescript - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the result variable to zero.

DSA Typescript

let result = [1];

Drag options to blanks, or click blank then click option'

A0

Bundefined

Cnull

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Initializing result with 1 or null instead of 0.

We start with result as 0 because we will build the reversed bits from scratch.

2fill in blank

medium

Complete the code to extract the least significant bit from n.

DSA Typescript

let bit = n [1] 1;

Drag options to blanks, or click blank then click option'

A|

B&

C^

D>>

Attempts:

3 left

💡 Hint

Common Mistakes

Using | or ^ instead of & to extract the bit.

Using bitwise AND (&) with 1 extracts the last bit of n.

3fill in blank

hard

Fix the error in the code to shift the result left by one bit.

DSA Typescript

result = result [1] 1;

Drag options to blanks, or click blank then click option'

A>>

B-

C+

D<<

Attempts:

3 left

💡 Hint

Common Mistakes

Using + or >> instead of << for shifting bits left.

Left shift (<<) moves bits to the left, making space for the next bit.

4fill in blank

hard

Fill both blanks to update result with the new bit and shift n right.

DSA Typescript

result = (result [1] bit);
n = n [2] 1;

Drag options to blanks, or click blank then click option'

A|

B&

C>>

D<<

Attempts:

3 left

💡 Hint

Common Mistakes

Using & instead of | to add bit, or << instead of >> to shift n.

Use bitwise OR (|) to add the bit to result, and right shift (>>) to move n's bits right.

5fill in blank

hard

Fill all three blanks to complete the reverseBits function.

DSA Typescript

function reverseBits(n: number): number {
  let result = [1];
  for (let i = 0; i < 32; i++) {
    let bit = n [2] 1;
    result = (result << 1) [3] bit;
    n = n >> 1;
  }
  return result;
}

Drag options to blanks, or click blank then click option'

A0

B&

C|

D<<

Attempts:

3 left

💡 Hint

Common Mistakes

Not shifting result left before OR, or wrong initialization of result.

Initialize result to 0, extract bit with AND (&), add bit with OR (|), and shift result left before adding bit.

Practice

1. What does reversing the bits of a number mean in simple terms?

easy

A. Changing all 0 bits to 1 bits

B. Flipping the order of all bits from left to right

C. Adding 1 to the number

D. Shifting bits to the left by one position

Solution

1. Step 1: Understand bit order

   Bits are arranged from left (most significant) to right (least significant).

2. Step 2: Reverse means flip order

   Reversing bits means the leftmost bit becomes rightmost, second leftmost becomes second rightmost, and so on.

3. Final Answer:

   Flipping the order of all bits from left to right -> Option B

4. Quick Check:

   Reverse bits = flip order [OK]

Hint: Reverse bits means flip their order from left to right [OK]

Common Mistakes:

• Thinking reversing bits means changing 0 to 1
• Confusing reversing bits with shifting bits
• Assuming reversing bits adds or subtracts from number

2. Which TypeScript code snippet correctly reverses the bits of an 8-bit number n?

easy

A. let result = 0; for(let i=0; i<8; i++) { result |= ((n >> i) & 1) << (7 - i); }

B. let result = 0; for(let i=0; i<8; i++) { result |= ((n << i) & 1) << i; }

C. let result = 0; for(let i=0; i<8; i++) { result += (n & 1) << i; n >>= 1; }

D. let result = 0; for(let i = 0; i < 8; i++) { result |= (n & 1) << i; n >>= 1; }

Solution

1. Step 1: Analyze bit extraction and placement

   let result = 0; for(let i=0; i<8; i++) { result |= ((n >> i) & 1) << (7 - i); } extracts each bit from right to left and places it reversed from left to right correctly.

2. Step 2: Check other options

   A extracts LSBs but places them starting from low bits (original order); B uses left shift for extraction which fails to get bits properly; C uses arithmetic + instead of bitwise | and builds original order.

3. Final Answer:

   let result = 0; for(let i=0; i<8; i++) { result |= ((n >> i) & 1) << (7 - i); } -> Option A

4. Quick Check:

   Right shift and left place = correct reverse [OK]

Hint: Shift right to extract bits, shift left to place reversed bits [OK]

Common Mistakes:

• Using left shift to extract bits instead of right shift
• Not reversing the bit position when placing
• Adding bits instead of using bitwise OR

3. What is the output of this TypeScript code?

function reverseBits(n: number): number {
  let result = 0;
  for (let i = 0; i < 4; i++) {
    result |= ((n >> i) & 1) << (3 - i);
  }
  return result;
}
console.log(reverseBits(6));

medium

A. 6

B. 9

C. 3

D. 12

Solution

1. Step 1: Convert 6 to 4-bit binary

   6 in binary (4 bits) is 0110.

2. Step 2: Reverse bits

   Bits from LSB: 0,1,1,0. Reversed positions yield 0,1,1,0 reversed is 0110 reversed to 0110 reversed is 0110? Actually reversed bits are 0110 reversed to 0110? Let's check carefully.

3. Step 3: Dry run code

   i=0: (6 >> 0) & 1 = 0 << 3 = 0
   i=1: (6 >> 1) & 1 = 1 << 2 = 4 (result=4)
   i=2: (6 >> 2) & 1 = 1 << 1 = 2 (result=6)
   i=3: (6 >> 3) & 1 = 0 << 0 = 0 (result=6)

4. Step 4: Check if output matches options

   Output is 6, but 9 is 9, 6 is 6.

5. Final Answer:

   6 -> Option A

6. Quick Check:

   Reverse bits of 6 (0110) = 6 [OK]

Hint: Trace bit shifts carefully to find reversed number [OK]

Common Mistakes:

• Confusing bit positions when reversing
• Assuming reversed bits always change the number
• Miscounting bits or loop range

4. Identify the bug in this TypeScript function that reverses 8-bit numbers:

function reverseBits(n: number): number {
  let result = 0;
  for (let i = 0; i <= 8; i++) {
    result |= ((n >> i) & 1) << (7 - i);
  }
  return result;
}

medium

A. Variable result should be initialized to 1

B. Bitwise OR operator is used incorrectly

C. Shift amount is not adjusted for 8 bits

D. Loop runs one extra time causing incorrect bit shift

Solution

1. Step 1: Check loop range

   The loop runs from i = 0 to i = 8 inclusive, so 9 iterations total, but 8-bit numbers have bits 0 to 7 only.

2. Step 2: Effect of extra iteration

   At i=8, shifting by (7 - 8) = -1 is invalid and causes incorrect behavior or runtime error.

3. Final Answer:

   Loop runs one extra time causing incorrect bit shift -> Option D

4. Quick Check:

   Loop should run 8 times, not 9 [OK]

Hint: Loop from 0 to 7 for 8 bits, not 0 to 8 [OK]

Common Mistakes:

• Using <= instead of < in loop condition
• Ignoring negative shift values
• Initializing result incorrectly

5. You want to reverse the bits of a 16-bit number and then check if the reversed number is a palindrome in binary (reads same forwards and backwards). Which approach is correct?

hard

A. Reverse bits using a loop, then compare reversed number to original

B. Reverse bits using a loop, then reverse again and compare to original

C. Reverse bits using a loop, then check if reversed number equals its own reverse

D. Check if original number equals its own reverse without reversing bits

Solution

1. Step 1: Reverse bits of the number

   Use a loop to reverse bits of the 16-bit number to get reversedNum.

2. Step 2: Check palindrome property

   To check if reversedNum is palindrome, reverse reversedNum again and compare with reversedNum itself.

3. Step 3: Reasoning

   If reversedNum equals its own reverse, it is a palindrome in binary.

4. Final Answer:

   Reverse bits using a loop, then check if reversed number equals its own reverse -> Option C

5. Quick Check:

   Palindrome check = reversedNum == reverse(reversedNum) [OK]

Hint: Check palindrome by reversing reversed number and comparing [OK]

Common Mistakes:

• Comparing reversed number to original instead of itself
• Not reversing reversed number for palindrome check
• Assuming original number palindrome means reversed number palindrome