A. pop() returns undefined when stack is empty, no error
B. Runtime error because pop() on empty array is invalid
C. Syntax error due to missing type annotation
D. pop() removes first element instead of last
Solution
Step 1: Check pop() behavior on empty array
pop() returns undefined if the array is empty; it does not throw an error.
Step 2: Verify code correctness
Code runs without error and prints undefined.
Final Answer:
pop() returns undefined when stack is empty, no error -> Option A
Quick Check:
pop() on empty array = undefined [OK]
Hint: pop() returns undefined if stack is empty, no crash [OK]
Common Mistakes:
Expecting runtime error on empty pop()
Confusing pop() with shift() behavior
Thinking pop() removes first element
5. Given a stack implemented as an array stack = [5, 10, 15, 20], write a TypeScript function popTwo that pops two elements and returns them as an array. What will be the returned value and the stack after calling popTwo(stack)?
hard
A. [15, 20], stack = [5, 10]
B. [20, 15], stack = [5, 10]
C. [20, 15], stack = [10, 5]
D. [10, 5], stack = [15, 20]
Solution
Step 1: Understand pop() order and stack state
pop() removes last element first. First pop returns 20, second pop returns 15.
Step 2: Determine returned array and stack after two pops
Returned array is [20, 15]. Stack after pops is [5, 10].
Final Answer:
[20, 15], stack = [5, 10] -> Option B
Quick Check:
Two pops remove last two elements in order [20, 15] [OK]
Hint: Pop twice returns last two elements in reverse order [OK]
Common Mistakes:
Returning popped elements in wrong order
Assuming stack order changes after pop
Mixing up stack contents after pops
Recommended
Ready to prove it?
Pass the test and this pattern moves unknownstrongwhile earning +1 Grip toward your certificate.