Discover how to find hidden mirror words inside any text without endless guessing!
Why Longest Palindromic Substring in DSA Typescript?
Imagine you have a long word or sentence, and you want to find the longest part that reads the same forwards and backwards, like 'racecar' or 'level'. Doing this by checking every possible part by hand is like looking for a needle in a haystack.
Manually checking each part is very slow and tiring because you have to look at many combinations. It's easy to make mistakes or miss the longest palindrome, especially when the word is long.
The Longest Palindromic Substring algorithm quickly finds the longest palindrome by expanding around centers, saving time and avoiding errors. It smartly checks only necessary parts instead of all combinations.
for (let i = 0; i < s.length; i++) { for (let j = i; j < s.length; j++) { let substring = s.substring(i, j + 1); if (isPalindrome(substring)) { updateLongest(substring); } } }
for (let center = 0; center < s.length; center++) { expandAroundCenter(s, center, center); expandAroundCenter(s, center, center + 1); }
This lets you quickly find the longest palindrome inside any string, enabling fast text analysis and pattern recognition.
In DNA research, finding palindromic sequences helps identify important genetic markers that read the same forwards and backwards.
Manual checking is slow and error-prone.
Expanding around centers finds palindromes efficiently.
Useful for fast pattern detection in strings.
Practice
Longest Palindromic Substring problem?Solution
Step 1: Understand palindrome definition
A palindrome reads the same forwards and backwards, like 'madam' or 'racecar'.Step 2: Identify the problem goal
The problem asks to find the longest substring inside a string that is a palindrome.Final Answer:
Find the longest substring that reads the same forwards and backwards -> Option BQuick Check:
Palindrome substring = longest palindrome [OK]
- Confusing palindrome with unique characters
- Looking for longest substring without repeats
- Thinking about substrings with vowels only
Solution
Step 1: Check input parameter type
The input is a string, so parameter type must bestring.Step 2: Check return type
The function returns the longest palindromic substring, which is a string.Final Answer:
function longestPalindrome(s: string): string -> Option AQuick Check:
Input string, output string [OK]
- Using wrong input type like number or boolean
- Returning array instead of string
- Mixing input and output types
function longestPalindrome(s: string): string {
let start = 0, maxLength = 1;
for (let i = 0; i < s.length; i++) {
let low = i, high = i;
while (low >= 0 && high < s.length && s[low] === s[high]) {
if (high - low + 1 > maxLength) {
start = low;
maxLength = high - low + 1;
}
low--;
high++;
}
}
return s.substring(start, start + maxLength);
}
console.log(longestPalindrome('babad'))Solution
Step 1: Understand the code logic
The code expands around each character to find odd-length palindromes and tracks the longest one.Step 2: Trace the input 'babad'
Expanding around index 1 ('a') finds 'bab' (length 3). Around index 2 ('b') finds 'aba' (length 3). Both have length 3, but 'bab' is found first and stored.Final Answer:
"bab" -> Option AQuick Check:
First longest palindrome found = "bab" [OK]
- Assuming 'aba' is always returned instead of 'bab'
- Returning entire string incorrectly
- Confusing substring indices
function longestPalindrome(s: string): string {
let start = 0, maxLength = 1;
for (let i = 0; i < s.length; i++) {
let low = i, high = i + 1;
while (low >= 0 && high < s.length && s[low] === s[high]) {
if (high - low + 1 > maxLength) {
start = low;
maxLength = high - low + 1;
}
low--;
high++;
}
}
return s.substring(start, start + maxLength);
}Solution
Step 1: Analyze initialization of low and high
low = i and high = i + 1 means it only checks even-length palindromes centered between i and i+1.Step 2: Identify missing odd-length palindrome check
Odd-length palindromes centered at i (low = high = i) are not checked, so some palindromes are missed.Final Answer:
The code only checks even-length palindromes, missing odd-length ones -> Option CQuick Check:
Only even-length palindrome check = bug [OK]
- Checking only even-length palindromes
- Not expanding around single character centers
- Incorrect loop start index
"forgeeksskeegfor", which approach correctly finds the longest palindromic substring and what is that substring?Solution
Step 1: Identify the longest palindrome in the string
The substring "geeksskeeg" is the longest palindrome inside "forgeeksskeegfor".Step 2: Match approach with correct palindrome
Expand around center approach finds "geeksskeeg" correctly. The entire string is not a palindrome, so options A and B are incorrect. Brute force (C) incorrectly identifies "ss" as the longest.Final Answer:
Expand around center approach; longest palindrome is "geeksskeeg" -> Option DQuick Check:
Center expansion finds "geeksskeeg" [OK]
- Assuming entire string is palindrome
- Confusing brute force with efficient methods
- Mixing up palindrome substrings
Ready to prove it?
Pass the test and this pattern moves unknown
