Kadane's Algorithm Maximum Subarray in DSA Typescript - Build from Scratch

Kadane's Algorithm Maximum Subarray

📖 Scenario: You are analyzing daily temperature changes to find the longest warm spell. The temperature changes are recorded as numbers in an array, where positive numbers mean warmer days and negative numbers mean colder days.

🎯 Goal: Build a program that finds the maximum sum of a continuous subarray using Kadane's Algorithm. This helps identify the warmest period in the temperature changes.

📋 What You'll Learn

Create an array called tempChanges with the exact values: [2, -1, 3, -4, 5, -2, 6, -1]

Create a variable called maxSoFar and set it to the first element of tempChanges

Create a variable called maxEndingHere and set it to the first element of tempChanges

Use a for loop with variable i starting from 1 to iterate over tempChanges

Inside the loop, update maxEndingHere to the maximum of tempChanges[i] and maxEndingHere + tempChanges[i]

Inside the loop, update maxSoFar to the maximum of maxSoFar and maxEndingHere

Print the value of maxSoFar

💡 Why This Matters

🌍 Real World

Finding the warmest period in temperature changes helps meteorologists and farmers plan better.

💼 Career

Kadane's Algorithm is a classic technique used in software engineering interviews and real-world problems involving maximum sums.

1

Create the temperature changes array

Create an array called tempChanges with these exact values: [2, -1, 3, -4, 5, -2, 6, -1]

DSA Typescript

# Your code here

Hint

Use const to create the array with the exact numbers inside square brackets.

2

Initialize variables for Kadane's Algorithm

Create a variable called maxSoFar and set it to the first element of tempChanges. Also create a variable called maxEndingHere and set it to the first element of tempChanges.

DSA Typescript

const tempChanges = [2, -1, 3, -4, 5, -2, 6, -1];
// Your code here

Hint

Use let to create variables and assign the first element of tempChanges using index 0.

3

Implement the core loop of Kadane's Algorithm

Use a for loop with variable i starting from 1 to iterate over tempChanges. Inside the loop, update maxEndingHere to the maximum of tempChanges[i] and maxEndingHere + tempChanges[i]. Then update maxSoFar to the maximum of maxSoFar and maxEndingHere.

DSA Typescript

const tempChanges = [2, -1, 3, -4, 5, -2, 6, -1];
let maxSoFar = tempChanges[0];
let maxEndingHere = tempChanges[0];
// Your code here

Hint

Use Math.max to compare values and update variables inside the loop.

4

Print the maximum subarray sum

Print the value of maxSoFar using console.log.

DSA Typescript

const tempChanges = [2, -1, 3, -4, 5, -2, 6, -1];
let maxSoFar = tempChanges[0];
let maxEndingHere = tempChanges[0];
for (let i = 1; i < tempChanges.length; i++) {
    maxEndingHere = Math.max(tempChanges[i], maxEndingHere + tempChanges[i]);
    maxSoFar = Math.max(maxSoFar, maxEndingHere);
}
// Your code here

Hint

Use console.log(maxSoFar) to print the result.

Practice

1. What does Kadane's Algorithm primarily help to find in an array of integers?

easy

A. The number of positive elements

B. The minimum element in the array

C. The total sum of all elements

D. The maximum sum of a contiguous subarray

Solution

1. Step 1: Understand the problem Kadane's Algorithm solves

   Kadane's Algorithm is designed to find the maximum sum of any contiguous subarray within a given array.

2. Step 2: Differentiate from other array operations

   It does not find minimum elements, total sum, or count positives, but specifically the largest sum of a continuous segment.

3. Final Answer:

   The maximum sum of a contiguous subarray -> Option D

4. Quick Check:

   Maximum subarray sum = The maximum sum of a contiguous subarray [OK]

Hint: Kadane finds max sum in continuous parts of array [OK]

Common Mistakes:

• Confusing max sum with total sum of array
• Thinking it finds minimum values
• Assuming it counts positive numbers

2. Which of the following is the correct initialization step in Kadane's Algorithm in TypeScript?

easy

A. let maxSoFar = Number.MIN_SAFE_INTEGER, maxEndingHere = 0;

B. let maxSoFar = [], maxEndingHere = [];

C. let maxSoFar = 0, maxEndingHere = 0;

D. let maxSoFar = null, maxEndingHere = null;

Solution

1. Step 1: Understand initialization for Kadane's Algorithm

   We initialize maxSoFar to the smallest safe integer to handle arrays with negative numbers correctly, and maxEndingHere to 0.

2. Step 2: Check each option's correctness

   let maxSoFar = Number.MIN_SAFE_INTEGER, maxEndingHere = 0; correctly uses Number.MIN_SAFE_INTEGER for maxSoFar and 0 for maxEndingHere. Other options use incorrect types or values.

3. Final Answer:

   let maxSoFar = Number.MIN_SAFE_INTEGER, maxEndingHere = 0; -> Option A

4. Quick Check:

   Initialization with min safe integer = let maxSoFar = Number.MIN_SAFE_INTEGER, maxEndingHere = 0; [OK]

Hint: Initialize maxSoFar with smallest integer to handle negatives [OK]

Common Mistakes:

• Initializing maxSoFar to 0 causes wrong results with all negatives
• Using arrays instead of numbers for maxSoFar
• Setting variables to null instead of numbers

3. What is the output of the following TypeScript code using Kadane's Algorithm?

function maxSubArray(nums: number[]): number {
  let maxSoFar = Number.MIN_SAFE_INTEGER;
  let maxEndingHere = 0;
  for (const num of nums) {
    maxEndingHere = Math.max(num, maxEndingHere + num);
    maxSoFar = Math.max(maxSoFar, maxEndingHere);
  }
  return maxSoFar;
}

console.log(maxSubArray([-2,1,-3,4,-1,2,1,-5,4]));

medium

A. 6

B. 7

C. 5

D. 4

Solution

1. Step 1: Trace the Kadane's Algorithm on the input array

   Iterate through [-2,1,-3,4,-1,2,1,-5,4]: max subarray sums update as -2,1, -2,4,3,5,6,1,5.

2. Step 2: Identify the maximum sum found

   The maximum sum found during iteration is 6, which corresponds to subarray [4,-1,2,1].

3. Final Answer:

   6 -> Option A

4. Quick Check:

   Max subarray sum = 6 [OK]

Hint: Track maxEndingHere and maxSoFar updates carefully [OK]

Common Mistakes:

• Adding all positive numbers only
• Ignoring negative numbers impact
• Confusing maxSoFar with maxEndingHere

4. Identify the bug in this Kadane's Algorithm implementation and select the fix:

function maxSubArray(nums: number[]): number {
  let maxSoFar = 0;
  let maxEndingHere = 0;
  for (const num of nums) {
    maxEndingHere = Math.max(num, maxEndingHere + num);
    maxSoFar = Math.max(maxSoFar, maxEndingHere);
  }
  return maxSoFar;
}

medium

A. Remove resetting maxEndingHere to 0 when negative

B. Initialize maxSoFar with Number.MIN_SAFE_INTEGER instead of 0

C. Change maxEndingHere += num to maxEndingHere = num

D. Return maxEndingHere instead of maxSoFar

Solution

1. Step 1: Analyze initialization problem

   Initializing maxSoFar to 0 causes wrong results if all numbers are negative, as maxSoFar never updates below 0.

2. Step 2: Fix initialization to handle negative arrays

   Setting maxSoFar to Number.MIN_SAFE_INTEGER allows correct tracking of max sums even if all are negative.

3. Final Answer:

   Initialize maxSoFar with Number.MIN_SAFE_INTEGER instead of 0 -> Option B

4. Quick Check:

   Proper initialization fixes negative-only arrays [OK]

Hint: Use smallest integer for maxSoFar to handle negatives [OK]

Common Mistakes:

• Leaving maxSoFar as 0 causes wrong max for negatives
• Removing reset of maxEndingHere breaks algorithm logic
• Returning wrong variable from function

5. Given an array of integers, how can Kadane's Algorithm be adapted to also return the start and end indices of the maximum sum subarray?
Choose the correct approach.

hard

A. Use two nested loops to find max sum and indices

B. Store all subarrays and pick the max sum one at the end

C. Track start index when maxEndingHere resets; update end index when maxSoFar updates

D. Return the first positive element's index as start and end

Solution

1. Step 1: Understand Kadane's Algorithm extension for indices

   When maxEndingHere resets to current element, update start index; when maxSoFar updates, update end index to current position.

2. Step 2: Compare with other approaches

   Storing all subarrays or using nested loops is inefficient; returning first positive index is incorrect.

3. Final Answer:

   Track start index when maxEndingHere resets; update end index when maxSoFar updates -> Option C

4. Quick Check:

   Index tracking with resets and updates = Track start index when maxEndingHere resets; update end index when maxSoFar updates [OK]

Hint: Update start on reset, end on max update for indices [OK]

Common Mistakes:

• Using nested loops loses Kadane's efficiency
• Ignoring index updates when maxEndingHere resets
• Assuming first positive element is max subarray start