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DSA Typescriptprogramming~3 mins

Why Insert at Specific Position in Doubly Linked List in DSA Typescript?

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The Big Idea

What if you could add anything exactly where you want without breaking your list?

The Scenario

Imagine you have a paper list of your favorite songs. You want to add a new song exactly at position 3, but you have to rewrite the whole list every time you want to insert a song in the middle.

The Problem

Manually rewriting the list every time you add a song in the middle is slow and easy to mess up. You might lose track of the order or accidentally skip a song.

The Solution

A doubly linked list lets you jump to the exact spot and insert the new song without rewriting the whole list. It keeps track of neighbors both before and after, so adding anywhere is quick and safe.

Before vs After
✗ Before
let list = ['song1', 'song2', 'song4'];
// To insert 'song3' at position 3
list = list.slice(0, 2).concat(['song3'], list.slice(2));
✓ After
doublyLinkedList.insertAtPosition('song3', 3);
What It Enables

You can quickly and safely add items anywhere in your list without breaking the order or rewriting everything.

Real Life Example

Adding a new contact in the middle of your phone's contact list without scrolling through and rewriting the entire list.

Key Takeaways

Manual insertion in the middle is slow and error-prone.

Doubly linked lists let you insert anywhere efficiently.

This keeps your data organized and easy to update.

Practice

(1/5)
1. What does inserting a node at a specific position in a doubly linked list involve?
easy
A. Adjusting the previous and next pointers of neighboring nodes to include the new node
B. Only changing the head pointer of the list
C. Replacing the node at that position without changing pointers
D. Adding the node at the end regardless of position

Solution

  1. Step 1: Understand doubly linked list structure

    Each node has pointers to both previous and next nodes, so insertion requires updating these pointers.
  2. Step 2: Insert node at specific position

    We must update the previous node's next pointer and the next node's previous pointer to point to the new node.
  3. Final Answer:

    Adjusting the previous and next pointers of neighboring nodes to include the new node -> Option A
  4. Quick Check:

    Pointer updates = Adjust neighbors [OK]
Hint: Remember to update both previous and next pointers [OK]
Common Mistakes:
  • Only updating one pointer leads to broken links
  • Ignoring the previous pointer in insertion
  • Replacing nodes instead of inserting
2. Which of the following TypeScript code snippets correctly declares a node class for a doubly linked list?
easy
A. class Node { value: number; next: Node | null; constructor(value: number) { this.value = value; this.next = null; } }
B. class Node { value: number; next: Node; prev: Node; constructor(value: number) { this.value = value; } }
C. class Node { val: number; next: Node | null; constructor(val: number) { this.val = val; this.next = null; } }
D. class Node { value: number; next: Node | null; prev: Node | null; constructor(value: number) { this.value = value; this.next = null; this.prev = null; } }

Solution

  1. Step 1: Check for previous and next pointers

    A doubly linked list node must have both next and prev pointers, which can be null.
  2. Step 2: Verify constructor initializes all properties

    class Node { value: number; next: Node | null; prev: Node | null; constructor(value: number) { this.value = value; this.next = null; this.prev = null; } } initializes value, next, and prev correctly with proper types.
  3. Final Answer:

    class Node { value: number; next: Node | null; prev: Node | null; constructor(value: number) { this.value = value; this.next = null; this.prev = null; } } -> Option D
  4. Quick Check:

    Both pointers initialized = class Node { value: number; next: Node | null; prev: Node | null; constructor(value: number) { this.value = value; this.next = null; this.prev = null; } } [OK]
Hint: Doubly linked nodes need both next and prev pointers [OK]
Common Mistakes:
  • Forgetting to initialize prev pointer
  • Using wrong property names
  • Not allowing null for next or prev
3. Given the doubly linked list 1 <-> 2 <-> 4 and the code below inserting 3 at position 3, what is the list after insertion?
insertAtPosition(head, 3, 3);
Positions start at 1.
medium
A. 1 <-> 2 <-> 3 <-> 4
B. 1 <-> 3 <-> 2 <-> 4
C. 3 <-> 1 <-> 2 <-> 4
D. 1 <-> 2 <-> 4 <-> 3

Solution

  1. Step 1: Identify position 3 in the list

    Positions: 1=1, 2=2, 3=4. We want to insert before node with value 4.
  2. Step 2: Insert node with value 3 at position 3

    Update pointers so 2 points next to 3, 3 points prev to 2 and next to 4, 4 points prev to 3.
  3. Final Answer:

    1 <-> 2 <-> 3 <-> 4 -> Option A
  4. Quick Check:

    Insert at position 3 = 1-2-3-4 [OK]
Hint: Count nodes, insert before node at that position [OK]
Common Mistakes:
  • Inserting after instead of before position
  • Mixing up prev and next pointers
  • Off-by-one errors in position counting
4. What is wrong with this TypeScript code snippet for inserting a node at position 2 in a doubly linked list?
function insertAtPosition(head: Node | null, value: number, position: number): Node | null {
  let newNode = new Node(value);
  if (position === 1) {
    newNode.next = head;
    if (head) head.prev = newNode;
    return newNode;
  }
  let current = head;
  for (let i = 1; i < position - 1; i++) {
    if (!current) return head;
    current = current.next;
  }
  newNode.next = current.next;
  current.next = newNode;
  newNode.prev = current;
  return head;
}
medium
A. Not handling insertion at head
B. Incorrect loop range in for loop
C. Missing update of newNode.next.prev to newNode
D. Not creating new node correctly

Solution

  1. Step 1: Analyze pointer updates after insertion

    After inserting newNode, newNode.next.prev should point back to newNode to maintain doubly links.
  2. Step 2: Identify missing pointer update

    The code misses updating newNode.next.prev = newNode, which breaks backward link from next node.
  3. Final Answer:

    Missing update of newNode.next.prev to newNode -> Option C
  4. Quick Check:

    Update both next and prev pointers [OK]
Hint: Always update newNode.next.prev after insertion [OK]
Common Mistakes:
  • Forgetting to update newNode.next.prev
  • Loop off-by-one errors
  • Not handling empty list insertion
5. You have a doubly linked list representing train cars: Engine <-> Car1 <-> Car2 <-> Caboose. You want to insert a new CarX at position 2. After insertion, what is the correct order of cars?
hard
A. CarX <-> Engine <-> Car1 <-> Car2 <-> Caboose
B. Engine <-> CarX <-> Car1 <-> Car2 <-> Caboose
C. Engine <-> Car1 <-> CarX <-> Car2 <-> Caboose
D. Engine <-> Car1 <-> Car2 <-> Caboose <-> CarX

Solution

  1. Step 1: Identify position 2 in the list

    Positions: 1=Engine, 2=Car1. Insert CarX before Car1 to become new position 2.
  2. Step 2: Insert CarX at position 2

    Update pointers so Engine next points to CarX, CarX prev to Engine, CarX next to Car1, Car1 prev to CarX.
  3. Final Answer:

    Engine <-> CarX <-> Car1 <-> Car2 <-> Caboose -> Option B
  4. Quick Check:

    Insert at position 2 = Engine-CarX-Car1... [OK]
Hint: Insert before node at position to shift others right [OK]
Common Mistakes:
  • Inserting after instead of before position
  • Not updating prev pointers correctly
  • Confusing position indexing starting at 0
Recommended

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