Why Find the Only Non Repeating Element Using XOR in DSA Typescript?

The Big Idea

What if you could find the odd one out instantly without checking every pair?

The Scenario

Imagine you have a box of socks where every sock has a matching pair except one. You want to find that single sock without checking each pair one by one.

The Problem

Manually checking each sock against all others takes a lot of time and can easily lead to mistakes, especially if the box is large. It's slow and tiring to compare every item multiple times.

The Solution

Using XOR, you can quickly find the single sock without comparing pairs. XOR cancels out pairs automatically, leaving only the unique sock at the end.

Before vs After

✗ Before

for (let i = 0; i < arr.length; i++) {
  let count = 0;
  for (let j = 0; j < arr.length; j++) {
    if (arr[i] === arr[j]) count++;
  }
  if (count === 1) return arr[i];
}

✓ After

let result = 0;
for (const num of arr) {
  result ^= num;
}
return result;

What It Enables

This method lets you find the unique item in a list instantly, no matter how big the list is.

Real Life Example

Finding the one defective product in a batch where every other product is identical and perfect.

Key Takeaways

Manual pair checking is slow and error-prone.

XOR operation cancels out duplicates automatically.

Efficiently finds the unique element in linear time.

Practice

1. What does the XOR operation do when applied between two identical numbers?

easy

A. It returns 1

B. It returns the number itself

C. It returns 0

D. It returns the sum of the numbers

Solution

1. Step 1: Understand XOR property for identical numbers

   XOR of a number with itself always results in 0 because bits cancel out.

2. Step 2: Apply XOR to example

   For example, 5 XOR 5 = 0.

3. Final Answer:

   It returns 0 -> Option C

4. Quick Check:

   X XOR X = 0 [OK]

Hint: XOR of same numbers is always zero [OK]

Common Mistakes:

• Thinking XOR returns the number itself
• Confusing XOR with OR or AND
• Assuming XOR sums the numbers

2. Which of the following TypeScript code snippets correctly initializes a variable to zero for XOR operation?

easy

A. let result = 1;

B. let result = 0;

C. let result = null;

D. let result = undefined;

Solution

1. Step 1: Identify correct initial value for XOR

   For XOR operations, starting with 0 is correct because 0 XOR any number returns that number.

2. Step 2: Check code snippets

   Only let result = 0; correctly initializes for XOR accumulation.

3. Final Answer:

   let result = 0; -> Option B

4. Quick Check:

   Initial XOR value = 0 [OK]

Hint: Start XOR with zero to keep numbers unchanged [OK]

Common Mistakes:

• Starting XOR with 1 instead of 0
• Using null or undefined which cause errors
• Not initializing the variable

3. What is the output of the following TypeScript code?

const arr = [2, 3, 2, 4, 3];
let result = 0;
for (const num of arr) {
  result ^= num;
}
console.log(result);

medium

A. 3

B. 0

C. 2

D. 4

Solution

1. Step 1: XOR all elements in the array

   Calculate stepwise: 0 XOR 2 = 2, 2 XOR 3 = 1, 1 XOR 2 = 3, 3 XOR 4 = 7, 7 XOR 3 = 4.

2. Step 2: Identify the non-repeating element

   All repeating numbers cancel out, leaving 4 as the only non-repeating element.

3. Final Answer:

   4 -> Option D

4. Quick Check:

   Result after XOR = 4 [OK]

Hint: XOR all numbers; duplicates cancel out [OK]

Common Mistakes:

• Not XORing all elements
• Confusing output with last element
• Assuming sum instead of XOR

4. Identify the error in this TypeScript code that tries to find the only non-repeating element using XOR:

const arr = [1, 2, 1, 3, 2];
let result;
for (let i = 0; i < arr.length; i++) {
  result ^= arr[i];
}
console.log(result);

medium

A. Variable 'result' is not initialized

B. Loop condition is incorrect

C. XOR operator is used wrongly

D. Array is empty

Solution

1. Step 1: Check variable initialization

   The variable 'result' is declared but not initialized, so it is undefined initially.

2. Step 2: Understand XOR with undefined

   XOR with undefined causes NaN or runtime error; it must start at 0.

3. Final Answer:

   Variable 'result' is not initialized -> Option A

4. Quick Check:

   Initialize result = 0 before XOR loop [OK]

Hint: Always initialize XOR accumulator to zero [OK]

Common Mistakes:

• Forgetting to initialize result
• Assuming undefined XOR number works
• Incorrect loop boundaries

5. Given an array where every element repeats twice except one element which repeats thrice, can XOR alone find the unique element? Why?

const arr = [5, 5, 5, 7, 7, 8, 8];

hard

A. No, XOR fails because it only cancels pairs, not triples

B. Yes, XOR works because duplicates cancel out

C. Yes, but only if array is sorted

D. No, XOR works only for arrays with all unique elements

Solution

1. Step 1: Understand XOR behavior with odd counts

   XOR cancels even appearances (like twice) to 0, but leaves the result of odd appearances (like thrice: x ^ x ^ x = 0, not x).

2. Step 2: Analyze the given array

   5 appears thrice (odd), 7 and 8 twice (even); XOR of all yields 0, so XOR alone cannot find the unique element repeated thrice.

3. Final Answer:

   No, XOR fails because it only cancels pairs, not triples -> Option A

4. Quick Check:

   XOR fails to find element repeated thrice [OK]

Hint: XOR cancels pairs, fails for triples [OK]

Common Mistakes:

• Thinking XOR works for triples
• Believing sorting is required for XOR
• Confusing XOR with requiring exactly one unique