A. It does not update the previous tail's next pointer to newNode
B. It incorrectly sets head to null when queue is empty
C. It creates newNode without value
D. It sets tail to null after enqueue
Solution
Step 1: Analyze enqueue logic
When queue is empty, head and tail should point to newNode.
Step 2: Check linking of nodes
Code sets tail = newNode but does not link old tail's next to newNode, breaking chain.
Final Answer:
It does not update the previous tail's next pointer to newNode -> Option A
Quick Check:
Link old tail's next to newNode [OK]
Hint: Always link old tail's next to new node when enqueueing [OK]
Common Mistakes:
Forgetting to update old tail's next pointer
Not handling empty queue case properly
Setting tail to null accidentally
Creating node without value parameter
5. You have a linked list queue with elements: 5 -> 15 -> 25 -> null. After enqueue(35), what will be the correct linked list representation and tail node value?
hard
A. 5 -> 15 -> 25 -> 35 -> null, tail value = 25
B. 35 -> 5 -> 15 -> 25 -> null, tail value = 25
C. 5 -> 15 -> 25 -> null, tail value = 25
D. 5 -> 15 -> 25 -> 35 -> null, tail value = 35
Solution
Step 1: Understand enqueue effect on queue
Enqueue adds new element at tail, so 35 goes after 25.
Step 2: Update tail pointer
Tail must point to the new last node, which holds 35.
Final Answer:
5 -> 15 -> 25 -> 35 -> null, tail value = 35 -> Option D
Quick Check:
Enqueue adds at tail, tail updates to new node [OK]
Hint: Tail always points to last enqueued node [OK]
Common Mistakes:
Adding new node at head instead of tail
Not updating tail pointer after enqueue
Confusing tail value with head value
Leaving tail pointing to old last node
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