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DSA Typescriptprogramming~5 mins

Delete by Value in Doubly Linked List in DSA Typescript - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a doubly linked list?
A doubly linked list is a chain of nodes where each node has three parts: data, a pointer to the next node, and a pointer to the previous node. This allows moving forward and backward through the list.
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beginner
What does 'delete by value' mean in a doubly linked list?
It means finding the first node that contains the given value and removing it from the list, adjusting the pointers of neighboring nodes to keep the list connected.
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intermediate
Which pointers need to be updated when deleting a node in a doubly linked list?
The previous node's next pointer and the next node's previous pointer must be updated to skip the deleted node.
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intermediate
What special cases must be handled when deleting a node by value in a doubly linked list?
Special cases include deleting the head node, deleting the tail node, and deleting a node in the middle. Also, if the value is not found, no deletion happens.
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advanced
Show the TypeScript code snippet to delete a node by value in a doubly linked list.
class Node {
  data: number;
  next: Node | null = null;
  prev: Node | null = null;
  constructor(data: number) { this.data = data; }
}

class DoublyLinkedList {
  head: Node | null = null;

  deleteByValue(value: number): void {
    let current = this.head;
    while (current) {
      if (current.data === value) {
        if (current.prev) current.prev.next = current.next;
        else this.head = current.next;
        if (current.next) current.next.prev = current.prev;
        break;
      }
      current = current.next;
    }
  }
}
Click to reveal answer
In a doubly linked list, what pointer does each node have besides 'next'?
APrevious
BRandom
CChild
DParent
What happens if you delete the head node in a doubly linked list?
AThe tail pointer moves to the previous node
BThe list becomes empty
CThe head pointer moves to the next node
DNothing changes
If a node to delete is in the middle, which pointers must be updated?
AOnly the next node's previous pointer
BBoth previous node's next and next node's previous pointers
COnly the previous node's next pointer
DNo pointers need updating
What should happen if the value to delete is not found in the list?
ADo nothing
BDelete the last node
CDelete the head node
DDelete a random node
Which of these is NOT a step in deleting a node by value in a doubly linked list?
AAdjust head if needed
BUpdate pointers of neighboring nodes
CFind the node with the value
DCreate a new node with the value
Explain step-by-step how to delete a node by value in a doubly linked list.
Think about how pointers before and after the node change.
You got /6 concepts.
    Describe the special cases to consider when deleting a node by value in a doubly linked list.
    Consider how the list's start and end pointers might change.
    You got /4 concepts.

      Practice

      (1/5)
      1. What happens when you delete a node by value in a doubly linked list?
      easy
      A. All nodes are deleted regardless of value
      B. The node with the matching value is removed and links are updated
      C. Only the first node is deleted no matter the value
      D. The list is reversed instead of deleting

      Solution

      1. Step 1: Identify the node with the given value

        Traverse the list from head to tail to find the node whose value matches the target.
      2. Step 2: Remove the node and update links

        Adjust the previous node's next pointer and the next node's previous pointer to exclude the found node.
      3. Final Answer:

        The node with the matching value is removed and links are updated -> Option B
      4. Quick Check:

        Deleting by value removes matching node [OK]
      Hint: Find node by value, then update previous and next links [OK]
      Common Mistakes:
      • Not updating previous node's next pointer
      • Not updating next node's previous pointer
      • Deleting all nodes instead of one
      2. Which of the following is the correct TypeScript syntax to delete a node by value in a doubly linked list?
      easy
      A. function deleteNode(value) { /* code */ }
      B. removeNode(value: number) => { /* code */ }
      C. deleteNode(value: number): void { /* code */ }
      D. delete node(value: number) { /* code */ }

      Solution

      1. Step 1: Check method declaration syntax in TypeScript class

        Methods inside classes use the syntax methodName(params): returnType { body }.
      2. Step 2: Identify correct syntax for deleteNode method

        deleteNode(value: number): void { /* code */ } uses correct TypeScript method syntax with type annotation and void return.
      3. Final Answer:

        deleteNode(value: number): void { /* code */ } -> Option C
      4. Quick Check:

        TypeScript method syntax = deleteNode(value: number): void { /* code */ } [OK]
      Hint: Use methodName(params): returnType { } inside class [OK]
      Common Mistakes:
      • Using arrow function syntax inside class method
      • Missing type annotations
      • Using invalid keywords like 'delete node'
      3. Given the doubly linked list: 10 <-> 20 <-> 30 <-> 40, what is the list after deleting the node with value 30?
      medium
      A. 10 <-> 20 <-> 40
      B. 10 <-> 30 <-> 40
      C. 20 <-> 30 <-> 40
      D. 10 <-> 20 <-> 30 <-> 40

      Solution

      1. Step 1: Locate node with value 30

        Traverse the list: 10 -> 20 -> 30 found at third node.
      2. Step 2: Remove node 30 and link 20 to 40

        Update 20's next pointer to 40 and 40's previous pointer to 20.
      3. Final Answer:

        10 <-> 20 <-> 40 -> Option A
      4. Quick Check:

        Deleted 30, list links updated [OK]
      Hint: Remove node, link previous and next nodes directly [OK]
      Common Mistakes:
      • Not updating previous node's next pointer
      • Not updating next node's previous pointer
      • Deleting wrong node
      4. What is wrong with this delete function snippet for doubly linked list?
      deleteNode(value: number): void {
        let current = this.head;
        while (current !== null) {
          if (current.value === value) {
            current.prev.next = current.next;
            current.next.prev = current.prev;
            break;
          }
          current = current.next;
        }
      }
      medium
      A. It does not handle deleting the head node correctly
      B. It deletes all nodes with the value instead of one
      C. It uses wrong variable names
      D. It causes infinite loop

      Solution

      1. Step 1: Check handling of head node deletion

        If current is head, current.prev is null, so current.prev.next causes error.
      2. Step 2: Identify missing head update

        Function does not update this.head when deleting the first node, causing broken list.
      3. Final Answer:

        It does not handle deleting the head node correctly -> Option A
      4. Quick Check:

        Head deletion needs special handling [OK]
      Hint: Check if node is head before updating prev pointers [OK]
      Common Mistakes:
      • Not checking if current.prev is null
      • Not updating head pointer when deleting first node
      • Assuming all nodes have prev and next
      5. You have a doubly linked list: 5 <-> 10 <-> 15 <-> 20 <-> 25. You want to delete the node with value 5, then delete the node with value 25. What is the final list?
      hard
      A. 15 <-> 20
      B. 5 <-> 10 <-> 15 <-> 20
      C. 10 <-> 15 <-> 20 <-> 25
      D. 10 <-> 15 <-> 20

      Solution

      1. Step 1: Delete node with value 5 (head node)

        Update head to 10, set 10.prev to null.
      2. Step 2: Delete node with value 25 (tail node)

        Update 20.next to null, removing 25.
      3. Final Answer:

        10 <-> 15 <-> 20 -> Option D
      4. Quick Check:

        Deleted head and tail nodes correctly [OK]
      Hint: Update head or tail pointers when deleting first or last nodes [OK]
      Common Mistakes:
      • Not updating head when deleting first node
      • Not updating tail when deleting last node
      • Breaking links between middle nodes
      Recommended

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