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DSA Rustprogramming~10 mins

Why Trie Exists and What Hash Map Cannot Do for Strings in DSA Rust - Test Your Knowledge

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to insert a character into the Trie node's children.

DSA Rust
node.children.insert([1], TrieNode::new());
Drag options to blanks, or click blank then click option'
Akey
B'a'
C'c'
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using a variable name instead of a character literal.
Inserting a value instead of a key.
2fill in blank
medium

Complete the code to check if the Trie node has a child for the given character.

DSA Rust
if node.children.contains_key(&[1]) {
Drag options to blanks, or click blank then click option'
Ach
Bkey
Cvalue
Dnode
Attempts:
3 left
💡 Hint
Common Mistakes
Using the wrong variable name.
Not using a reference (&) when checking the key.
3fill in blank
hard

Fix the error in the code to mark the end of a word in the Trie.

DSA Rust
node.is_end_of_word = [1];
Drag options to blanks, or click blank then click option'
Afalse
Btrue
CNone
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Setting the flag to false or zero.
Using None instead of a boolean.
4fill in blank
hard

Fill both blanks to complete the loop that traverses the Trie for each character in the word.

DSA Rust
for [1] in word.chars() {
    if !node.children.contains_key(&[2]) {
        return false;
    }
    node = node.children.get_mut(&ch).unwrap();
}
Drag options to blanks, or click blank then click option'
Ach
Bkey
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using different variable names for loop and key check.
Using incorrect variable names.
5fill in blank
hard

Fill all three blanks to complete the function that inserts a word into the Trie.

DSA Rust
fn insert(&mut self, word: &str) {
    let mut node = &mut self.root;
    for [1] in word.chars() {
        node = node.children.entry([2]).or_insert(TrieNode::new());
    }
    node.[3] = true;
}
Drag options to blanks, or click blank then click option'
Ach
Cis_end_of_word
Dchildren
Attempts:
3 left
💡 Hint
Common Mistakes
Using different names for loop variable and key.
Forgetting to mark the end of the word.

Practice

(1/5)
1. Why do we use a Trie data structure instead of a Hash Map for storing many strings?
easy
A. Because Hash Map can only store numbers, not strings
B. Because Hash Map uses less memory than Trie
C. Because Trie stores strings as keys directly without splitting
D. Because Trie can efficiently find all strings with a common prefix

Solution

  1. Step 1: Understand Trie prefix search ability

    Trie stores strings character by character, allowing quick prefix-based searches.
  2. Step 2: Compare with Hash Map capabilities

    Hash Map stores whole strings as keys but cannot efficiently find all keys sharing a prefix.
  3. Final Answer:

    Because Trie can efficiently find all strings with a common prefix -> Option D
  4. Quick Check:

    Trie = prefix search [OK]
Hint: Trie excels at prefix search, Hash Map does not [OK]
Common Mistakes:
  • Thinking Hash Map can do prefix search efficiently
  • Confusing memory usage advantages
  • Believing Trie stores whole strings as keys
2. Which of the following is the correct way to declare a Trie node struct in Rust for lowercase English letters?
easy
A. struct TrieNode { children: [Option; 26], is_end: bool }
B. struct TrieNode { children: Vec<TrieNode>, is_end: bool }
C. struct TrieNode { children: HashMap, is_end: bool }
D. struct TrieNode { children: [TrieNode; 26], is_end: bool }

Solution

  1. Step 1: Understand Rust ownership and recursive types

    Recursive structs need Box to allocate on heap to avoid infinite size.
  2. Step 2: Check array size and type

    Array of 26 Option fits lowercase letters and allows empty children.
  3. Final Answer:

    struct TrieNode { children: [Option; 26], is_end: bool } -> Option A
  4. Quick Check:

    Use Box and Option for recursive children [OK]
Hint: Use Box and Option for recursive children array [OK]
Common Mistakes:
  • Using Vec without Box causes infinite size error
  • Using HashMap instead of fixed array for fixed alphabet
  • Using array of TrieNode directly without Box
3. What will be the output of the following Rust code snippet using a Trie to insert and search strings?
let mut trie = Trie::new();
trie.insert("cat");
trie.insert("car");
trie.insert("dog");
println!("{}", trie.starts_with("ca"));
println!("{}", trie.starts_with("do"));
println!("{}", trie.starts_with("bat"));
medium
A. true false false
B. false true false
C. true true false
D. false false true

Solution

  1. Step 1: Insert strings into Trie

    Strings "cat", "car", and "dog" are inserted, so prefixes "ca" and "do" exist.
  2. Step 2: Check starts_with queries

    "ca" matches "cat" and "car" (true), "do" matches "dog" (true), "bat" not inserted (false).
  3. Final Answer:

    true true false -> Option C
  4. Quick Check:

    Prefix search matches inserted prefixes [OK]
Hint: Inserted prefixes return true on starts_with [OK]
Common Mistakes:
  • Assuming starts_with returns true only for full words
  • Confusing starts_with with exact search
  • Mixing up true/false outputs
4. Given this Rust Trie insert function snippet, what is the bug?
fn insert(&mut self, word: &str) {
  let mut node = &mut self.root;
  for c in word.chars() {
    let index = (c as usize) - ('a' as usize);
    if node.children[index].is_none() {
      node.children[index] = Some(Box::new(TrieNode::new()));
    }
    node = &mut node.children[index].as_mut().unwrap();
  }
  node.is_end = true;
}
medium
A. The index calculation assumes only lowercase letters without validation
B. The unwrap() call can cause a panic if children[index] is None
C. The loop should iterate over bytes, not chars
D. The is_end flag is set before the loop

Solution

  1. Step 1: Analyze index calculation

    Index is calculated by subtracting 'a' from character code, assuming lowercase letters only.
  2. Step 2: Identify missing validation

    No check if character is lowercase a-z, so uppercase or other chars cause wrong index or panic.
  3. Final Answer:

    The index calculation assumes only lowercase letters without validation -> Option A
  4. Quick Check:

    Index must be validated for safe access [OK]
Hint: Check character range before index calculation [OK]
Common Mistakes:
  • Ignoring character validation causes panic
  • Thinking unwrap() is unsafe here (it's safe after check)
  • Confusing iteration over chars vs bytes
5. You want to find all words in a dictionary that start with a given prefix efficiently. Why is a Trie better than a Hash Map for this task, and how does it achieve this?
hard
A. Trie uses less memory than Hash Map for storing strings; Hash Map stores full strings wasting space
B. Trie stores words character by character, enabling fast prefix traversal; Hash Map cannot efficiently list keys by prefix
C. Trie hashes prefixes for quick lookup; Hash Map hashes full strings only
D. Trie sorts all words internally; Hash Map stores words unsorted

Solution

  1. Step 1: Understand Trie's character-by-character storage

    Trie nodes represent characters, so traversing nodes follows prefix paths quickly.
  2. Step 2: Compare with Hash Map key storage

    Hash Map keys are full strings; no structure to find all keys sharing a prefix efficiently.
  3. Step 3: Explain prefix search advantage

    Trie traversal to prefix node then explores subtree for all matching words efficiently.
  4. Final Answer:

    Trie stores words character by character, enabling fast prefix traversal; Hash Map cannot efficiently list keys by prefix -> Option B
  5. Quick Check:

    Trie = prefix traversal, Hash Map = no prefix listing [OK]
Hint: Trie traverses prefix nodes; Hash Map cannot list by prefix [OK]
Common Mistakes:
  • Assuming Hash Map can list keys by prefix efficiently
  • Confusing hashing with prefix traversal
  • Thinking Trie sorts words internally
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