Radix Sort Algorithm in DSA Rust - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to get the maximum value in the array for Radix Sort.

DSA Rust

let max = *arr.iter().[1]().unwrap();

Drag options to blanks, or click blank then click option'

Amax_by_key

Bmax

Cmax_by

Dmin

Attempts:

3 left

💡 Hint

Common Mistakes

Using min instead of max.

Using max_by_key or max_by which require additional arguments.

We use iter().max() to find the maximum value in the array, which is needed to know the number of digits.

2fill in blank

medium

Complete the code to extract the digit at the current place value.

DSA Rust

let digit = (num / [1]) % 10;

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A10

B1

C100

Dplace

Attempts:

3 left

💡 Hint

Common Mistakes

Using a fixed number like 10 instead of the variable place.

Using modulo before division.

We divide the number by the current place value (place) to shift the digit to the units place, then take modulo 10 to get that digit.

3fill in blank

hard

Fix the error in the counting array initialization for digits 0-9.

DSA Rust

let mut count = vec![0; [1]];

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A10

B9

C11

D8

Attempts:

3 left

💡 Hint

Common Mistakes

Using 9 instead of 10, causing index errors.

Using 11 which wastes space.

We need a count array of size 10 to count digits 0 through 9.

4fill in blank

hard

Fill both blanks to update the count array to hold cumulative counts.

DSA Rust

for i in 1..[1] {
    count[i] += count[[2]];
}

Drag options to blanks, or click blank then click option'

A10

Bi - 1

Ci + 1

D9

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong loop range causing index out of bounds.

Adding count[i+1] instead of count[i-1].

We loop from 1 to 10 (exclusive) and add the previous count to the current to get cumulative counts.

5fill in blank

hard

Fill all three blanks to place elements into output array in stable order.

DSA Rust

for &num in arr.iter().rev() {
    let digit = (num / [1]) % 10;
    output[count[digit] [2]] = num;
    count[digit] [3];
}

Drag options to blanks, or click blank then click option'

Aplace

B-= 1

C- 1

D+= 1

Attempts:

3 left

💡 Hint

Common Mistakes

Using += 1 instead of -= 1 causing wrong placement.

Not subtracting 1 from count[digit] index.

We calculate the digit using place, place the number at count[digit] - 1 index, then decrement count[digit] by 1.

Practice

1. What is the main idea behind the Radix Sort Algorithm?

easy

A. Sort numbers by swapping adjacent elements repeatedly

B. Sort numbers by comparing each pair directly

C. Sort numbers by dividing them into two halves recursively

D. Sort numbers digit by digit starting from the least significant digit

Solution

1. Step 1: Understand Radix Sort approach

   Radix sort sorts numbers by processing each digit separately, starting from the least significant digit (rightmost).

2. Step 2: Compare with other sorting methods

   Unlike comparison-based sorts, radix sort uses digit positions to sort without direct element comparisons.

3. Final Answer:

   Sort numbers digit by digit starting from the least significant digit -> Option D

4. Quick Check:

   Radix sort = digit-by-digit sorting [OK]

Hint: Radix sort processes digits from right to left [OK]

Common Mistakes:

• Thinking radix sort compares elements directly
• Assuming it sorts by dividing arrays recursively
• Confusing it with bubble or quick sort methods

2. Which of the following Rust code snippets correctly initializes a vector to hold buckets for digits 0 to 9 in radix sort?

easy

A. let mut buckets: Vec = vec![Vec::new(); 10];

B. let buckets = Vec::with_capacity(10);

C. let buckets: Vec<i32> = vec![0; 10];

D. let mut buckets = vec![0; 10];

Solution

1. Step 1: Understand bucket structure needed

   Radix sort uses buckets as vectors of vectors to hold numbers for each digit (0-9).

2. Step 2: Check Rust syntax for initializing vector of vectors

   Using vec![Vec::new(); 10] creates 10 empty vectors, one for each digit bucket.

3. Final Answer:

   let mut buckets: Vec = vec![Vec::new(); 10]; -> Option A

4. Quick Check:

   Vector of vectors for buckets = let mut buckets: Vec = vec![Vec::new(); 10]; [OK]

Hint: Buckets need vectors inside a vector, not just integers [OK]

Common Mistakes:

• Using Vec<i32> instead of Vec for buckets
• Using with_capacity without initializing inner vectors
• Initializing buckets as integers instead of vectors

3. What will be the output of the following Rust code snippet implementing one pass of radix sort on the least significant digit?

let arr = vec![170, 45, 75, 90, 802, 24, 2, 66];
let mut buckets: Vec = vec![Vec::new(); 10];
for &num in &arr {
    let digit = num % 10;
    buckets[digit as usize].push(num);
}
let mut result = Vec::new();
for bucket in buckets {
    for num in bucket {
        result.push(num);
    }
}
println!("{:?}", result);

medium

A. [2, 802, 24, 45, 75, 66, 170, 90]

B. [170, 90, 802, 2, 24, 45, 75, 66]

C. [170, 802, 2, 24, 45, 75, 90, 66]

D. [802, 2, 24, 45, 75, 66, 170, 90]

Solution

1. Step 1: Calculate least significant digit for each number

   Digits: 170%10=0, 45%10=5, 75%10=5, 90%10=0, 802%10=2, 24%10=4, 2%10=2, 66%10=6.

2. Step 2: Place numbers in buckets and flatten

   Buckets: 0->[170,90], 2->[802,2], 4->[24], 5->[45,75], 6->[66]. Flattening in order: [170, 90, 802, 2, 24, 45, 75, 66].

3. Final Answer:

   [170, 90, 802, 2, 24, 45, 75, 66] -> Option B

4. Quick Check:

   Sorted by least digit = [170, 90, 802, 2, 24, 45, 75, 66] [OK]

Hint: Check digit % 10 and group accordingly [OK]

Common Mistakes:

• Mixing up digit extraction with division
• Not preserving order within buckets
• Incorrectly flattening buckets

4. Identify the bug in this Rust code snippet for one pass of radix sort and choose the fix:

let arr = vec![170, 45, 75];
let mut buckets: Vec = vec![Vec::new(); 10];
for num in arr {
    let digit = num / 10 % 10;
    buckets[digit].push(num);
}

medium

A. Change buckets[digit] to buckets[digit as usize]

B. Change num / 10 % 10 to num % 10

C. Initialize buckets with vec![0; 10] instead of vectors

D. Use for &num in &arr instead of for num in arr

Solution

1. Step 1: Identify type mismatch in indexing

   Variable digit is an integer but Rust requires usize for vector indexing.

2. Step 2: Fix by casting digit to usize

   Use buckets[digit as usize] to correctly index the vector.

3. Final Answer:

   Change buckets[digit] to buckets[digit as usize] -> Option A

4. Quick Check:

   Vector index must be usize = Change buckets[digit] to buckets[digit as usize] [OK]

Hint: Vector indices in Rust must be usize type [OK]

Common Mistakes:

• Using integer directly as vector index without casting
• Changing digit calculation unnecessarily
• Incorrect bucket initialization

5. Given the Rust function below that performs radix sort on a vector of positive integers, what will be the final sorted vector?

fn radix_sort(mut arr: Vec<i32>) -> Vec<i32> {
    let max = *arr.iter().max().unwrap();
    let mut exp = 1;
    while max / exp > 0 {
        let mut buckets: Vec = vec![Vec::new(); 10];
        for &num in &arr {
            let digit = (num / exp) % 10;
            buckets[digit as usize].push(num);
        }
        arr.clear();
        for bucket in buckets {
            for num in bucket {
                arr.push(num);
            }
        }
        exp *= 10;
    }
    arr
}

let input = vec![329, 457, 657, 839, 436, 720, 355];
let sorted = radix_sort(input);
println!("{:?}", sorted);

hard

A. [329, 436, 355, 457, 657, 720, 839]

B. [839, 720, 657, 457, 436, 355, 329]

C. [329, 355, 436, 457, 657, 720, 839]

D. [355, 329, 436, 457, 657, 720, 839]

Solution

1. Step 1: Understand the radix sort passes

   The function sorts by digits starting from least significant (units), then tens, then hundreds until max digit processed.

2. Step 2: Trace sorting steps on input

   After all passes, the vector is sorted ascending: [329, 355, 436, 457, 657, 720, 839].

3. Final Answer:

   [329, 355, 436, 457, 657, 720, 839] -> Option C

4. Quick Check:

   Radix sort final output = sorted ascending [OK]

Hint: Radix sort outputs fully sorted list ascending [OK]

Common Mistakes:

• Confusing order as descending
• Missing clearing array before collecting buckets
• Not multiplying exp by 10 each iteration