What if you could find any word starting with your letters instantly, no matter how big the list?
Why Prefix Search Using Trie in DSA Rust?
Imagine you have a huge phone book and you want to find all contacts starting with "Sam". You try to look through every name one by one, which takes forever.
Searching each name manually is slow and tiring. You might miss some names or get confused. It's hard to keep track of all possibilities without a clear system.
A Trie is like a smart tree that organizes words by their letters. It lets you quickly jump to all names starting with "Sam" without checking every single name.
let mut results = Vec::new(); for name in contacts.iter() { if name.starts_with("Sam") { results.push(name.clone()); } }
let results = trie.search_prefix("Sam");It makes searching for words by their beginnings super fast and easy, even with thousands of entries.
When you type in a search bar on your phone, the suggestions appear instantly because the system uses a Trie to find words starting with what you typed.
Manual search is slow and error-prone for prefix queries.
Trie organizes words by letters for quick prefix lookup.
Using Trie makes prefix search efficient and scalable.
Practice
Trie data structure in prefix search?Solution
Step 1: Understand Trie usage
A Trie stores strings in a tree-like structure where each node represents a character, making prefix searches efficient.Step 2: Identify prefix search goal
Prefix search requires finding all words starting with a given prefix, which Trie supports directly by traversing nodes.Final Answer:
To efficiently find all words that start with a given prefix -> Option AQuick Check:
Trie = prefix search efficiency [OK]
- Confusing Trie with sorting data structure
- Thinking Trie is for numeric operations
- Assuming Trie stores full words only at root
Solution
Step 1: Check children type for TrieNode
Children must map characters to child nodes, so HashMap is correct for recursive structure without size issues.Step 2: Validate other options
Vec<char> or String cannot map characters to nodes; i32 is invalid for children.Final Answer:
struct TrieNode { children: HashMap, is_end: bool } -> Option AQuick Check:
Children map chars to nodes = struct TrieNode { children: HashMap, is_end: bool } [OK]
- Using Vec<char> instead of mapping to nodes
- Using String for children instead of node references
- Using primitive types like i32 for children
let mut trie = Trie::new();
trie.insert("cat");
trie.insert("car");
trie.insert("dog");
let result = trie.starts_with("ca");
println!("{:?}", result);
What will be printed?Solution
Step 1: Insert words into Trie
Words "cat", "car", and "dog" are inserted. "cat" and "car" share prefix "ca".Step 2: Search for prefix "ca"
Searching prefix "ca" returns all words starting with "ca", which are "cat" and "car".Final Answer:
["cat", "car"] -> Option BQuick Check:
Prefix "ca" matches cat, car [OK]
- Including words without the prefix
- Returning empty list if prefix exists
- Confusing prefix search with full word search
fn starts_with(&self, prefix: &str) -> bool {
let mut node = &self.root;
for ch in prefix.chars() {
if !node.children.contains_key(&ch) {
return false;
}
node = node.children.get(&ch).unwrap();
}
true
}
What is the main issue with this code snippet?Solution
Step 1: Analyze function purpose
This implements prefix existence check (returns bool).Step 2: Identify mismatch for prefix search
Prefix search requires returning all words with the prefix (e.g. Vec<String>), not just bool.Final Answer:
Incorrect return type for starts_with function -> Option DQuick Check:
Prefix search needs Vec<String> not bool [OK]
- Confusing prefix existence (bool) with full prefix search (list)
- Assuming unwrap() causes runtime error here
- Forgetting Rust borrow checker rules
Solution
Step 1: Understand prefix search with limit
We want to find all words starting with prefix but stop after 2 matches to save time.Step 2: Modify DFS traversal
During DFS from prefix node, keep count of collected words and stop recursion once 2 words are found.Step 3: Evaluate other options
Storing only 2 words per node loses data; filtering after search is inefficient; returning one word is incomplete.Final Answer:
Modify DFS traversal to stop collecting words after 2 matches -> Option CQuick Check:
Limit results by stopping DFS early [OK]
- Limiting stored words per node loses data
- Filtering after full search wastes time
- Returning only one word ignores requirement
Ready to prove it?
Pass the test and this pattern moves unknown
