Longest Word in Dictionary Using Trie in DSA Rust - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a Trie data structure?

A Trie is a tree-like data structure that stores a dynamic set of strings, where each node represents a character. It is used to efficiently search for words or prefixes.

intermediate

How does a Trie help in finding the longest word in a dictionary?

A Trie allows checking if all prefixes of a word exist in the dictionary by traversing nodes. This helps find the longest word where every prefix is also a valid word.

intermediate

In the context of the longest word problem, why do we only continue traversal if the current node marks the end of a word?

Because the problem requires that all prefixes of the word must be valid words. If a node is not an end of a word, it means the prefix is missing, so we stop.

beginner

What is the time complexity of inserting a word of length n into a Trie?

The time complexity is O(n), where n is the length of the word, because we insert one node per character.

beginner

What is the output format when printing the longest word found using a Trie?

The output is the longest word as a string where all prefixes are valid words. For example: "apple".

What does each node in a Trie represent?

A A character of a word

B A whole word

C A number

D A sentence

Each node in a Trie represents a single character of a word.

Why do we check if a node is the end of a word when finding the longest word in a Trie?

A To delete the word

B To count the number of words

C To ensure all prefixes are valid words

D To find the shortest word

We check if a node is the end of a word to ensure all prefixes exist as valid words.

What is the main advantage of using a Trie for dictionary word problems?

A Sorting words alphabetically

B Compressing data

C Storing numbers

D Fast prefix search

Trie allows fast prefix search which is useful for dictionary word problems.

If a word is "apple", which prefixes must exist in the Trie for it to be considered the longest word?

A "a", "ap", "app", "appl", "apple"

B "apple" only

C "ap", "app", "apple" only

D "a", "apple" only

All prefixes "a", "ap", "app", "appl", and "apple" must be valid words.

What is the worst-case time complexity to find the longest word in a Trie with m words and maximum length n?

A O(m)

B O(m * n)

C O(n^2)

D O(m + n)

We may need to check all words and their prefixes, leading to O(m * n) complexity.

Explain how a Trie is used to find the longest word in a dictionary where all prefixes are valid words.

Think about checking prefixes step-by-step in the Trie.

Describe the steps to insert words into a Trie and then find the longest word with all prefixes present.

Focus on insertion and traversal logic.

Practice

1. What is the main purpose of using a Trie data structure when finding the longest word in a dictionary?

easy

A. To reverse the words quickly

B. To sort words alphabetically

C. To count the total number of words

D. To efficiently store and search words by their prefixes

Solution

1. Step 1: Understand Trie usage

   A Trie stores words by their prefixes, allowing quick prefix checks.

2. Step 2: Relate to longest word search

   Finding the longest word with all prefixes present is easier with Trie traversal.

3. Final Answer:

   To efficiently store and search words by their prefixes -> Option D

4. Quick Check:

   Trie = prefix-based search [OK]

Hint: Trie is all about prefixes and fast prefix lookups [OK]

Common Mistakes:

• Confusing Trie with sorting structure
• Thinking Trie counts words only
• Assuming Trie reverses words

2. Which of the following Rust code snippets correctly defines a Trie node struct for storing children nodes?

easy

A. struct TrieNode { children: [Option; 26] }

B. struct TrieNode { children: HashMap }

C. struct TrieNode { children: Vec> }

D. struct TrieNode { children: Vec<TrieNode> }

Solution

1. Step 1: Understand Trie children representation

   Each node has fixed 26 children for letters a-z, stored as array of Options.

2. Step 2: Check Rust syntax correctness

   Option allows nullable child nodes; array size 26 matches alphabet.

3. Final Answer:

   struct TrieNode { children: [Option; 26] } -> Option A

4. Quick Check:

   Fixed-size array with Option<Box> = correct Trie node [OK]

Hint: Use fixed-size array with Option<Box> for children in Rust Trie [OK]

Common Mistakes:

• Using Vec without fixed size wastes memory
• Using HashMap without Box causes ownership errors
• Not wrapping children in Option causes panic

3. Given the following Rust code snippet that inserts words into a Trie and finds the longest word with all prefixes present, what will be the printed output?

let words = vec!["a", "app", "ap", "apply", "apple"];
let longest = find_longest_word(words);
println!("{}", longest);

Assume find_longest_word uses a Trie to find the longest word where every prefix is also a word.

medium

A. "apple"

B. "apply"

C. "app"

D. "ap"

Solution

1. Step 1: Check prefixes for each word

   "apple" prefixes: a, ap, app, appl; "appl" missing, so invalid.
   "apply" prefixes: a, ap, app, appl; "appl" missing, invalid.
   "app" prefixes: a, ap, app; all present.
   "ap" prefixes: a, ap; all present.

2. Step 2: Find longest valid word

   "app" is longest word with all prefixes present.

3. Final Answer:

   "app" -> Option C

4. Quick Check:

   Longest word with all prefixes = "app" [OK]

Hint: Check all prefixes exist before choosing longest word [OK]

Common Mistakes:

• Assuming 'apple' or 'apply' are valid without all prefixes
• Ignoring prefix 'appl' missing
• Choosing shortest word instead of longest

4. The following Rust function attempts to insert words into a Trie and find the longest word with all prefixes present. It compiles but returns an empty string. What is the likely bug?

fn find_longest_word(words: Vec<&str>) -> String {
    let mut trie = Trie::new();
    for word in &words {
        trie.insert(word);
    }
    trie.search_longest_word()
}

// Trie methods:
// insert(&self, word: &str)
// search_longest_word(&self) -> String

medium

A. The function should return &str, not String

B. The insert method should take &mut self, not &self

C. Words vector should be mutable

D. The search_longest_word method should take &mut self, not &self

Solution

1. Step 1: Analyze method signatures

   Inserting words modifies Trie, so insert must take mutable reference &mut self.

2. Step 2: Identify compilation vs runtime issue

   Code compiles but insert called with &self means no actual insertion happens, so Trie remains empty.

3. Final Answer:

   The insert method should take &mut self, not &self -> Option B

4. Quick Check:

   Mutable insert needed for Trie modification [OK]

Hint: Insert modifies Trie; needs &mut self in Rust [OK]

Common Mistakes:

• Thinking search needs mutable reference
• Making words vector mutable unnecessarily
• Returning wrong type String vs &str

5. You have a list of words: ["a", "banana", "app", "appl", "ap", "apply", "apple"]. Using a Trie, which word will be returned as the longest word where every prefix is also a word? Explain why the word "banana" is not chosen.

hard

A. "apple" because "banana" prefixes are missing

B. "apply" because it is longer than "apple"

C. "appl" because "appl" is a prefix of "apple" and "apply"

D. "apple" because all its prefixes exist

Solution

1. Step 1: Check prefixes of each candidate word

   "apple" prefixes: a, ap, app, appl, apple - all present.
   "apply" prefixes: a, ap, app, appl, apply - all present.
   "banana" prefixes: b, ba, ban, bana, banan, banana - none except 'b' likely missing.

2. Step 2: Understand why "banana" is excluded

   Since prefixes like 'b', 'ba' are not in the word list, "banana" is invalid.
   Between "apple" and "apply", both valid, but "apple" is chosen (depends on lex order or implementation).

3. Final Answer:

   "apple" because "banana" prefixes are missing -> Option A

4. Quick Check:

   Missing prefixes exclude "banana" [OK]

Hint: Check all prefixes exist; missing prefixes exclude word [OK]

Common Mistakes:

• Assuming "banana" is valid without prefixes
• Confusing "apply" as longer than "apple"
• Ignoring prefix checks for all words