Hash Map vs Array vs Linked List for Lookup in DSA Rust - Interactive Comparison Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a vector and access its first element.

DSA Rust

let numbers = vec![10, 20, 30];
let first = numbers[1]0;
println!("{}", first);

Drag options to blanks, or click blank then click option'

A[

B(

C{

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using parentheses or curly braces instead of square brackets for indexing.

Vectors in Rust use square brackets [] to access elements by index.

2fill in blank

medium

Complete the code to insert a key-value pair into a HashMap.

DSA Rust

use std::collections::HashMap;
let mut map = HashMap::new();
map.[1]("apple", 3);
println!("{:?}", map);

Drag options to blanks, or click blank then click option'

Ainsert

Badd

Cpush

Dset

Attempts:

3 left

💡 Hint

Common Mistakes

Using push which is for vectors, not HashMaps.

The insert method adds a key-value pair to a HashMap in Rust.

3fill in blank

hard

Fix the error in the linked list traversal to print all values.

DSA Rust

struct Node {
    value: i32,
    next: Option<Box<Node>>,
};

fn print_list(mut current: &Option<Box<Node>>) {
    while let Some(node) = current.as_ref() {
        println!("{}", node.value);
        current = &node.[1];
    }
}

Drag options to blanks, or click blank then click option'

Ahead

Bvalue

Cnext

Dprev

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to access value or a non-existent prev field.

To move to the next node in a linked list, access the next field.

4fill in blank

hard

Fill both blanks to create a HashMap from a vector of keys and assign values.

DSA Rust

use std::collections::HashMap;
let keys = vec!["a", "b", "c"];
let mut map = HashMap::new();
for key in keys {
    map.[1](key, key.[2]());
}

Drag options to blanks, or click blank then click option'

Ainsert

Bto_string

Cclone

Dpush

Attempts:

3 left

💡 Hint

Common Mistakes

Using push instead of insert, or clone instead of to_string().

Use insert to add key-value pairs, and to_string() to convert &str to String.

5fill in blank

hard

Fill all three blanks to filter an array and collect values into a vector.

DSA Rust

let numbers = [1, 2, 3, 4, 5];
let evens: Vec<i32> = numbers.iter()
    .[1](|&x| x [2] 2 == 0)
    .[3](|&x| x)
    .collect();
println!("{:?}", evens);

Drag options to blanks, or click blank then click option'

Afilter

B%

Ccopied

Dmap

Attempts:

3 left

💡 Hint

Common Mistakes

Using copied instead of map, or wrong operator for modulo.

Use filter to select even numbers, % for modulo, and map to transform references.

Practice

1. Which data structure provides the fastest average lookup time for a key-value pair in Rust?

easy

A. Array

B. Vector

C. Linked List

D. Hash Map

Solution

1. Step 1: Understand lookup times for data structures

   Hash Map uses hashing to find keys quickly, usually in constant time O(1).

2. Step 2: Compare with Array and Linked List

   Array and Linked List require searching elements linearly, which is slower (O(n)).

3. Final Answer:

   Hash Map -> Option D

4. Quick Check:

   Fastest lookup = Hash Map [OK]

Hint: Hash Map uses hashing for O(1) lookup, arrays and lists are slower [OK]

Common Mistakes:

• Thinking arrays have O(1) lookup for keys (only for indices)
• Confusing linked list traversal with direct access
• Assuming vector is same as hash map for lookup

2. Which Rust syntax correctly declares a mutable HashMap named map with String keys and i32 values?

easy

A. let map: HashMap = HashMap::new();

B. let mut map: HashMap = HashMap::new();

C. let mut map = HashMap::new();

D. let map = HashMap::new();

Solution

1. Step 1: Check correct syntax for mutable HashMap declaration

   In Rust, let mut declares a mutable variable. The type is HashMap<String, i32>. The constructor is HashMap::new().

2. Step 2: Identify errors in other options

   let map = HashMap::new(); misses mut. let mut map = HashMap::new(); has wrong generic syntax. let map: HashMap = HashMap::new(); swaps key and value types.

3. Final Answer:

   let mut map: HashMap = HashMap::new(); -> Option B

4. Quick Check:

   Mutable HashMap syntax = let mut map: HashMap = HashMap::new(); [OK]

Hint: Use let mut with HashMap::new() and correct generics [OK]

Common Mistakes:

• Forgetting mut keyword for mutable map
• Wrong generic syntax with new()
• Swapping key and value types

3. What is the output of this Rust code snippet?

use std::collections::HashMap;

fn main() {
    let mut map = HashMap::new();
    map.insert("apple", 3);
    map.insert("banana", 2);
    map.insert("orange", 5);

    let lookup = map.get("banana");
    println!("{:?}", lookup);
}

medium

A. None

B. 2

C. Some(2)

D. banana

Solution

1. Step 1: Understand HashMap get method return type

   The get method returns an Option type: Some(&value) if key exists, else None.

2. Step 2: Check if key "banana" exists and its value

   Key "banana" exists with value 2, so get("banana") returns Some(&2). Printing with {:?} shows Some(2).

3. Final Answer:

   Some(2) -> Option C

4. Quick Check:

   HashMap get returns Option = Some(2) [OK]

Hint: HashMap get returns Option; Some(value) if found, else None [OK]

Common Mistakes:

• Expecting direct value instead of Option
• Confusing None with Some
• Printing key instead of value

4. Identify the error in this Rust code that tries to find a value in a linked list:

struct Node {
    value: i32,
    next: Option,
}

fn find(head: &Option, target: i32) -> bool {
    let mut current = head;
    while current.is_some() {
        if current.as_ref().unwrap().value == target {
            return true;
        }
        current = current.unwrap().next;
    }
    false
}

medium

A. Using unwrap() twice causes ownership error

B. Missing mutable keyword for current

C. Incorrect comparison operator in if statement

D. next field should be a reference, not Box

Solution

1. Step 1: Analyze ownership in while loop

   Calling unwrap() on current moves ownership, so current cannot be used again.

2. Step 2: Identify why unwrap() causes error

   Using unwrap() twice consumes current, causing ownership error. Instead, use references or pattern matching.

3. Final Answer:

   Using unwrap() twice causes ownership error -> Option A

4. Quick Check:

   Ownership error due to unwrap() usage [OK]

Hint: unwrap() moves ownership; use references to avoid errors [OK]

Common Mistakes:

• Ignoring ownership rules with unwrap()
• Thinking mutable needed for current here
• Confusing Box with reference types

5. You need to store a large collection of user IDs (integers) and quickly check if a user ID exists. Which data structure is best and why? Choose the best option considering lookup speed and memory efficiency.

hard

A. Hash Map, because it offers average constant time lookup for keys

B. Array, because it provides constant time lookup for any integer key

C. Linked List, because it uses less memory and is easy to implement

D. Vector, because it automatically resizes and supports fast lookup

Solution

1. Step 1: Consider lookup speed for large collections

   Linked List has O(n) lookup, which is slow. Array lookup by index is O(1), but only if keys are indices, not arbitrary integers.

2. Step 2: Evaluate Hash Map and Vector

   Hash Map provides average O(1) lookup for arbitrary keys like user IDs. Vector lookup by index is O(1), but user IDs may not be continuous indices.

3. Final Answer:

   Hash Map, because it offers average constant time lookup for keys -> Option A

4. Quick Check:

   Best lookup for arbitrary keys = Hash Map [OK]

Hint: Use Hash Map for fast lookup of arbitrary keys like user IDs [OK]

Common Mistakes:

• Assuming array lookup works for arbitrary keys
• Choosing linked list for speed
• Confusing vector with hash map for key lookup