Autocomplete System with Trie in DSA Python - Time & Space Complexity

Time Complexity: Autocomplete System with Trie

O(n)

Understanding Time Complexity

We want to understand how fast an autocomplete system using a trie can find suggestions.

How does the time to find words grow as we add more words or type more letters?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

class TrieNode:
    def __init__(self):
        self.children = {}
        self.is_word = False

class Trie:
    def __init__(self):
        self.root = TrieNode()

    def insert(self, word):
        node = self.root
        for char in word:
            if char not in node.children:
                node.children[char] = TrieNode()
            node = node.children[char]
        node.is_word = True

    def search_prefix(self, prefix):
        node = self.root
        for char in prefix:
            if char not in node.children:
                return None
            node = node.children[char]
        return node

This code builds a trie and searches for the node matching a prefix typed by the user.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: Looping through each character of the input word or prefix.
• How many times: Once per character in the word or prefix (length = n).

How Execution Grows With Input

As the prefix length grows, the search checks more characters one by one.

Input Size (n)	Approx. Operations
10	10 character checks
100	100 character checks
1000	1000 character checks

Pattern observation: The time grows linearly with the length of the prefix typed.

Final Time Complexity

Time Complexity: O(n)

This means the time to find the prefix node grows directly with the number of characters typed.

Common Mistake

[X] Wrong: "Searching a prefix in a trie takes time proportional to the total number of words stored."

[OK] Correct: The search only follows the path for the prefix characters, so it depends on prefix length, not total words.

Interview Connect

Understanding trie search time helps you explain how autocomplete suggestions appear quickly as you type.

Self-Check

"What if we added a function to collect all words under the prefix node? How would that affect the time complexity?"

Practice

1. What is the main purpose of using a Trie in an autocomplete system?

easy

A. To sort words alphabetically

B. To efficiently store and search prefixes of words

C. To count the total number of words

D. To encrypt the stored words

Solution

1. Step 1: Understand the role of Trie in prefix search

   A Trie is a tree-like data structure designed to store strings by their prefixes, allowing quick prefix-based searches.

2. Step 2: Connect Trie usage to autocomplete

   Autocomplete requires finding all words starting with a given prefix efficiently, which Trie supports by traversing nodes matching the prefix.

3. Final Answer:

   To efficiently store and search prefixes of words -> Option B

4. Quick Check:

   Trie = prefix search [OK]

Hint: Trie stores prefixes for fast autocomplete search [OK]

Common Mistakes:

• Thinking Trie sorts words alphabetically
• Confusing Trie with hash tables
• Assuming Trie encrypts data

2. Which of the following is the correct way to insert a word "cat" into a Trie node in Python?

easy

A. node['c'] = TrieNode()

B. node.insert('c')

C. node.add('c')

D. node.children['c'] = TrieNode()

Solution

1. Step 1: Understand Trie node structure

   Trie nodes typically have a dictionary called children to map characters to child nodes.

2. Step 2: Insert character as a key in children dictionary

   To insert 'c', assign a new TrieNode to node.children['c'].

3. Final Answer:

   node.children['c'] = TrieNode() -> Option D

4. Quick Check:

   Insert char in children dict = node.children['c'] = TrieNode() [OK]

Hint: Use children dictionary to add new character nodes [OK]

Common Mistakes:

• Trying to assign directly to node['c'] without children
• Using non-existent methods like add or insert
• Confusing list with dictionary for children

3. Given the following code snippet, what will be the output?

class TrieNode:
    def __init__(self):
        self.children = {}
        self.is_end = False

class Trie:
    def __init__(self):
        self.root = TrieNode()

    def insert(self, word):
        node = self.root
        for char in word:
            if char not in node.children:
                node.children[char] = TrieNode()
            node = node.children[char]
        node.is_end = True

    def search_prefix(self, prefix):
        node = self.root
        for char in prefix:
            if char not in node.children:
                return False
            node = node.children[char]
        return True

trie = Trie()
trie.insert('dog')
trie.insert('deer')
print(trie.search_prefix('de'))
print(trie.search_prefix('do'))
print(trie.search_prefix('da'))

medium

A. True\nFalse\nFalse

B. False\nTrue\nFalse

C. True\nTrue\nFalse

D. False\nFalse\nFalse

Solution

1. Step 1: Insert words 'dog' and 'deer' into Trie

   Both words add nodes for their characters. 'dog' adds d->o->g, 'deer' adds d->e->e->r.

2. Step 2: Check prefixes 'de', 'do', and 'da'

   'de' exists as prefix in 'deer', so returns True. 'do' exists as prefix in 'dog', so True. 'da' does not exist, so False.

3. Final Answer:

   True True False -> Option C

4. Quick Check:

   Prefix 'de' and 'do' found, 'da' not found = True, True, False [OK]

Hint: Check prefix path existence in Trie children [OK]

Common Mistakes:

• Confusing search_prefix with full word search
• Assuming 'da' prefix exists
• Ignoring is_end flag for prefix search

4. The following code is intended to insert words into a Trie, but it raises an error. What is the error?

class TrieNode:
    def __init__(self):
        self.children = []
        self.is_end = False

class Trie:
    def __init__(self):
        self.root = TrieNode()

    def insert(self, word):
        node = self.root
        for char in word:
            if char not in node.children:
                node.children[char] = TrieNode()
            node = node.children[char]

medium

A. TypeError: list indices must be integers or slices, not str

B. AttributeError: 'TrieNode' object has no attribute 'children'

C. SyntaxError: invalid syntax

D. No error, code runs fine

Solution

1. Step 1: Identify data structure used for children

   The code uses a list for children, but tries to access it with string keys.

2. Step 2: Understand list indexing rules

   Lists require integer indices, but code uses node.children[char] where char is a string, causing TypeError.

3. Final Answer:

   TypeError: list indices must be integers or slices, not str -> Option A

4. Quick Check:

   Using list with string keys causes TypeError [OK]

Hint: Use dictionary, not list, for children to index by characters [OK]

Common Mistakes:

• Using list instead of dict for children
• Ignoring error message details
• Assuming code runs without error

5. You want to implement an autocomplete system that returns all words starting with a given prefix using a Trie. Which approach correctly collects all matching words after reaching the prefix node?

hard

A. Perform a depth-first search (DFS) from the prefix node, collecting words where is_end is True

B. Return all children keys of the prefix node without further traversal

C. Only return the prefix itself without searching deeper

D. Use breadth-first search (BFS) but ignore is_end flags

Solution

1. Step 1: Reach the node matching the prefix

   Traverse the Trie to the node representing the last character of the prefix.

2. Step 2: Collect all words starting from prefix node using DFS

   Use DFS to explore all child nodes recursively, collecting words where is_end is True to get complete words.

3. Final Answer:

   Perform a depth-first search (DFS) from the prefix node, collecting words where is_end is True -> Option A

4. Quick Check:

   DFS from prefix node with is_end check = correct autocomplete [OK]

Hint: Use DFS from prefix node, collect words at is_end True [OK]

Common Mistakes:

• Returning only immediate children keys
• Ignoring is_end flags and returning incomplete words
• Using BFS without checking word ends