Recall & Review
beginner
What is the main idea behind using a heap to find the top K frequent elements?
Use a heap to keep track of the K elements with the highest frequency by pushing elements and popping the least frequent when size exceeds K.
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beginner
What type of heap is commonly used to solve the Top K Frequent Elements problem efficiently?
A min-heap is used to keep the smallest frequency element at the top, so when the heap size exceeds K, the least frequent element can be removed.
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beginner
Why do we use a frequency map before using a heap in this problem?
The frequency map counts how many times each element appears, which helps us know the frequency to compare when adding elements to the heap.
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intermediate
In JavaScript, which data structure can be used to implement a min-heap for this problem?
JavaScript does not have a built-in heap, so we can implement a min-heap using an array and helper functions to maintain heap properties.
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intermediate
What is the time complexity of finding the top K frequent elements using a heap?
The time complexity is O(N log K), where N is the number of unique elements, because each element is pushed and popped from the heap of size K.
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What data structure is first used to count element frequencies before using a heap?
✗ Incorrect
A hash map is used to count how many times each element appears.
Which heap type helps efficiently keep track of the top K frequent elements?
✗ Incorrect
A min-heap keeps the smallest frequency at the top, so we can remove less frequent elements when size exceeds K.
If the heap size exceeds K, what operation is performed?
✗ Incorrect
We remove the least frequent element to keep only the top K frequent elements.
What is the main benefit of using a heap over sorting all elements by frequency?
✗ Incorrect
Heap is faster because it only keeps track of K elements instead of sorting all N elements.
What is the output of the algorithm?
✗ Incorrect
The algorithm returns the top K frequent elements but order is not guaranteed.
Explain step-by-step how to find the top K frequent elements using a heap.
Think about counting first, then using a small heap to keep only K elements.
You got /5 concepts.
Why is a min-heap preferred over a max-heap for this problem?
Consider which element you want to remove when the heap grows too big.
You got /4 concepts.