Quick Sort Algorithm in DSA Javascript - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to choose the pivot element as the last element of the array.

DSA Javascript

function quickSort(arr) {
  if (arr.length <= 1) return arr;
  const pivot = arr[1];
  // rest of the code
}

Drag options to blanks, or click blank then click option'

A[0]

B[1]

C[arr.length - 1]

D[Math.floor(arr.length / 2)]

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing the first element as pivot instead of the last.

Using arr.length instead of arr.length - 1.

The pivot is chosen as the last element, which is at index arr.length - 1.

2fill in blank

medium

Complete the code to partition the array by comparing elements with the pivot.

DSA Javascript

function partition(arr, low, high) {
  const pivot = arr[high];
  let i = low - 1;
  for (let j = low; j < high; j++) {
    if (arr[j] [1] pivot) {
      i++;
      [arr[i], arr[j]] = [arr[j], arr[i]];
    }
  }
  [arr[i + 1], arr[high]] = [arr[high], arr[i + 1]];
  return i + 1;
}

Drag options to blanks, or click blank then click option'

A<=

B<

C>

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using greater than operator which reverses the partition logic.

Using >= or <= which includes equality and may cause incorrect swaps.

Elements less than the pivot are moved to the left side during partition.

3fill in blank

hard

Fix the error in the recursive call to quickSort to sort the left partition.

DSA Javascript

function quickSort(arr, low = 0, high = arr.length - 1) {
  if (low < high) {
    const pi = partition(arr, low, high);
    quickSort(arr, low, [1]);
    quickSort(arr, pi + 1, high);
  }
  return arr;
}

Drag options to blanks, or click blank then click option'

Api - 1

Bpi

Clow

Dhigh

Attempts:

3 left

💡 Hint

Common Mistakes

Using pi instead of pi - 1 causes infinite recursion.

Using high or low incorrectly changes the partition boundaries.

The left partition ends at pi - 1, so we sort from low to pi - 1.

4fill in blank

hard

Fill both blanks to complete the recursive calls for sorting left and right partitions.

DSA Javascript

function quickSort(arr, low = 0, high = arr.length - 1) {
  if (low < high) {
    const pi = partition(arr, low, high);
    quickSort(arr, [1], pi - 1);
    quickSort(arr, pi + 1, [2]);
  }
  return arr;
}

Drag options to blanks, or click blank then click option'

Alow

Bpi

Chigh

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using pi instead of low or high causes wrong partition ranges.

Using 0 instead of low or high causes incorrect sorting range.

Left partition is from low to pi - 1, right partition is from pi + 1 to high.

5fill in blank

hard

Fill all three blanks to complete the quickSort function with partitioning and recursive calls.

DSA Javascript

function quickSort(arr, [1] = 0, [2] = arr.length - 1) {
  if ([1] < [2]) {
    const pi = partition(arr, [1], [2]);
    quickSort(arr, [1], pi - 1);
    quickSort(arr, pi + 1, [2]);
  }
  return arr;
}

Drag options to blanks, or click blank then click option'

Alow

Bhigh

Cpivot

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Using pivot or index as parameter names causes confusion.

Mixing parameter names in recursive calls causes errors.

The function uses low and high as parameters and compares low < high.

Practice

1. What is the main idea behind the Quick Sort algorithm?

easy

A. Sort the array by repeatedly selecting the smallest element

B. Compare every element with every other element and swap if needed

C. Divide the array into smaller parts using a pivot and sort them recursively

D. Merge two sorted arrays into one sorted array

Solution

1. Step 1: Understand Quick Sort's approach

   Quick Sort picks a pivot element and divides the array into parts smaller and larger than the pivot.

2. Step 2: Recursive sorting of parts

   It then sorts these parts by calling itself recursively until the whole array is sorted.

3. Final Answer:

   Divide the array into smaller parts using a pivot and sort them recursively -> Option C

4. Quick Check:

   Quick Sort = Divide and conquer [OK]

Hint: Remember: pivot divides array, then sort parts recursively [OK]

Common Mistakes:

• Thinking Quick Sort compares all pairs directly
• Confusing Quick Sort with Selection Sort
• Believing Quick Sort merges arrays like Merge Sort

2. Which of the following is the correct syntax to swap two elements arr[i] and arr[j] in JavaScript during Quick Sort?

easy

A. arr[i], arr[j] = arr[j], arr[i];

B. temp = arr[i]; arr[i] = arr[j]; arr[j] = temp;

C. swap(arr[i], arr[j]);

D. arr[i] = arr[j]; arr[j] = arr[i];

Solution

1. Step 1: Identify correct swap method in JavaScript

   JavaScript does not support tuple unpacking like Python, so swapping requires a temporary variable.

2. Step 2: Check each option

   temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; uses a temporary variable to swap correctly. arr[i], arr[j] = arr[j], arr[i]; is Python syntax, swap(arr[i], arr[j]); is undefined, arr[i] = arr[j]; arr[j] = arr[i]; overwrites values incorrectly.

3. Final Answer:

   temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; -> Option B

4. Quick Check:

   Swap with temp variable = temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; [OK]

Hint: Use a temp variable to swap in JavaScript [OK]

Common Mistakes:

• Using Python-style tuple swap in JavaScript
• Overwriting one element before saving it
• Calling undefined swap function

3. What will be the output of the following Quick Sort partition step on array [4, 2, 7, 1] with pivot as the last element?

function partition(arr, low, high) {
  let pivot = arr[high];
  let i = low - 1;
  for (let j = low; j < high; j++) {
    if (arr[j] < pivot) {
      i++;
      let temp = arr[i]; arr[i] = arr[j]; arr[j] = temp;
    }
  }
  let temp = arr[i + 1]; arr[i + 1] = arr[high]; arr[high] = temp;
  return i + 1;
}

let arr = [4, 2, 7, 1];
let pi = partition(arr, 0, arr.length - 1);
console.log(arr);

medium

A. [1, 2, 7, 4]

B. [1, 2, 4, 7]

C. [4, 2, 7, 1]

D. [2, 1, 4, 7]

Solution

1. Step 1: Trace the partition loop

   Pivot = 1. Loop checks elements less than 1. No elements are less, so i stays at -1.

2. Step 2: Swap pivot with element at i+1

   Swap arr[0] and arr[3]: 4 and 1 swap places. Array becomes [1, 2, 7, 4].

3. Final Answer:

   [1, 2, 7, 4] -> Option A

4. Quick Check:

   Pivot 1 placed at start, others unchanged [OK]

Hint: Pivot swaps with first bigger element after loop [OK]

Common Mistakes:

• Assuming pivot stays at end
• Swapping wrong elements after loop
• Not updating i correctly

4. Identify the error in this Quick Sort partition function:

function partition(arr, low, high) {
  let pivot = arr[low];
  let i = low + 1;
  for (let j = low + 1; j <= high; j++) {
    if (arr[j] <= pivot) {
      let temp = arr[i]; arr[i] = arr[j]; arr[j] = temp;
      i++;
    }
  }
  let temp = arr[low]; arr[low] = arr[i]; arr[i] = temp;
  return i;
}

medium

A. Loop should start from low, not low + 1

B. Pivot should be arr[high], not arr[low]

C. No error, function is correct

D. Swapping pivot with arr[i] should be with arr[i - 1]

Solution

1. Step 1: Understand pivot placement

   Pivot is arr[low]. After loop, pivot must be placed at correct position.

2. Step 2: Check swap of pivot with arr[i]

   Variable i points to next greater element, so pivot should swap with arr[i - 1], not arr[i].

3. Final Answer:

   Swapping pivot with arr[i] should be with arr[i - 1] -> Option D

4. Quick Check:

   Pivot swap index off by one [OK]

Hint: Pivot swap index is i-1 after partition loop [OK]

Common Mistakes:

• Swapping pivot with wrong index
• Confusing pivot position in array
• Changing loop start incorrectly

5. Which of the following pivot selection strategies in Quick Sort will result in the most balanced partitions and thus better performance?

hard

A. Choosing the median of first, middle, and last elements as pivot

B. Choosing the first element as pivot

C. Choosing the middle element as pivot

D. Choosing the last element as pivot

Solution

1. Step 1: Understand pivot selection strategies

   Choosing first or last can lead to worst-case O(n^2) on sorted arrays. Middle element alone may not be representative.

2. Step 2: Best strategy for balance

   Median-of-three selects a pivot likely closer to the array's true median, promoting balanced partitions and average O(n log n) performance.

3. Final Answer:

   Choosing the median of first, middle, and last elements as pivot -> Option A

4. Quick Check:

   Median-of-three pivot = balanced partitions [OK]

Hint: Median-of-three pivot improves balance and speed [OK]

Common Mistakes:

• Always picking first or last element as pivot
• Ignoring pivot choice impact on performance
• Assuming middle element is always best pivot