Discover how to quickly find the closest shared ancestor without getting lost in the branches!
Why Lowest Common Ancestor in Binary Tree in DSA Javascript?
Imagine you have a family tree drawn on paper, and you want to find the closest common grandparent of two cousins. Without a clear method, you might have to trace each person's ancestors one by one, which can get confusing and slow.
Manually tracing ancestors means checking many paths repeatedly, which is slow and easy to make mistakes. If the tree is big, you might lose track or miss the closest common ancestor, leading to wrong answers.
The Lowest Common Ancestor (LCA) method helps find the closest shared ancestor of two nodes in a tree quickly and reliably by exploring the tree just once. It avoids repeated work and confusion by using a clear step-by-step approach.
function findAncestor(node, target) {
// Manually check each ancestor path
// Complex and repetitive
}function lowestCommonAncestor(root, node1, node2) {
if (!root) return null;
if (root === node1 || root === node2) return root;
const left = lowestCommonAncestor(root.left, node1, node2);
const right = lowestCommonAncestor(root.right, node1, node2);
if (left && right) return root;
return left || right;
}This concept enables fast and accurate discovery of shared ancestors in any tree, making complex family or organizational relationships easy to understand.
In a company's organizational chart, finding the lowest common manager of two employees helps decide who should approve joint projects or resolve conflicts.
Manual ancestor search is slow and error-prone.
LCA finds the closest shared ancestor efficiently.
It simplifies understanding relationships in trees.
Practice
Lowest Common Ancestor (LCA) of two nodes in a binary tree?Solution
Step 1: Understand ancestor concept
An ancestor of a node is any node on the path from the root to that node.Step 2: Define lowest common ancestor
The lowest common ancestor is the deepest node that is an ancestor of both given nodes.Final Answer:
The deepest node that is an ancestor of both nodes -> Option CQuick Check:
LCA = deepest common ancestor [OK]
- Confusing LCA with root node
- Choosing node with smallest value
- Selecting node based on traversal order
Solution
Step 1: Identify base case for recursion
When the current node is null, it means we've reached the end of a path without finding the target nodes.Step 2: Correct base case condition
Return null to indicate no ancestor found in this path.Final Answer:
if (root == null) return null; -> Option DQuick Check:
Base case returns null on null node [OK]
- Returning root when left or right child is null
- Checking root.value == null which is invalid
- Missing base case leading to infinite recursion
3
/ \
5 1
/ \ / \
6 2 0 8
function findLCA(root, p, q) {
if (!root || root === p || root === q) return root;
const left = findLCA(root.left, p, q);
const right = findLCA(root.right, p, q);
if (left && right) return root;
return left ? left : right;
}
const lca = findLCA(root, node5, node1);
console.log(lca.value);What will be printed?Solution
Step 1: Trace recursive calls for nodes 5 and 1
Both nodes 5 and 1 are children of root 3, so recursion finds them in left and right subtrees respectively.Step 2: Determine LCA based on recursion
Since left and right recursive calls return non-null (nodes 5 and 1), the current root 3 is the LCA.Final Answer:
3 -> Option BQuick Check:
LCA of 5 and 1 is 3 [OK]
- Returning one of the nodes instead of root
- Confusing node values with LCA
- Ignoring both left and right recursive results
function findLCA(root, p, q) {
if (!root) return null;
if (root === p || root === q) return root;
const left = findLCA(root.left, p, q);
const right = findLCA(root.right, p, q);
if (left) return left;
if (right) return right;
return null;
}Solution
Step 1: Analyze return conditions after recursion
The code returns left if left is non-null without checking right, missing the case when both are non-null.Step 2: Identify missing combined check
It should return root if both left and right are non-null, indicating LCA found at current root.Final Answer:
It returns left child even if right child is also non-null -> Option AQuick Check:
Must check both sides before returning [OK]
- Returning left without checking right
- Missing combined condition for LCA
- Ignoring null root check
Solution
Step 1: Understand tree structure
Nodes 2 and 4 are in left subtree of 3; nodes 5 and 6 are in right subtree of 3.Step 2: Find common ancestor of nodes 2 and 6
Since 2 is in left subtree and 6 is in right subtree, their lowest common ancestor is the root node 3.Final Answer:
3 -> Option AQuick Check:
LCA of nodes in opposite subtrees is root [OK]
- Choosing one of the nodes instead of ancestor
- Confusing sibling nodes as LCA
- Ignoring tree structure
Ready to prove it?
Pass the test and this pattern moves unknown
