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DSA Javascriptprogramming~3 mins

Why Lowest Common Ancestor in Binary Tree in DSA Javascript?

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The Big Idea

Discover how to quickly find the closest shared ancestor without getting lost in the branches!

The Scenario

Imagine you have a family tree drawn on paper, and you want to find the closest common grandparent of two cousins. Without a clear method, you might have to trace each person's ancestors one by one, which can get confusing and slow.

The Problem

Manually tracing ancestors means checking many paths repeatedly, which is slow and easy to make mistakes. If the tree is big, you might lose track or miss the closest common ancestor, leading to wrong answers.

The Solution

The Lowest Common Ancestor (LCA) method helps find the closest shared ancestor of two nodes in a tree quickly and reliably by exploring the tree just once. It avoids repeated work and confusion by using a clear step-by-step approach.

Before vs After
✗ Before
function findAncestor(node, target) {
  // Manually check each ancestor path
  // Complex and repetitive
}
✓ After
function lowestCommonAncestor(root, node1, node2) {
  if (!root) return null;
  if (root === node1 || root === node2) return root;
  const left = lowestCommonAncestor(root.left, node1, node2);
  const right = lowestCommonAncestor(root.right, node1, node2);
  if (left && right) return root;
  return left || right;
}
What It Enables

This concept enables fast and accurate discovery of shared ancestors in any tree, making complex family or organizational relationships easy to understand.

Real Life Example

In a company's organizational chart, finding the lowest common manager of two employees helps decide who should approve joint projects or resolve conflicts.

Key Takeaways

Manual ancestor search is slow and error-prone.

LCA finds the closest shared ancestor efficiently.

It simplifies understanding relationships in trees.

Practice

(1/5)
1. What is the Lowest Common Ancestor (LCA) of two nodes in a binary tree?
easy
A. The node that appears first in an inorder traversal
B. The root node of the binary tree
C. The deepest node that is an ancestor of both nodes
D. The node with the smallest value between the two nodes

Solution

  1. Step 1: Understand ancestor concept

    An ancestor of a node is any node on the path from the root to that node.
  2. Step 2: Define lowest common ancestor

    The lowest common ancestor is the deepest node that is an ancestor of both given nodes.
  3. Final Answer:

    The deepest node that is an ancestor of both nodes -> Option C
  4. Quick Check:

    LCA = deepest common ancestor [OK]
Hint: LCA is the deepest shared parent node [OK]
Common Mistakes:
  • Confusing LCA with root node
  • Choosing node with smallest value
  • Selecting node based on traversal order
2. Which of the following is the correct base case condition in a recursive function to find LCA in a binary tree?
easy
A. if (root.right == null) return root;
B. if (root.left == null) return root;
C. if (root.value == null) return root;
D. if (root == null) return null;

Solution

  1. Step 1: Identify base case for recursion

    When the current node is null, it means we've reached the end of a path without finding the target nodes.
  2. Step 2: Correct base case condition

    Return null to indicate no ancestor found in this path.
  3. Final Answer:

    if (root == null) return null; -> Option D
  4. Quick Check:

    Base case returns null on null node [OK]
Hint: Return null when node is null [OK]
Common Mistakes:
  • Returning root when left or right child is null
  • Checking root.value == null which is invalid
  • Missing base case leading to infinite recursion
3. Consider the following binary tree and code snippet to find LCA of nodes 5 and 1:
    3
   / \
  5   1
 / \ / \
6  2 0  8

function findLCA(root, p, q) {
  if (!root || root === p || root === q) return root;
  const left = findLCA(root.left, p, q);
  const right = findLCA(root.right, p, q);
  if (left && right) return root;
  return left ? left : right;
}

const lca = findLCA(root, node5, node1);
console.log(lca.value);
What will be printed?
medium
A. 5
B. 3
C. 1
D. null

Solution

  1. Step 1: Trace recursive calls for nodes 5 and 1

    Both nodes 5 and 1 are children of root 3, so recursion finds them in left and right subtrees respectively.
  2. Step 2: Determine LCA based on recursion

    Since left and right recursive calls return non-null (nodes 5 and 1), the current root 3 is the LCA.
  3. Final Answer:

    3 -> Option B
  4. Quick Check:

    LCA of 5 and 1 is 3 [OK]
Hint: If both sides return nodes, root is LCA [OK]
Common Mistakes:
  • Returning one of the nodes instead of root
  • Confusing node values with LCA
  • Ignoring both left and right recursive results
4. The following code attempts to find the LCA but has a bug. What is the error?
function findLCA(root, p, q) {
  if (!root) return null;
  if (root === p || root === q) return root;
  const left = findLCA(root.left, p, q);
  const right = findLCA(root.right, p, q);
  if (left) return left;
  if (right) return right;
  return null;
}
medium
A. It returns left child even if right child is also non-null
B. It does not check if root is null
C. It returns root instead of null when no nodes found
D. It does not handle the case when p or q is missing

Solution

  1. Step 1: Analyze return conditions after recursion

    The code returns left if left is non-null without checking right, missing the case when both are non-null.
  2. Step 2: Identify missing combined check

    It should return root if both left and right are non-null, indicating LCA found at current root.
  3. Final Answer:

    It returns left child even if right child is also non-null -> Option A
  4. Quick Check:

    Must check both sides before returning [OK]
Hint: Check both left and right before returning root [OK]
Common Mistakes:
  • Returning left without checking right
  • Missing combined condition for LCA
  • Ignoring null root check
5. Given a binary tree where nodes 2 and 4 are in the left subtree of node 3, and nodes 5 and 6 are in the right subtree of node 3, what is the LCA of nodes 2 and 6?
hard
A. 3
B. 2
C. 4
D. 5

Solution

  1. Step 1: Understand tree structure

    Nodes 2 and 4 are in left subtree of 3; nodes 5 and 6 are in right subtree of 3.
  2. Step 2: Find common ancestor of nodes 2 and 6

    Since 2 is in left subtree and 6 is in right subtree, their lowest common ancestor is the root node 3.
  3. Final Answer:

    3 -> Option A
  4. Quick Check:

    LCA of nodes in opposite subtrees is root [OK]
Hint: LCA of nodes in different subtrees is their root [OK]
Common Mistakes:
  • Choosing one of the nodes instead of ancestor
  • Confusing sibling nodes as LCA
  • Ignoring tree structure
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