Heap Concept Structure and Properties in DSA Javascript - Build from Scratch

Heap Concept Structure and Properties

📖 Scenario: Imagine you are organizing a priority queue for tasks in a to-do app. Each task has a priority number. You want to store these tasks so that the highest priority task is always easy to find.

🎯 Goal: You will create a simple heap structure using an array to understand how tasks are stored and how the heap properties keep the highest priority task at the top.

📋 What You'll Learn

Create an array called tasks with specific priority numbers

Create a variable called heapSize to store the number of tasks

Write a function called isHeapPropertyValid to check if the array follows max-heap property

Print the result of the heap property check

💡 Why This Matters

🌍 Real World

Heaps are used in task scheduling, priority queues, and efficient sorting algorithms like heap sort.

💼 Career

Understanding heap structure helps in roles involving algorithm optimization, system design, and software development.

1

Create the tasks array

Create an array called tasks with these exact priority numbers in order: 40, 30, 20, 15, 10, 12, 8.

DSA Javascript

// Create the tasks array with given priorities
// Your code here

Hint

Use square brackets [] to create an array and separate numbers with commas.

2

Set the heap size

Create a variable called heapSize and set it to the length of the tasks array.

DSA Javascript

const tasks = [40, 30, 20, 15, 10, 12, 8];
// Create heapSize variable to store number of tasks
// Your code here

Hint

Use array.length to get the number of items in an array.

3

Check the max-heap property

Write a function called isHeapPropertyValid that takes the tasks array and heapSize as parameters. It should return true if every parent node is greater than or equal to its children (max-heap property), otherwise false. Use a for loop with variable i from 0 to Math.floor(heapSize / 2) - 1 to check each parent node.

DSA Javascript

const tasks = [40, 30, 20, 15, 10, 12, 8];
const heapSize = tasks.length;

// Write isHeapPropertyValid function below
// Your code here

Hint

Remember, for each parent at index i, left child is at 2*i + 1 and right child is at 2*i + 2.

4

Print the heap property check result

Use console.log to print the result of calling isHeapPropertyValid(tasks, heapSize).

DSA Javascript

const tasks = [40, 30, 20, 15, 10, 12, 8];
const heapSize = tasks.length;

function isHeapPropertyValid(tasks, heapSize) {
    for (let i = 0; i <= Math.floor(heapSize / 2) - 1; i++) {
        let left = 2 * i + 1;
        let right = 2 * i + 2;
        if (left < heapSize && tasks[i] < tasks[left]) {
            return false;
        }
        if (right < heapSize && tasks[i] < tasks[right]) {
            return false;
        }
    }
    return true;
}

// Print the result below
// Your code here

Hint

Use console.log to print the boolean result.

Practice

1. What is a key property of a max heap data structure?

easy

A. Every parent node is greater than or equal to its child nodes

B. Every parent node is less than or equal to its child nodes

C. All leaf nodes are greater than the root node

D. The tree is always a complete binary tree but unordered

Solution

1. Step 1: Understand max heap property

   A max heap requires that each parent node is greater than or equal to its children.

2. Step 2: Compare options with max heap definition

   Every parent node is greater than or equal to its child nodes matches the max heap property exactly, others describe min heap or incorrect properties.

3. Final Answer:

   Every parent node is greater than or equal to its child nodes -> Option A

4. Quick Check:

   Max heap = parent ≥ children [OK]

Hint: Max heap means parent is always bigger or equal [OK]

Common Mistakes:

• Confusing max heap with min heap property
• Thinking leaf nodes must be bigger than root
• Ignoring the complete binary tree requirement

2. Which of the following is the correct way to represent a heap in JavaScript using an array?

easy

A. Parent at index i, left child at i + 1, right child at i + 2

B. Parent at index i, left child at 2*i + 1, right child at 2*i + 2

C. Parent at index i, left child at 2*i, right child at 2*i + 1

D. Parent at index i, left child at i - 1, right child at i - 2

Solution

1. Step 1: Recall array indexing for heap

   In zero-based arrays, left child index = 2*i + 1, right child index = 2*i + 2.

2. Step 2: Match options with formula

   Parent at index i, left child at 2*i + 1, right child at 2*i + 2 matches the correct formula for zero-based indexing heaps.

3. Final Answer:

   Parent at index i, left child at 2*i + 1, right child at 2*i + 2 -> Option B

4. Quick Check:

   Heap array indexing = 2*i+1, 2*i+2 [OK]

Hint: Remember zero-based indexing: left=2i+1, right=2i+2 [OK]

Common Mistakes:

• Using one-based indexing formulas incorrectly
• Swapping left and right child indices
• Using i+1 or i+2 which is wrong for heap

3. Consider the following JavaScript code that builds a max heap from an array:

const arr = [3, 9, 2, 1, 4, 5];
function maxHeapify(arr, i, n) {
  let largest = i;
  let left = 2 * i + 1;
  let right = 2 * i + 2;
  if (left < n && arr[left] > arr[largest]) largest = left;
  if (right < n && arr[right] > arr[largest]) largest = right;
  if (largest !== i) {
    [arr[i], arr[largest]] = [arr[largest], arr[i]];
    maxHeapify(arr, largest, n);
  }
}

function buildMaxHeap(arr) {
  let n = arr.length;
  for (let i = Math.floor(n / 2) - 1; i >= 0; i--) {
    maxHeapify(arr, i, n);
  }
}

buildMaxHeap(arr);
console.log(arr);

What is the output printed?

medium

A. [3, 9, 2, 1, 4, 5]

B. [9, 3, 5, 1, 4, 2]

C. [5, 4, 3, 1, 9, 2]

D. [9, 4, 5, 1, 3, 2]

Solution

1. Step 1: Understand buildMaxHeap process

   Start heapifying from last non-leaf node at index 2 (value 2), then index 1 (value 9), then index 0 (value 3).

2. Step 2: Trace heapify calls

   Initial: [3,9,2,1,4,5]
   Heapify i=2: left=5 (5>2), largest=5, swap 2-5: [3,9,5,1,4,2]. Heapify 5: no children.
   Heapify i=1: left=3(1<9), right=4(4<9), no swap.
   Heapify i=0: left=1(9>3), largest=1; right=2(5<9), swap 0-1: [9,3,5,1,4,2]. Heapify 1 (val=3): left=3(1<3), right=4(4>3), largest=4, swap 1-4: [9,4,5,1,3,2]. Heapify 4: no children.

3. Final Answer:

   [9, 4, 5, 1, 3, 2] -> Option D

4. Quick Check:

   Max heap array after build = [9,4,5,1,3,2] [OK]

Hint: Heapify from bottom non-leaf nodes up [OK]

Common Mistakes:

• Not heapifying recursively after swap
• Confusing indices for children
• Assuming original array order remains

4. The following JavaScript function is intended to insert a new value into a max heap represented as an array. Identify the bug:

function insertHeap(arr, value) {
  arr.push(value);
  let i = arr.length - 1;
  while (i > 0) {
    let parent = Math.floor(i / 2);
    if (arr[parent] < arr[i]) {
      [arr[parent], arr[i]] = [arr[i], arr[parent]];
      i = parent;
    } else {
      break;
    }
  }
}

medium

A. Parent index calculation should be Math.floor((i - 1) / 2)

B. The loop should run while i >= 0

C. The swap should happen only if arr[parent] > arr[i]

D. The function should remove the last element before inserting

Solution

1. Step 1: Check parent index formula in zero-based heap

   In zero-based arrays, parent index = Math.floor((i - 1) / 2), not Math.floor(i / 2).

2. Step 2: Understand impact of wrong parent index

   Using Math.floor(i / 2) causes incorrect parent calculation, breaking heap property restoration.

3. Final Answer:

   Parent index calculation should be Math.floor((i - 1) / 2) -> Option A

4. Quick Check:

   Parent index = (i-1)//2 in zero-based heap [OK]

Hint: Parent index in zero-based heap = (i-1)//2 [OK]

Common Mistakes:

• Using i/2 instead of (i-1)/2 for parent
• Loop condition allowing i=0 to cause errors
• Swapping when parent is larger, not smaller

5. You have a min heap represented as an array: [2, 5, 8, 10, 15, 20]. You want to insert the value 1 and maintain the min heap property. Which sequence of array states correctly shows the heap after each step of insertion and heapify up?

hard

A. [2, 5, 8, 10, 15, 20, 1] -> [2, 5, 8, 10, 15, 20, 1] -> [1, 5, 8, 10, 15, 20, 2]

B. [2, 5, 8, 10, 15, 20, 1] -> [1, 5, 8, 10, 15, 20, 2]

C. [2, 5, 8, 10, 15, 20, 1] -> [2, 5, 1, 10, 15, 20, 8] -> [1, 5, 2, 10, 15, 20, 8]

D. [2, 5, 8, 10, 15, 20, 1] -> [1, 2, 5, 10, 15, 20, 8]

Solution

1. Step 1: Insert value at end

   Insert 1 at the end: [2, 5, 8, 10, 15, 20, 1]

2. Step 2: Heapify up swaps

   Compare 1 with parent at index 2 (value 8), swap: [2, 5, 1, 10, 15, 20, 8]
   Compare 1 with new parent at index 0 (value 2), swap: [1, 5, 2, 10, 15, 20, 8]

3. Step 3: Final heap state

   Heap property restored with 1 at root.

4. Final Answer:

   [2, 5, 8, 10, 15, 20, 1] -> [2, 5, 1, 10, 15, 20, 8] -> [1, 5, 2, 10, 15, 20, 8] -> Option C

5. Quick Check:

   Heapify up swaps child with parent until order restored [OK]

Hint: Heapify up swaps child with parent until order restored [OK]

Common Mistakes:

• Not swapping with correct parent index
• Stopping heapify too early
• Incorrect final heap array after swaps