Push Operation on Stack in DSA Javascript - Build from Scratch

Push Operation on Stack

📖 Scenario: Imagine you have a stack of books. You want to add a new book on top of the stack. This is called a push operation in computer science.

🎯 Goal: You will create a stack using a list, set up a new book to add, push the book onto the stack, and then print the stack to see the new order.

📋 What You'll Learn

Create a stack as an array with exact books: 'Book1', 'Book2', 'Book3'

Create a variable called newBook with the value 'Book4'

Use the push method to add newBook to the stack

Print the stack array to show the books after pushing

💡 Why This Matters

🌍 Real World

Stacks are used in many places like undo buttons in apps, browser history, and managing tasks in order.

💼 Career

Understanding stack operations like push is important for software development and technical interviews.

1

Create the initial stack

Create an array called stack with these exact books in order: 'Book1', 'Book2', 'Book3'

DSA Javascript

// Your code here

Hint

Use square brackets [] to create an array and separate items with commas.

2

Add a new book to push

Create a variable called newBook and set it to the string 'Book4'

DSA Javascript

const stack = ['Book1', 'Book2', 'Book3'];
// Your code here

Hint

Use const newBook = 'Book4'; to create the variable.

3

Push the new book onto the stack

Use the push method on stack to add newBook to the top of the stack

DSA Javascript

const stack = ['Book1', 'Book2', 'Book3'];
const newBook = 'Book4';
// Your code here

Hint

Use stack.push(newBook); to add the new book.

4

Print the stack after push

Print the stack array using console.log(stack) to show the books after pushing

DSA Javascript

const stack = ['Book1', 'Book2', 'Book3'];
const newBook = 'Book4';
stack.push(newBook);
// Your code here

Hint

Use console.log(stack); to print the stack.

Practice

1. What does the push operation do in a stack data structure?

easy

A. Checks if the stack is empty

B. Removes the top element from the stack

C. Returns the bottom element of the stack

D. Adds an element to the top of the stack

Solution

1. Step 1: Understand stack operations

   A stack follows Last In First Out (LIFO). The push operation adds an element on top.

2. Step 2: Identify the role of push

   It inserts a new element at the top, increasing stack size by one.

3. Final Answer:

   Adds an element to the top of the stack -> Option D

4. Quick Check:

   Push = Add top element [OK]

Hint: Push means add on top of stack [OK]

Common Mistakes:

• Confusing push with pop operation
• Thinking push removes elements
• Mixing stack with queue operations

2. Which of the following is the correct syntax to push an element 5 into a stack array named stack in JavaScript?

easy

A. stack.add(5);

B. stack.push(5);

C. push.stack(5);

D. stack.insert(5);

Solution

1. Step 1: Recall JavaScript array push syntax

   JavaScript arrays use push() method to add elements at the end.

2. Step 2: Match correct method call

   stack.push(5); correctly calls push on the array named stack.

3. Final Answer:

   stack.push(5); -> Option B

4. Quick Check:

   Array push method = stack.push(value) [OK]

Hint: Use arrayName.push(value) to add element [OK]

Common Mistakes:

• Using non-existent methods like add or insert
• Reversing method and object like push.stack()
• Forgetting parentheses after push

3. What will be the output after executing the following code?

const stack = [];
stack.push(10);
stack.push(20);
stack.push(30);
console.log(stack);

medium

A. [10, 20]

B. [30, 20, 10]

C. [10, 20, 30]

D. Error: push is not a function

Solution

1. Step 1: Trace push operations on empty stack

   Initially stack is empty []. After push(10), stack = [10]. After push(20), stack = [10, 20]. After push(30), stack = [10, 20, 30].

2. Step 2: Understand console.log output

   Logging stack prints the array as is: [10, 20, 30].

3. Final Answer:

   [10, 20, 30] -> Option C

4. Quick Check:

   Push adds at end, so stack = [10,20,30] [OK]

Hint: Push adds at end, array grows left to right [OK]

Common Mistakes:

• Assuming push adds at start (top as front)
• Confusing stack order with queue
• Expecting reversed array output

4. Identify the error in the following code snippet that tries to push an element into a stack:

let stack = 5;
stack.push(10);

medium

A. stack is not an array, so push method is undefined

B. push method requires two arguments

C. stack.push should be stack.add

D. No error, code runs fine

Solution

1. Step 1: Check variable type of stack

   stack is assigned number 5, not an array. Numbers do not have push method.

2. Step 2: Understand push method applicability

   push is an array method. Calling push on a number causes error: push is not a function.

3. Final Answer:

   stack is not an array, so push method is undefined -> Option A

4. Quick Check:

   push only works on arrays [OK]

Hint: Only arrays have push method [OK]

Common Mistakes:

• Assuming push works on numbers
• Thinking push needs multiple arguments
• Confusing push with add method

5. Given a stack implemented as an array, how would you push multiple elements [1, 2, 3] onto it so that 3 is on top after all pushes?
Choose the correct code snippet.

hard

A. stack.push(1); stack.push(2); stack.push(3);

B. stack.push(3); stack.push(2); stack.push(1);

C. stack.push([1, 2, 3]);

D. stack = [1, 2, 3];

Solution

1. Step 1: Understand push order for stack

   Push adds elements on top. To have 3 on top, push 1 first, then 2, then 3.

2. Step 2: Analyze options

   Sequential pushes of 1 then 2 then 3 add elements individually with 3 on top. Pushing [1,2,3] adds a single array element with [1,2,3] on top. Reverse pushes put 1 on top. Assignment replaces the stack entirely.

3. Final Answer:

   stack.push(1); stack.push(2); stack.push(3); -> Option A

4. Quick Check:

   Push in order to have last element on top [OK]

Hint: Push elements in order, last pushed is top [OK]

Common Mistakes:

• Pushing array [1,2,3] as single element
• Pushing in reverse order
• Replacing stack instead of pushing