Push Operation on Stack in DSA Javascript - Time & Space Complexity
We want to understand how the time needed to add an item to a stack changes as the stack grows.
How does the push operation behave when the stack size increases?
Analyze the time complexity of the following code snippet.
class Stack {
constructor() {
this.items = [];
}
push(element) {
this.items.push(element);
}
}
This code adds an element to the top of the stack using an array's push method.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Adding one element to the end of the array.
- How many times: Exactly once per push call.
Each push adds one element without scanning or moving other elements.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 10 pushes = 10 operations |
| 100 | 100 pushes = 100 operations |
| 1000 | 1000 pushes = 1000 operations |
Pattern observation: Operations grow directly with the number of pushes, one per push.
Time Complexity: O(1)
This means adding an element takes the same short time no matter how big the stack is.
[X] Wrong: "Push takes longer as the stack grows because it has to move all elements."
[OK] Correct: The push operation adds only to the end without moving existing elements, so time stays constant.
Knowing push is quick and constant time helps you explain stack efficiency clearly in interviews.
"What if the stack was implemented using a linked list instead of an array? How would the time complexity of push change?"
Practice
push operation do in a stack data structure?Solution
Step 1: Understand stack operations
A stack follows Last In First Out (LIFO). Thepushoperation adds an element on top.Step 2: Identify the role of
It inserts a new element at the top, increasing stack size by one.pushFinal Answer:
Adds an element to the top of the stack -> Option DQuick Check:
Push = Add top element [OK]
- Confusing push with pop operation
- Thinking push removes elements
- Mixing stack with queue operations
5 into a stack array named stack in JavaScript?Solution
Step 1: Recall JavaScript array push syntax
JavaScript arrays usepush()method to add elements at the end.Step 2: Match correct method call
stack.push(5);correctly calls push on the array named stack.Final Answer:
stack.push(5); -> Option BQuick Check:
Array push method = stack.push(value) [OK]
- Using non-existent methods like add or insert
- Reversing method and object like push.stack()
- Forgetting parentheses after push
const stack = []; stack.push(10); stack.push(20); stack.push(30); console.log(stack);
Solution
Step 1: Trace push operations on empty stack
Initially stack is empty []. After push(10), stack = [10]. After push(20), stack = [10, 20]. After push(30), stack = [10, 20, 30].Step 2: Understand console.log output
Logging stack prints the array as is: [10, 20, 30].Final Answer:
[10, 20, 30] -> Option CQuick Check:
Push adds at end, so stack = [10,20,30] [OK]
- Assuming push adds at start (top as front)
- Confusing stack order with queue
- Expecting reversed array output
let stack = 5; stack.push(10);
Solution
Step 1: Check variable type of stack
stack is assigned number 5, not an array. Numbers do not have push method.Step 2: Understand push method applicability
push is an array method. Calling push on a number causes error: push is not a function.Final Answer:
stack is not an array, so push method is undefined -> Option AQuick Check:
push only works on arrays [OK]
- Assuming push works on numbers
- Thinking push needs multiple arguments
- Confusing push with add method
[1, 2, 3] onto it so that 3 is on top after all pushes?Choose the correct code snippet.
Solution
Step 1: Understand push order for stack
Push adds elements on top. To have 3 on top, push 1 first, then 2, then 3.Step 2: Analyze options
Sequential pushes of 1 then 2 then 3 add elements individually with 3 on top. Pushing [1,2,3] adds a single array element with [1,2,3] on top. Reverse pushes put 1 on top. Assignment replaces the stack entirely.Final Answer:
stack.push(1); stack.push(2); stack.push(3); -> Option AQuick Check:
Push in order to have last element on top [OK]
- Pushing array [1,2,3] as single element
- Pushing in reverse order
- Replacing stack instead of pushing
Ready to prove it?
Pass the test and this pattern moves unknown
